Aljabar Contoh

$2 x^{\frac{1}{5}} - 2$

Langkah 1

Saling tukar variabel.

$x = 2 y^{\frac{1}{5}} - 2$

Langkah 2

Selesaikan $y$ .

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Langkah 2.1

Tulis kembali persamaan tersebut sebagai $2 y^{\frac{1}{5}} - 2 = x$ .

$2 y^{\frac{1}{5}} - 2 = x$

Langkah 2.2

Pindahkan semua suku yang tidak mengandung $y$ ke sisi kanan dari persamaan.

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Langkah 2.2.1

Tambahkan $2$ ke kedua sisi persamaan.

$2 y^{\frac{1}{5}} - x = 2$

Langkah 2.2.2

Tambahkan $x$ ke kedua sisi persamaan.

$2 y^{\frac{1}{5}} = 2 + x$

Langkah 2.3

Pangkatkan setiap sisi persamaan dengan pangkat $5$ untuk menghilangkan eksponen pecahan di sisi kiri.

${(2 y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Langkah 2.4

Sederhanakan bentuk eksponen.

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Langkah 2.4.1

Sederhanakan sisi kirinya.

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Langkah 2.4.1.1

Sederhanakan ${(2 y^{\frac{1}{5}})}^{5}$ .

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Langkah 2.4.1.1.1

Terapkan kaidah hasil kali ke $2 y^{\frac{1}{5}}$ .

$2^{5} {(y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Langkah 2.4.1.1.2

Naikkan $2$ menjadi pangkat $5$ .

$32 {(y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Langkah 2.4.1.1.3

Kalikan eksponen dalam ${(y^{\frac{1}{5}})}^{5}$ .

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Langkah 2.4.1.1.3.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$32 y^{\frac{1}{5} \cdot 5} = {(2 + x)}^{5}$

Langkah 2.4.1.1.3.2

Batalkan faktor persekutuan dari $5$ .

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Langkah 2.4.1.1.3.2.1

Batalkan faktor persekutuan.

$32 y^{\frac{1}{5} \cdot 5} = {(2 + x)}^{5}$

Langkah 2.4.1.1.3.2.2

Tulis kembali pernyataannya.

$32 y^{1} = {(2 + x)}^{5}$

Langkah 2.4.1.1.4

Sederhanakan.

$32 y = {(2 + x)}^{5}$

Langkah 2.4.2

Sederhanakan sisi kanannya.

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Langkah 2.4.2.1

Sederhanakan ${(2 + x)}^{5}$ .

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Langkah 2.4.2.1.1

Gunakan Teorema Binomial.

$32 y = 2^{5} + 5 \cdot 2^{4} x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2

Sederhanakan setiap suku.

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Langkah 2.4.2.1.2.1

Naikkan $2$ menjadi pangkat $5$ .

$32 y = 32 + 5 \cdot 2^{4} x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.2

Naikkan $2$ menjadi pangkat $4$ .

$32 y = 32 + 5 \cdot 16 x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.3

Kalikan $5$ dengan $16$ .

$32 y = 32 + 80 x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.4

Naikkan $2$ menjadi pangkat $3$ .

$32 y = 32 + 80 x + 10 \cdot 8 x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.5

Kalikan $10$ dengan $8$ .

$32 y = 32 + 80 x + 80 x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.6

Naikkan $2$ menjadi pangkat $2$ .

$32 y = 32 + 80 x + 80 x^{2} + 10 \cdot 4 x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.7

Kalikan $10$ dengan $4$ .

$32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Langkah 2.4.2.1.2.8

Kalikan $5$ dengan $2$ .

$32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$

Langkah 2.5

Bagi setiap suku pada $32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$ dengan $32$ dan sederhanakan.

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Langkah 2.5.1

Bagilah setiap suku di $32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$ dengan $32$ .

$\frac{32 y}{32} = \frac{32}{32} + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.2

Sederhanakan sisi kirinya.

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Langkah 2.5.2.1

Batalkan faktor persekutuan dari $32$ .

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Langkah 2.5.2.1.1

Batalkan faktor persekutuan.

$\frac{32 y}{32} = \frac{32}{32} + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.2.1.2

Bagilah $y$ dengan $1$ .

$y = \frac{32}{32} + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3

Sederhanakan sisi kanannya.

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Langkah 2.5.3.1

Sederhanakan setiap suku.

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Langkah 2.5.3.1.1

Bagilah $32$ dengan $32$ .

