Algebra Examples

$5 (- b - 2) = - 4 b - 9 - 1$

Step 1

Simplify $5 (- b - 2)$ .

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Step 1.1

Rewrite.

$0 + 0 + 5 (- b - 2) = - 4 b - 9 - 1$

Step 1.2

Simplify by adding zeros.

$5 (- b - 2) = - 4 b - 9 - 1$

Step 1.3

Apply the distributive property.

$5 (- b) + 5 \cdot - 2 = - 4 b - 9 - 1$

Step 1.4

Multiply.

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Step 1.4.1

Multiply $- 1$ by $5$ .

$- 5 b + 5 \cdot - 2 = - 4 b - 9 - 1$

Step 1.4.2

Multiply $5$ by $- 2$ .

$- 5 b - 10 = - 4 b - 9 - 1$

Step 2

Subtract $1$ from $- 9$ .

$- 5 b - 10 = - 4 b - 10$

Step 3

Move all terms containing $b$ to the left side of the equation.

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Step 3.1

Add $4 b$ to both sides of the equation.

$- 5 b - 10 + 4 b = - 10$

Step 3.2

Add $- 5 b$ and $4 b$ .

$- b - 10 = - 10$

Step 4

Move all terms not containing $b$ to the right side of the equation.

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Step 4.1

Add $10$ to both sides of the equation.

$- b = - 10 + 10$

Step 4.2

Add $- 10$ and $10$ .

$- b = 0$

Step 5

Divide each term in $- b = 0$ by $- 1$ and simplify.

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Step 5.1

Divide each term in $- b = 0$ by $- 1$ .

$\frac{- b}{- 1} = \frac{0}{- 1}$

Step 5.2

Simplify the left side.

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Step 5.2.1

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{0}{- 1}$

Step 5.2.2

Divide $b$ by $1$ .

$b = \frac{0}{- 1}$

Step 5.3

Simplify the right side.

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Step 5.3.1

Divide $0$ by $- 1$ .

$b = 0$