Algebra Examples

$y^{2} - 8 x - 16 = 0$

Step 1

Since $x = r \cos (θ)$ , replace $x$ with $r \cos (θ)$ .

$y^{2} - 8 (r \cos (θ)) - 16 = 0$

Step 2

Since $y = r \sin (θ)$ , replace $y$ with $r \sin (θ)$ .

${(r \sin (θ))}^{2} - 8 (r \cos (θ)) - 16 = 0$

Step 3

Simplify the left side.

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Step 3.1

Apply the product rule to $r \sin (θ)$ .

$r^{2} \sin^{2} (θ) - 8 r \cos (θ) - 16 = 0$