Algebra Examples

$y = 2 x$ $- 6 x + 3 y = 16$

Step 1

Replace all occurrences of $y$ with $2 x$ in each equation.

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Step 1.1

Replace all occurrences of $y$ in $- 6 x + 3 y = 16$ with $2 x$ .

$- 6 x + 3 (2 x) = 16$

$y = 2 x$

Step 1.2

Simplify the left side.

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Step 1.2.1

Simplify $- 6 x + 3 (2 x)$ .

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Step 1.2.1.1

Multiply $2$ by $3$ .

$- 6 x + 6 x = 16$

$y = 2 x$

Step 1.2.1.2

Add $- 6 x$ and $6 x$ .

$0 = 16$

$y = 2 x$

$0 = 16$

$y = 2 x$

$0 = 16$

$y = 2 x$

$0 = 16$

$y = 2 x$

Step 2

Since $0 = 16$ is not true, there is no solution.

No solution

Step 3

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$