लीनियर एलजेब्रा उदाहरण

[\begin{array}{c} - 6 & 5 \end{array}]

$[\begin{array}{c} - 6 & 5 \end{array}]$

चरण 1

Multiply each element of

R_{1}

$R_{1}$ by

- \frac{1}{6}

$- \frac{1}{6}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

[\begin{array}{c} - \frac{1}{6} \cdot - 6 & - \frac{1}{6} \cdot 5 \end{array}]

$[\begin{array}{c} - \frac{1}{6} \cdot - 6 & - \frac{1}{6} \cdot 5 \end{array}]$

चरण 2

R_{1}

$R_{1}$ को सरल करें.

[\begin{array}{c} 1 & - \frac{5}{6} \end{array}]

$[\begin{array}{c} 1 & - \frac{5}{6} \end{array}]$