$y = 1 + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.2

Hapus faktor persekutuan dari $80$ dan $32$ .

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Langkah 2.5.3.1.2.1

Faktorkan $16$ dari $80 x$ .

$y = 1 + \frac{16 (5 x)}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.2.2

Batalkan faktor persekutuan.

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Langkah 2.5.3.1.2.2.1

Faktorkan $16$ dari $32$ .

$y = 1 + \frac{16 (5 x)}{16 (2)} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.2.2.2

Batalkan faktor persekutuan.

$y = 1 + \frac{16 (5 x)}{16 \cdot 2} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.2.2.3

Tulis kembali pernyataannya.

$y = 1 + \frac{5 x}{2} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.3

Hapus faktor persekutuan dari $80$ dan $32$ .

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Langkah 2.5.3.1.3.1

Faktorkan $16$ dari $80 x^{2}$ .

$y = 1 + \frac{5 x}{2} + \frac{16 (5 x^{2})}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.3.2

Batalkan faktor persekutuan.

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Langkah 2.5.3.1.3.2.1

Faktorkan $16$ dari $32$ .

$y = 1 + \frac{5 x}{2} + \frac{16 (5 x^{2})}{16 (2)} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.3.2.2

Batalkan faktor persekutuan.

$y = 1 + \frac{5 x}{2} + \frac{16 (5 x^{2})}{16 \cdot 2} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.3.2.3

Tulis kembali pernyataannya.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.4

Hapus faktor persekutuan dari $40$ dan $32$ .

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Langkah 2.5.3.1.4.1

Faktorkan $8$ dari $40 x^{3}$ .

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{8 (5 x^{3})}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.4.2

Batalkan faktor persekutuan.

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Langkah 2.5.3.1.4.2.1

Faktorkan $8$ dari $32$ .

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{8 (5 x^{3})}{8 (4)} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.4.2.2

Batalkan faktor persekutuan.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{8 (5 x^{3})}{8 \cdot 4} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.4.2.3

Tulis kembali pernyataannya.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.5

Hapus faktor persekutuan dari $10$ dan $32$ .

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Langkah 2.5.3.1.5.1

Faktorkan $2$ dari $10 x^{4}$ .

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{2 (5 x^{4})}{32} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.5.2

Batalkan faktor persekutuan.

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Langkah 2.5.3.1.5.2.1

Faktorkan $2$ dari $32$ .

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{2 (5 x^{4})}{2 (16)} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.5.2.2

Batalkan faktor persekutuan.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{2 (5 x^{4})}{2 \cdot 16} + \frac{x^{5}}{32}$

Langkah 2.5.3.1.5.2.3

Tulis kembali pernyataannya.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$

Langkah 3

Ganti $y$ dengan $f^{- 1} (x)$ untuk memunculkan jawaban akhir.

$f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$

Langkah 4

Periksa apakah $f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$ merupakan balikan dari $f (x) = 2 x^{\frac{1}{5}} - 2$ .

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Langkah 4.1

Untuk memverifikasi balikannya, periksa apakah $f^{- 1} (f (x)) = x$ dan $f (f^{- 1} (x)) = x$ .

Langkah 4.2

Evaluasi $f^{- 1} (f (x))$ .

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Langkah 4.2.1

Tulis fungsi hasil komposit.

$f^{- 1} (f (x))$

Langkah 4.2.2

Evaluasi $f^{- 1} (2 x^{\frac{1}{5}} - 2)$ dengan mensubstitusikan nilai (Variabel1) ke dalam (Variabel2).

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{5 (2 x^{\frac{1}{5}} - 2)}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3

Sederhanakan setiap suku.

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Langkah 4.2.3.1

Faktorkan $2$ dari $5 (2 x^{\frac{1}{5}} - 2)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{2 (5 (x^{\frac{1}{5}} - 1))}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.2

Batalkan faktor persekutuan.

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Langkah 4.2.3.2.1

Faktorkan $2$ dari $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{2 (5 (x^{\frac{1}{5}} - 1))}{2 (1)} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.2.2

Batalkan faktor persekutuan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{2 (5 (x^{\frac{1}{5}} - 1))}{2 \cdot 1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.2.3

Tulis kembali pernyataannya.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{5 (x^{\frac{1}{5}} - 1)}{1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.2.4

Bagilah $5 (x^{\frac{1}{5}} - 1)$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 (x^{\frac{1}{5}} - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.3

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 5 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.4

Kalikan $5$ dengan $- 1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.5

Sederhanakan pembilangnya.

