Algebra Examples

$\tan (- 225 °) + \tan (405 °)$

Step 1

Simplify each term.

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Step 1.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because tangent is negative in the second quadrant.

$- \tan (45) + \tan (405 °)$

Step 1.2

The exact value of $\tan (45)$ is $1$ .

$- 1 \cdot 1 + \tan (405 °)$

Step 1.3

Multiply $- 1$ by $1$ .

$- 1 + \tan (405 °)$

Step 1.4

Remove full rotations of $360$ ° until the angle is between $0$ ° and $360$ °.

$- 1 + \tan (45)$

Step 1.5

The exact value of $\tan (45)$ is $1$ .

$- 1 + 1$

Step 2

Add $- 1$ and $1$ .

$0$