输入问题...
三角学 示例
sin(7x)sin(7x)
解题步骤 1
展开 sin(7x)sin(7x) 的好方法是利用棣美弗定理 (r(cos(x)+i⋅sin(x))n=rn(cos(nx)+i⋅sin(nx)))(r(cos(x)+i⋅sin(x))n=rn(cos(nx)+i⋅sin(nx)))。当 r=1r=1 时,cos(nx)+i⋅sin(nx)=(cos(x)+i⋅sin(x))ncos(nx)+i⋅sin(nx)=(cos(x)+i⋅sin(x))n。
cos(nx)+i⋅sin(nx)=(cos(x)+i⋅sin(x))ncos(nx)+i⋅sin(nx)=(cos(x)+i⋅sin(x))n
解题步骤 2
使用二项式定理来展开 cos(nx)+i⋅sin(nx)=(cos(x)+i⋅sin(x))ncos(nx)+i⋅sin(nx)=(cos(x)+i⋅sin(x))n 的右边。
展开:(cos(x)+i⋅sin(x))7(cos(x)+i⋅sin(x))7
解题步骤 3
使用二项式定理。
cos7(x)+7cos6(x)(isin(x))+21cos5(x)(isin(x))2+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)(isin(x))+21cos5(x)(isin(x))2+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4
解题步骤 4.1
化简每一项。
解题步骤 4.1.1
对 isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)+21cos5(x)(i2sin2(x))+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)+21cos5(x)(i2sin2(x))+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.2
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)+21⋅i2cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)+21⋅i2cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.3
将 i2i2 重写为 -1−1。
cos7(x)+7cos6(x)isin(x)+21⋅-1cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)+21⋅−1cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.4
将 2121 乘以 -1−1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.5
对 isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35cos4(x)(i3sin3(x))+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)+35cos4(x)(i3sin3(x))+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.6
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35⋅i3cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)+35⋅i3cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.7
因式分解出 i2i2。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35⋅(i2⋅i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)+35⋅(i2⋅i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.8
将 i2i2 重写为 -1−1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35⋅(-1⋅i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)+35⋅(−1⋅i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.9
将 -1i−1i 重写为 -i−i。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35⋅(-i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)+35⋅(−i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.10
将 -1−1 乘以 3535。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.11
对 isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)(i4sin4(x))+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)(i4sin4(x))+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.12
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35⋅i4cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35⋅i4cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.13
将 i4i4 重写为 11。
解题步骤 4.1.13.1
将 i4i4 重写为 (i2)2(i2)2。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35⋅(i2)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35⋅(i2)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.13.2
将 i2i2 重写为 -1−1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35⋅(-1)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35⋅(−1)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.13.3
对 -1−1 进行 22 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35⋅1cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35⋅1cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35⋅1cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35⋅1cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.14
将 3535 乘以 11。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.15
对 isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(i5sin5(x))+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(i5sin5(x))+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.16
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅i5cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅i5cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.17
因式分解出 i4i4。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅(i4i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅(i4i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.18
将 i4i4 重写为 11。
解题步骤 4.1.18.1
将 i4i4 重写为 (i2)2(i2)2。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅((i2)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅((i2)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.18.2
将 i2i2 重写为 -1−1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅((-1)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅((−1)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.18.3
对 -1−1 进行 22 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.19
将 ii 乘以 11。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅icos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21⋅icos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.20
对 isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i6sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i6sin6(x))+(isin(x))7
解题步骤 4.1.21
因式分解出 i4i4。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i4i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i4i2sin6(x))+(isin(x))7
解题步骤 4.1.22
将 i4i4 重写为 11。
解题步骤 4.1.22.1
将 i4i4 重写为 (i2)2(i2)2。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((i2)2i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((i2)2i2sin6(x))+(isin(x))7
解题步骤 4.1.22.2
将 i2i2 重写为 -1−1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((-1)2i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((−1)2i2sin6(x))+(isin(x))7
解题步骤 4.1.22.3
对 -1−1 进行 22 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)−21cos5(x)sin2(x)−35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7
解题步骤 4.1.23
将 i2 乘以 1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i2sin6(x))+(isin(x))7
解题步骤 4.1.24
将 i2 重写为 -1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(-1sin6(x))+(isin(x))7
解题步骤 4.1.25
将 -1sin6(x) 重写为 -sin6(x)。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(-sin6(x))+(isin(x))7
解题步骤 4.1.26
将 -1 乘以 7。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+(isin(x))7
解题步骤 4.1.27
对 isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i7sin7(x)
解题步骤 4.1.28
将 i7 重写为 i4(i2⋅i)。
解题步骤 4.1.28.1
因式分解出 i4。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i4i3sin7(x)
解题步骤 4.1.28.2
因式分解出 i2。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i4(i2⋅i)sin7(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i4(i2⋅i)sin7(x)
解题步骤 4.1.29
将 i4 重写为 1。
解题步骤 4.1.29.1
将 i4 重写为 (i2)2。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+(i2)2(i2⋅i)sin7(x)
解题步骤 4.1.29.2
将 i2 重写为 -1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+(-1)2(i2⋅i)sin7(x)
解题步骤 4.1.29.3
对 -1 进行 2 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+1(i2⋅i)sin7(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+1(i2⋅i)sin7(x)
解题步骤 4.1.30
将 i2⋅i 乘以 1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i2⋅isin7(x)
解题步骤 4.1.31
将 i2 重写为 -1。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-1⋅isin7(x)
解题步骤 4.1.32
将 -1i 重写为 -i。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
解题步骤 4.2
将 cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x) 中的因式重新排序。
cos7(x)+7icos6(x)sin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
cos7(x)+7icos6(x)sin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
解题步骤 5
提取虚部等于 sin(7x) 的表达式。去掉虚数 i。
sin(7x)=7cos6(x)sin(x)-35cos4(x)sin3(x)+21cos2(x)sin5(x)-sin7(x)