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Langkah 4.2.3.5.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}} - 2$ .

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Langkah 4.2.3.5.1.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 (x^{\frac{1}{5}}) - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.5.1.2

Faktorkan $2$ dari $- 2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 (x^{\frac{1}{5}}) + 2 (- 1))}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.5.1.3

Faktorkan $2$ dari $2 (x^{\frac{1}{5}}) + 2 (- 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 (x^{\frac{1}{5}} - 1))}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.5.2

Terapkan kaidah hasil kali ke $2 (x^{\frac{1}{5}} - 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 \cdot (2^{2} {(x^{\frac{1}{5}} - 1)}^{2})}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.5.3

Naikkan $2$ menjadi pangkat $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 \cdot (4 {(x^{\frac{1}{5}} - 1)}^{2})}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.5.4

Kalikan $5$ dengan $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{20 {(x^{\frac{1}{5}} - 1)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.6

Faktorkan $2$ dari $20 {(x^{\frac{1}{5}} - 1)}^{2}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{2 (10 {(x^{\frac{1}{5}} - 1)}^{2})}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.7

Batalkan faktor persekutuan.

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Langkah 4.2.3.7.1

Faktorkan $2$ dari $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{2 (10 {(x^{\frac{1}{5}} - 1)}^{2})}{2 (1)} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.7.2

Batalkan faktor persekutuan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{2 (10 {(x^{\frac{1}{5}} - 1)}^{2})}{2 \cdot 1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.7.3

Tulis kembali pernyataannya.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{10 {(x^{\frac{1}{5}} - 1)}^{2}}{1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.7.4

Bagilah $10 {(x^{\frac{1}{5}} - 1)}^{2}$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 {(x^{\frac{1}{5}} - 1)}^{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.8

Tulis kembali ${(x^{\frac{1}{5}} - 1)}^{2}$ sebagai $(x^{\frac{1}{5}} - 1) (x^{\frac{1}{5}} - 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 ((x^{\frac{1}{5}} - 1) (x^{\frac{1}{5}} - 1)) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.9

Perluas $(x^{\frac{1}{5}} - 1) (x^{\frac{1}{5}} - 1)$ menggunakan Metode FOIL.

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Langkah 4.2.3.9.1

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5}} (x^{\frac{1}{5}} - 1) - 1 (x^{\frac{1}{5}} - 1)) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.9.2

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5}} x^{\frac{1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 (x^{\frac{1}{5}} - 1)) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.9.3

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5}} x^{\frac{1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10

Sederhanakan dan gabungkan suku-suku sejenis.

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Langkah 4.2.3.10.1

Sederhanakan setiap suku.

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Langkah 4.2.3.10.1.1

Kalikan $x^{\frac{1}{5}}$ dengan $x^{\frac{1}{5}}$ dengan menambahkan eksponennya.

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Langkah 4.2.3.10.1.1.1

Gunakan kaidah pangkat $a^{m} a^{n} = a^{m + n}$ untuk menggabungkan pangkat.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5} + \frac{1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.1.1.2

Gabungkan pembilang dari penyebut persekutuan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1 + 1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.1.1.3

Tambahkan $1$ dan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.1.2

Pindahkan $- 1$ ke sebelah kiri $x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - 1 \cdot x^{\frac{1}{5}} - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.1.3

Tulis kembali $- 1 x^{\frac{1}{5}}$ sebagai $- x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - x^{\frac{1}{5}} - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.1.4

Tulis kembali $- 1 x^{\frac{1}{5}}$ sebagai $- x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - x^{\frac{1}{5}} - x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.1.5

Kalikan $- 1$ dengan $- 1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - x^{\frac{1}{5}} - x^{\frac{1}{5}} + 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.10.2

Kurangi $x^{\frac{1}{5}}$ dengan $- x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - 2 x^{\frac{1}{5}} + 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.11

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} + 10 (- 2 x^{\frac{1}{5}}) + 10 \cdot 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.12

Sederhanakan.

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Langkah 4.2.3.12.1

Kalikan $- 2$ dengan $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 \cdot 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.12.2

Kalikan $10$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.13

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Langkah 4.2.3.13.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}} - 2$ .

