Algebra Examples

6 x - 17 = k

$6 x - 17 = k$ for

x

$x$

Step 1

Add

17

$17$ to both sides of the equation.

6 x = k + 17

$6 x = k + 17$

Step 2

Divide each term in

6 x = k + 17

$6 x = k + 17$ by

6

$6$ and simplify.

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Step 2.1

Divide each term in

6 x = k + 17

$6 x = k + 17$ by

6

$6$ .

\frac{6 x}{6} = \frac{k}{6} + \frac{17}{6}

$\frac{6 x}{6} = \frac{k}{6} + \frac{17}{6}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of

6

$6$ .

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Step 2.2.1.1

Cancel the common factor.

\frac{6 x}{6} = \frac{k}{6} + \frac{17}{6}

$\frac{6 x}{6} = \frac{k}{6} + \frac{17}{6}$

Step 2.2.1.2

Divide

x

$x$ by

1

$1$ .

x = \frac{k}{6} + \frac{17}{6}

$x = \frac{k}{6} + \frac{17}{6}$

x = \frac{k}{6} + \frac{17}{6}

$x = \frac{k}{6} + \frac{17}{6}$

x = \frac{k}{6} + \frac{17}{6}

$x = \frac{k}{6} + \frac{17}{6}$

x = \frac{k}{6} + \frac{17}{6}

$x = \frac{k}{6} + \frac{17}{6}$

6 x - 17 = k

$6 x - 17 = k$ for

x

$x$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$