Algebra Examples

Solve by Substitution y=3x+14 y=x
y=3x+14y=3x+14 y=xy=x
Step 1
Eliminate the equal sides of each equation and combine.
3x+14=x3x+14=x
Step 2
Solve 3x+14=x3x+14=x for xx.
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Step 2.1
Move all terms containing xx to the left side of the equation.
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Step 2.1.1
Subtract xx from both sides of the equation.
3x+14-x=03x+14x=0
Step 2.1.2
Subtract xx from 3x3x.
2x+14=02x+14=0
2x+14=02x+14=0
Step 2.2
Subtract 1414 from both sides of the equation.
2x=-142x=14
Step 2.3
Divide each term in 2x=-142x=14 by 22 and simplify.
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Step 2.3.1
Divide each term in 2x=-142x=14 by 22.
2x2=-1422x2=142
Step 2.3.2
Simplify the left side.
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Step 2.3.2.1
Cancel the common factor of 22.
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Step 2.3.2.1.1
Cancel the common factor.
2x2=-142
Step 2.3.2.1.2
Divide x by 1.
x=-142
x=-142
x=-142
Step 2.3.3
Simplify the right side.
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Step 2.3.3.1
Divide -14 by 2.
x=-7
x=-7
x=-7
x=-7
Step 3
Evaluate y when x=-7.
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Step 3.1
Substitute -7 for x.
y=-7
Step 3.2
Remove parentheses.
y=-7
y=-7
Step 4
The solution to the system is the complete set of ordered pairs that are valid solutions.
(-7,-7)
Step 5
The result can be shown in multiple forms.
Point Form:
(-7,-7)
Equation Form:
x=-7,y=-7
Step 6
image of graph
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