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Langkah 4.2.3.13.1.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 (x^{\frac{1}{5}}) - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.13.1.2

Faktorkan $2$ dari $- 2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 (x^{\frac{1}{5}}) + 2 (- 1))}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.13.1.3

Faktorkan $2$ dari $2 (x^{\frac{1}{5}}) + 2 (- 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 (x^{\frac{1}{5}} - 1))}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.13.2

Terapkan kaidah hasil kali ke $2 (x^{\frac{1}{5}} - 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 \cdot (2^{3} {(x^{\frac{1}{5}} - 1)}^{3})}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.13.3

Naikkan $2$ menjadi pangkat $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 \cdot (8 {(x^{\frac{1}{5}} - 1)}^{3})}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.13.4

Kalikan $5$ dengan $8$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{40 {(x^{\frac{1}{5}} - 1)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.14

Faktorkan $4$ dari $40 {(x^{\frac{1}{5}} - 1)}^{3}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{4 (10 {(x^{\frac{1}{5}} - 1)}^{3})}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.15

Batalkan faktor persekutuan.

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Langkah 4.2.3.15.1

Faktorkan $4$ dari $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{4 (10 {(x^{\frac{1}{5}} - 1)}^{3})}{4 (1)} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.15.2

Batalkan faktor persekutuan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{4 (10 {(x^{\frac{1}{5}} - 1)}^{3})}{4 \cdot 1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.15.3

Tulis kembali pernyataannya.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{10 {(x^{\frac{1}{5}} - 1)}^{3}}{1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.15.4

Bagilah $10 {(x^{\frac{1}{5}} - 1)}^{3}$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 {(x^{\frac{1}{5}} - 1)}^{3} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.16

Gunakan Teorema Binomial.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 ({(x^{\frac{1}{5}})}^{3} + 3 {(x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17

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Langkah 4.2.3.17.1

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{3}$ .

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Langkah 4.2.3.17.1.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{1}{5} \cdot 3} + 3 {(x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.1.2

Gabungkan $\frac{1}{5}$ dan $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} + 3 {(x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.2

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{2}$ .

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Langkah 4.2.3.17.2.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} + 3 x^{\frac{1}{5} \cdot 2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.2.2

Gabungkan $\frac{1}{5}$ dan $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} + 3 x^{\frac{2}{5}} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.3

Kalikan $- 1$ dengan $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.4

Naikkan $- 1$ menjadi pangkat $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} \cdot 1 + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.5

Kalikan $3$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.17.6

Naikkan $- 1$ menjadi pangkat $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.18

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} + 10 (- 3 x^{\frac{2}{5}}) + 10 (3 x^{\frac{1}{5}}) + 10 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.19

Sederhanakan.

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Langkah 4.2.3.19.1

Kalikan $- 3$ dengan $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 10 (3 x^{\frac{1}{5}}) + 10 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.19.2

Kalikan $3$ dengan $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 10 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.19.3

Kalikan $10$ dengan $- 1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.20

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Langkah 4.2.3.20.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}} - 2$ .

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Langkah 4.2.3.20.1.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 (x^{\frac{1}{5}}) - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.20.1.2

Faktorkan $2$ dari $- 2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 (x^{\frac{1}{5}}) + 2 (- 1))}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.20.1.3

Faktorkan $2$ dari $2 (x^{\frac{1}{5}}) + 2 (- 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 (x^{\frac{1}{5}} - 1))}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.20.2

Terapkan kaidah hasil kali ke $2 (x^{\frac{1}{5}} - 1)$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 \cdot (2^{4} {(x^{\frac{1}{5}} - 1)}^{4})}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.20.3

Naikkan $2$ menjadi pangkat $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 \cdot (16 {(x^{\frac{1}{5}} - 1)}^{4})}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.20.4

Kalikan $5$ dengan $16$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{80 {(x^{\frac{1}{5}} - 1)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.21

Faktorkan $16$ dari $80 {(x^{\frac{1}{5}} - 1)}^{4}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{16 (5 {(x^{\frac{1}{5}} - 1)}^{4})}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.22

Batalkan faktor persekutuan.

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Langkah 4.2.3.22.1

Faktorkan $16$ dari $16$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{16 (5 {(x^{\frac{1}{5}} - 1)}^{4})}{16 (1)} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.22.2

Batalkan faktor persekutuan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{16 (5 {(x^{\frac{1}{5}} - 1)}^{4})}{16 \cdot 1} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.22.3

Tulis kembali pernyataannya.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(x^{\frac{1}{5}} - 1)}^{4}}{1} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.22.4

Bagilah $5 {(x^{\frac{1}{5}} - 1)}^{4}$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 {(x^{\frac{1}{5}} - 1)}^{4} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.23

Gunakan Teorema Binomial.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 ({(x^{\frac{1}{5}})}^{4} + 4 {(x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24

Sederhanakan setiap suku.

