Algebra Examples

$\sqrt[4]{n + 1} = 2$

Step 1

To remove the radical on the left side of the equation, raise both sides of the equation to the power of $4$ .

${\sqrt[4]{n + 1}}^{4} = 2^{4}$

Step 2

Simplify each side of the equation.

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Step 2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[4]{n + 1}$ as ${(n + 1)}^{\frac{1}{4}}$ .

${({(n + 1)}^{\frac{1}{4}})}^{4} = 2^{4}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify ${({(n + 1)}^{\frac{1}{4}})}^{4}$ .

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Step 2.2.1.1

Multiply the exponents in ${({(n + 1)}^{\frac{1}{4}})}^{4}$ .

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Step 2.2.1.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(n + 1)}^{\frac{1}{4} \cdot 4} = 2^{4}$

Step 2.2.1.1.2

Cancel the common factor of $4$ .

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Step 2.2.1.1.2.1

Cancel the common factor.

${(n + 1)}^{\frac{1}{4} \cdot 4} = 2^{4}$

Step 2.2.1.1.2.2

Rewrite the expression.

${(n + 1)}^{1} = 2^{4}$

Step 2.2.1.2

Simplify.

$n + 1 = 2^{4}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Raise $2$ to the power of $4$ .

$n + 1 = 16$

Step 3

Move all terms not containing $n$ to the right side of the equation.

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Step 3.1

Subtract $1$ from both sides of the equation.

$n = 16 - 1$

Step 3.2

Subtract $1$ from $16$ .

$n = 15$