Algebra Examples

$\frac{6 + \sqrt{3}}{\sqrt{3} - 1}$

Step 1

Multiply $\frac{6 + \sqrt{3}}{\sqrt{3} - 1}$ by $\frac{\sqrt{3} + 1}{\sqrt{3} + 1}$ .

$\frac{6 + \sqrt{3}}{\sqrt{3} - 1} \cdot \frac{\sqrt{3} + 1}{\sqrt{3} + 1}$

Step 2

Combine fractions.

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Step 2.1

Multiply $\frac{6 + \sqrt{3}}{\sqrt{3} - 1}$ by $\frac{\sqrt{3} + 1}{\sqrt{3} + 1}$ .

$\frac{(6 + \sqrt{3}) (\sqrt{3} + 1)}{(\sqrt{3} - 1) (\sqrt{3} + 1)}$

Step 2.2

Expand the denominator using the FOIL method.

$\frac{(6 + \sqrt{3}) (\sqrt{3} + 1)}{{\sqrt{3}}^{2} + \sqrt{3} - \sqrt{3} - 1}$

Step 2.3

Simplify.

$\frac{(6 + \sqrt{3}) (\sqrt{3} + 1)}{2}$

Step 3

Expand $(6 + \sqrt{3}) (\sqrt{3} + 1)$ using the FOIL Method.

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Step 3.1

Apply the distributive property.

$\frac{6 (\sqrt{3} + 1) + \sqrt{3} (\sqrt{3} + 1)}{2}$

Step 3.2

Apply the distributive property.

$\frac{6 \sqrt{3} + 6 \cdot 1 + \sqrt{3} (\sqrt{3} + 1)}{2}$

Step 3.3

Apply the distributive property.

$\frac{6 \sqrt{3} + 6 \cdot 1 + \sqrt{3} \sqrt{3} + \sqrt{3} \cdot 1}{2}$

Step 4

Simplify and combine like terms.

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Step 4.1

Simplify each term.

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Step 4.1.1

Multiply $6$ by $1$ .

$\frac{6 \sqrt{3} + 6 + \sqrt{3} \sqrt{3} + \sqrt{3} \cdot 1}{2}$

Step 4.1.2

Combine using the product rule for radicals.

$\frac{6 \sqrt{3} + 6 + \sqrt{3 \cdot 3} + \sqrt{3} \cdot 1}{2}$

Step 4.1.3

Multiply $3$ by $3$ .

$\frac{6 \sqrt{3} + 6 + \sqrt{9} + \sqrt{3} \cdot 1}{2}$

Step 4.1.4

Rewrite $9$ as $3^{2}$ .

$\frac{6 \sqrt{3} + 6 + \sqrt{3^{2}} + \sqrt{3} \cdot 1}{2}$

Step 4.1.5

Pull terms out from under the radical, assuming positive real numbers.

$\frac{6 \sqrt{3} + 6 + 3 + \sqrt{3} \cdot 1}{2}$

Step 4.1.6

Multiply $\sqrt{3}$ by $1$ .

$\frac{6 \sqrt{3} + 6 + 3 + \sqrt{3}}{2}$

Step 4.2

Add $6 \sqrt{3}$ and $\sqrt{3}$ .

$\frac{6 + 3 + 7 \sqrt{3}}{2}$

Step 4.3

Add $6$ and $3$ .

$\frac{9 + 7 \sqrt{3}}{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$\frac{9 + 7 \sqrt{3}}{2}$

Decimal Form:

$10.56217782 \dots$