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Langkah 4.2.3.24.1

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{4}$ .

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Langkah 4.2.3.24.1.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{1}{5} \cdot 4} + 4 {(x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.1.2

Gabungkan $\frac{1}{5}$ dan $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} + 4 {(x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.2

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{3}$ .

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Langkah 4.2.3.24.2.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} + 4 x^{\frac{1}{5} \cdot 3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.2.2

Gabungkan $\frac{1}{5}$ dan $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} + 4 x^{\frac{3}{5}} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.3

Kalikan $- 1$ dengan $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.4

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{2}$ .

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Langkah 4.2.3.24.4.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{1}{5} \cdot 2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.4.2

Gabungkan $\frac{1}{5}$ dan $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.5

Naikkan $- 1$ menjadi pangkat $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} \cdot 1 + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.6

Kalikan $6$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.7

Naikkan $- 1$ menjadi pangkat $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} + 4 x^{\frac{1}{5}} \cdot - 1 + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.8

Kalikan $- 1$ dengan $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} - 4 x^{\frac{1}{5}} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.24.9

Naikkan $- 1$ menjadi pangkat $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} - 4 x^{\frac{1}{5}} + 1) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.25

Terapkan sifat distributif.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} + 5 (- 4 x^{\frac{3}{5}}) + 5 (6 x^{\frac{2}{5}}) + 5 (- 4 x^{\frac{1}{5}}) + 5 \cdot 1 + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.26

Sederhanakan.

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Langkah 4.2.3.26.1

Kalikan $- 4$ dengan $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 5 (6 x^{\frac{2}{5}}) + 5 (- 4 x^{\frac{1}{5}}) + 5 \cdot 1 + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.26.2

Kalikan $6$ dengan $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} + 5 (- 4 x^{\frac{1}{5}}) + 5 \cdot 1 + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Langkah 4.2.3.26.3

Kalikan $- 4$ dengan $5$ .

Langkah 4.2.3.26.4

Kalikan $5$ dengan $1$ .

Langkah 4.2.3.27

Sederhanakan pembilangnya.

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Langkah 4.2.3.27.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}} - 2$ .

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Langkah 4.2.3.27.1.1

Faktorkan $2$ dari $2 x^{\frac{1}{5}}$ .

Langkah 4.2.3.27.1.2

Faktorkan $2$ dari $- 2$ .

Langkah 4.2.3.27.1.3

Faktorkan $2$ dari $2 (x^{\frac{1}{5}}) + 2 (- 1)$ .

Langkah 4.2.3.27.2

Terapkan kaidah hasil kali ke $2 (x^{\frac{1}{5}} - 1)$ .

Langkah 4.2.3.27.3

Naikkan $2$ menjadi pangkat $5$ .

Langkah 4.2.3.28

Batalkan faktor persekutuan.

Langkah 4.2.3.29

Bagilah ${(x^{\frac{1}{5}} - 1)}^{5}$ dengan $1$ .

Langkah 4.2.3.30

Gunakan Teorema Binomial.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + {(x^{\frac{1}{5}})}^{5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31

Sederhanakan setiap suku.

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Langkah 4.2.3.31.1

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{5}$ .

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Langkah 4.2.3.31.1.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x^{\frac{1}{5} \cdot 5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.1.2

Batalkan faktor persekutuan dari $5$ .

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Langkah 4.2.3.31.1.2.1

Batalkan faktor persekutuan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x^{\frac{1}{5} \cdot 5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.1.2.2

Tulis kembali pernyataannya.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.2

Sederhanakan.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.3

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{4}$ .

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Langkah 4.2.3.31.3.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 x^{\frac{1}{5} \cdot 4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.3.2

Gabungkan $\frac{1}{5}$ dan $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 x^{\frac{4}{5}} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.4

Kalikan $- 1$ dengan $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.5

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{3}$ .

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Langkah 4.2.3.31.5.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{1}{5} \cdot 3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.5.2

Gabungkan $\frac{1}{5}$ dan $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.6

Naikkan $- 1$ menjadi pangkat $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} \cdot 1 + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.7

Kalikan $10$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.8

Kalikan eksponen dalam ${(x^{\frac{1}{5}})}^{2}$ .

