लीनियर एलजेब्रा उदाहरण

$[\begin{array}{c} 0 & \cos (x) & \sin (x) \\ 0 & - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \\ 0 & 3 \cos (x) + 4 \sin (x) & - 4 \cos (x) + 3 \sin (x) \end{array}]$

Step 1

Multiply every element in the $1 s t$ column by its cofactor and add.

$0 | \begin{array}{c} - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \\ 3 \cos (x) + 4 \sin (x) & - 4 \cos (x) + 3 \sin (x) \end{array} | + 0 | \begin{array}{c} \cos (x) & \sin (x) \\ 3 \cos (x) + 4 \sin (x) & - 4 \cos (x) + 3 \sin (x) \end{array} | + 0 | \begin{array}{c} \cos (x) & \sin (x) \\ - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \end{array} |$

Step 2

$0$ को $| \begin{array}{c} - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \\ 3 \cos (x) + 4 \sin (x) & - 4 \cos (x) + 3 \sin (x) \end{array} |$ से गुणा करें.

$0 + 0 | \begin{array}{c} \cos (x) & \sin (x) \\ 3 \cos (x) + 4 \sin (x) & - 4 \cos (x) + 3 \sin (x) \end{array} | + 0 | \begin{array}{c} \cos (x) & \sin (x) \\ - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \end{array} |$

Step 3

$0$ को $| \begin{array}{c} \cos (x) & \sin (x) \\ 3 \cos (x) + 4 \sin (x) & - 4 \cos (x) + 3 \sin (x) \end{array} |$ से गुणा करें.

$0 + 0 + 0 | \begin{array}{c} \cos (x) & \sin (x) \\ - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \end{array} |$

Step 4

$0$ को $| \begin{array}{c} \cos (x) & \sin (x) \\ - 2 \cos (x) - \sin (x) & \cos (x) - 2 \sin (x) \end{array} |$ से गुणा करें.

$0 + 0 + 0$

Step 5

सारणिक को सरल करें.

और स्टेप्स के लिए टैप करें…

$0$ और $0$ जोड़ें.

$0 + 0$

$0$ और $0$ जोड़ें.

$0$