Algebra Examples

$0 = x^{2} {(x + 3)}^{4} (x - 1)$

Step 1

Rewrite the equation as $x^{2} {(x + 3)}^{4} (x - 1) = 0$ .

$x^{2} {(x + 3)}^{4} (x - 1) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{2} = 0$

${(x + 3)}^{4} = 0$

$x - 1 = 0$

Step 3

Set $x^{2}$ equal to $0$ and solve for $x$ .

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Step 3.1

Set $x^{2}$ equal to $0$ .

$x^{2} = 0$

Step 3.2

Solve $x^{2} = 0$ for $x$ .

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Step 3.2.1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Step 3.2.2

Simplify $\pm \sqrt{0}$ .

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Step 3.2.2.1

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Step 3.2.2.2

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Step 3.2.2.3

Plus or minus $0$ is $0$ .

$x = 0$

Step 4

Set ${(x + 3)}^{4}$ equal to $0$ and solve for $x$ .

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Step 4.1

Set ${(x + 3)}^{4}$ equal to $0$ .

${(x + 3)}^{4} = 0$

Step 4.2

Solve ${(x + 3)}^{4} = 0$ for $x$ .

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Step 4.2.1

Set the $x + 3$ equal to $0$ .

$x + 3 = 0$

Step 4.2.2

Subtract $3$ from both sides of the equation.

$x = - 3$

Step 5

Set $x - 1$ equal to $0$ and solve for $x$ .

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Step 5.1

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Step 5.2

Add $1$ to both sides of the equation.

$x = 1$

Step 6

The final solution is all the values that make $x^{2} {(x + 3)}^{4} (x - 1) = 0$ true.

$x = 0, - 3, 1$

Step 7