Exemples

[\begin{array}{c} 4 \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 4 \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 1

Nullity is the dimension of the null space, which is the same as the number of free variables in the system after row reducing. The free variables are the columns without pivot positions.

Étape 2

Déterminez la forme d’échelon en ligne réduite.

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Étape 2.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

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Étape 2.1.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

[\begin{array}{c} \frac{4}{4} \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} \frac{4}{4} \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 2.1.2

Simplifiez

R_{1}

$R_{1}$ .

[\begin{array}{c} 1 \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 4 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 2.2

Perform the row operation

R_{3} = R_{3} - 4 R_{1}

$R_{3} = R_{3} - 4 R_{1}$ to make the entry at

3, 1

$3, 1$ a

0

$0$ .

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Étape 2.2.1

Perform the row operation

R_{3} = R_{3} - 4 R_{1}

$R_{3} = R_{3} - 4 R_{1}$ to make the entry at

3, 1

$3, 1$ a

0

$0$ .

[\begin{array}{c} 1 \\ 0 \\ 4 - 4 \cdot 1 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 4 - 4 \cdot 1 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 2.2.2

Simplifiez

R_{3}

$R_{3}$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 5 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 2.3

Perform the row operation

R_{4} = R_{4} - 5 R_{1}

$R_{4} = R_{4} - 5 R_{1}$ to make the entry at

4, 1

$4, 1$ a

0

$0$ .

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Étape 2.3.1

Perform the row operation

R_{4} = R_{4} - 5 R_{1}

$R_{4} = R_{4} - 5 R_{1}$ to make the entry at

4, 1

$4, 1$ a

0

$0$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 5 - 5 \cdot 1 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 5 - 5 \cdot 1 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 2.3.2

Simplifiez

R_{4}

$R_{4}$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 6 \\ 7 \\ 8 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 6 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 6 \\ 7 \\ 8 \end{array}]$

Étape 2.4

Perform the row operation

R_{5} = R_{5} - 6 R_{1}

$R_{5} = R_{5} - 6 R_{1}$ to make the entry at

5, 1

$5, 1$ a

0

$0$ .

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Étape 2.4.1

Perform the row operation

R_{5} = R_{5} - 6 R_{1}

$R_{5} = R_{5} - 6 R_{1}$ to make the entry at

5, 1

$5, 1$ a

0

$0$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 6 - 6 \cdot 1 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 6 - 6 \cdot 1 \\ 7 \\ 8 \end{array}]$

Étape 2.4.2

Simplifiez

R_{5}

$R_{5}$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 7 \\ 8 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 7 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 7 \\ 8 \end{array}]$

Étape 2.5

Perform the row operation

R_{6} = R_{6} - 7 R_{1}

$R_{6} = R_{6} - 7 R_{1}$ to make the entry at

6, 1

$6, 1$ a

0

$0$ .

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Étape 2.5.1

Perform the row operation

R_{6} = R_{6} - 7 R_{1}

$R_{6} = R_{6} - 7 R_{1}$ to make the entry at

6, 1

$6, 1$ a

0

$0$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 7 - 7 \cdot 1 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 7 - 7 \cdot 1 \\ 8 \end{array}]$

Étape 2.5.2

Simplifiez

R_{6}

$R_{6}$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 8 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 8 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 8 \end{array}]$

Étape 2.6

Perform the row operation

R_{7} = R_{7} - 8 R_{1}

$R_{7} = R_{7} - 8 R_{1}$ to make the entry at

7, 1

$7, 1$ a

0

$0$ .

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Étape 2.6.1

Perform the row operation

R_{7} = R_{7} - 8 R_{1}

$R_{7} = R_{7} - 8 R_{1}$ to make the entry at

7, 1

$7, 1$ a

0

$0$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 8 - 8 \cdot 1 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 8 - 8 \cdot 1 \end{array}]$

Étape 2.6.2

Simplifiez

R_{7}

$R_{7}$ .

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \end{array}]$

[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \end{array}]

$[\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \\ 0 \end{array}]$

Étape 3

The pivot positions are the locations with the leading

1

$1$ in each row. The pivot columns are the columns that have a pivot position.

Pivot Positions:

a_{11}

$a_{11}$

Pivot Columns:

1

$1$

Étape 4

The nullity is the number of columns without a pivot position in the row reduced matrix.

0

$0$

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