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Langkah 4.2.3.31.8.1

Terapkan kaidah pangkat dan perkalian eksponen, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 x^{\frac{1}{5} \cdot 2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.8.2

Gabungkan $\frac{1}{5}$ dan $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 x^{\frac{2}{5}} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.9

Naikkan $- 1$ menjadi pangkat $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 x^{\frac{2}{5}} \cdot - 1 + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.10

Kalikan $- 1$ dengan $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Langkah 4.2.3.31.11

Naikkan $- 1$ menjadi pangkat $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} \cdot 1 + {(- 1)}^{5}$

Langkah 4.2.3.31.12

Kalikan $5$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} + {(- 1)}^{5}$

Langkah 4.2.3.31.13

Naikkan $- 1$ menjadi pangkat $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4

Sederhanakan dengan menambahkan suku-suku.

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Langkah 4.2.4.1

Gabungkan suku balikan dalam $1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$ .

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Langkah 4.2.4.1.1

Kurangi $10$ dengan $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 0 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.2

Tambahkan $1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}}$ dan $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.3

Tambahkan $- 30 x^{\frac{2}{5}}$ dan $30 x^{\frac{2}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 0 - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.4

Tambahkan $1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}}$ dan $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.5

Tambahkan $- 5$ dan $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + 0 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.6

Tambahkan $1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}}$ dan $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.7

Kurangi $5 x^{\frac{4}{5}}$ dengan $5 x^{\frac{4}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 0 + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.8

Tambahkan $1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x$ dan $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.9

Kurangi $10 x^{\frac{2}{5}}$ dengan $10 x^{\frac{2}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 0 + 5 x^{\frac{1}{5}} - 1$

Langkah 4.2.4.1.10

Tambahkan $1 + 5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}}$ dan $0$ .

Langkah 4.2.4.1.11

Kurangi $1$ dengan $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}} + 0$

Langkah 4.2.4.1.12

Tambahkan $5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$ dan $0$ .

Langkah 4.2.4.2

Kurangi $20 x^{\frac{1}{5}}$ dengan $5 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = - 15 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$

Langkah 4.2.4.3

Tambahkan $- 15 x^{\frac{1}{5}}$ dan $30 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 15 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$

Langkah 4.2.4.4

Kurangi $20 x^{\frac{1}{5}}$ dengan $15 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = - 5 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$

Langkah 4.2.4.5

Gabungkan suku balikan dalam $- 5 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$ .

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Langkah 4.2.4.5.1

Tambahkan $- 5 x^{\frac{1}{5}}$ dan $5 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}} + 0$

Langkah 4.2.4.5.2

Tambahkan $10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$ dan $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$

Langkah 4.2.4.6

Kurangi $20 x^{\frac{3}{5}}$ dengan $10 x^{\frac{3}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = - 10 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$

Langkah 4.2.4.7

Gabungkan suku balikan dalam $- 10 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$ .

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Langkah 4.2.4.7.1

Tambahkan $- 10 x^{\frac{3}{5}}$ dan $10 x^{\frac{3}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = x + 0$

Langkah 4.2.4.7.2

Tambahkan $x$ dan $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = x$

Langkah 4.3

Evaluasi $f (f^{- 1} (x))$ .

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Langkah 4.3.1

Tulis fungsi hasil komposit.

$f (f^{- 1} (x))$

Langkah 4.3.2

Evaluasi $f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32})$ dengan mensubstitusikan nilai (Variabel1) ke dalam (Variabel2).

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32})}^{\frac{1}{5}} - 2$

Langkah 4.3.3

Pindahkan $1$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + 1)}^{\frac{1}{5}} - 2$

Langkah 4.3.4

Pindahkan $\frac{5 x}{2}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Langkah 4.3.5

Pindahkan $\frac{5 x^{2}}{2}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Langkah 4.3.6

Pindahkan $\frac{5 x^{3}}{4}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x^{3}}{4} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Langkah 4.3.7

Susun kembali $\frac{5 x^{4}}{16}$ dan $\frac{x^{5}}{32}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{x^{5}}{32} + \frac{5 x^{4}}{16} + \frac{5 x^{3}}{4} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Langkah 4.4

Karena $f^{- 1} (f (x)) = x$ dan $f (f^{- 1} (x)) = x$ , maka $f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$ merupakan balikan dari $f (x) = 2 x^{\frac{1}{5}} - 2$ .

$f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$