三角学 示例

使用棣莫弗定理展开 sin(7x)
sin(7x)sin(7x)
解题步骤 1
展开 sin(7x)sin(7x) 的好方法是利用棣美弗定理 (r(cos(x)+isin(x))n=rn(cos(nx)+isin(nx)))(r(cos(x)+isin(x))n=rn(cos(nx)+isin(nx)))。当 r=1r=1 时,cos(nx)+isin(nx)=(cos(x)+isin(x))ncos(nx)+isin(nx)=(cos(x)+isin(x))n
cos(nx)+isin(nx)=(cos(x)+isin(x))ncos(nx)+isin(nx)=(cos(x)+isin(x))n
解题步骤 2
使用二项式定理来展开 cos(nx)+isin(nx)=(cos(x)+isin(x))ncos(nx)+isin(nx)=(cos(x)+isin(x))n 的右边。
展开:(cos(x)+isin(x))7(cos(x)+isin(x))7
解题步骤 3
使用二项式定理。
cos7(x)+7cos6(x)(isin(x))+21cos5(x)(isin(x))2+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)(isin(x))+21cos5(x)(isin(x))2+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4
化简项。
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解题步骤 4.1
化简每一项。
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解题步骤 4.1.1
isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)+21cos5(x)(i2sin2(x))+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)+21cos5(x)(i2sin2(x))+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.2
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)+21i2cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)+21i2cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.3
i2i2 重写为 -11
cos7(x)+7cos6(x)isin(x)+21-1cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)+211cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.4
2121 乘以 -11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)+35cos4(x)(isin(x))3+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.5
isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35cos4(x)(i3sin3(x))+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)+35cos4(x)(i3sin3(x))+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.6
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35i3cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)+35i3cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.7
因式分解出 i2i2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35(i2i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)+35(i2i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.8
i2i2 重写为 -11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35(-1i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)+35(1i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.9
-1i1i 重写为 -ii
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)+35(-i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)+35(i)cos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.10
-11 乘以 3535
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)(isin(x))4+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.11
isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)(i4sin4(x))+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)(i4sin4(x))+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.12
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35i4cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35i4cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.13
i4i4 重写为 11
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解题步骤 4.1.13.1
i4i4 重写为 (i2)2(i2)2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35(i2)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35(i2)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.13.2
i2i2 重写为 -11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35(-1)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35(1)2cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.13.3
-11 进行 22 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+351cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+351cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+351cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+351cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.14
3535 乘以 11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(isin(x))5+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.15
isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(i5sin5(x))+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21cos2(x)(i5sin5(x))+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.16
使用乘法的交换性质重写。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21i5cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21i5cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.17
因式分解出 i4i4
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21(i4i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21(i4i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.18
i4i4 重写为 11
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解题步骤 4.1.18.1
i4i4 重写为 (i2)2(i2)2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21((i2)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21((i2)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.18.2
i2i2 重写为 -11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21((-1)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21((1)2i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.18.3
-11 进行 22 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21(1i)cos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.19
ii 乘以 11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(isin(x))6+(isin(x))7
解题步骤 4.1.20
isin(x)isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i6sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i6sin6(x))+(isin(x))7
解题步骤 4.1.21
因式分解出 i4i4
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i4i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i4i2sin6(x))+(isin(x))7
解题步骤 4.1.22
i4i4 重写为 11
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解题步骤 4.1.22.1
i4i4 重写为 (i2)2(i2)2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((i2)2i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((i2)2i2sin6(x))+(isin(x))7
解题步骤 4.1.22.2
i2i2 重写为 -11
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((-1)2i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)((1)2i2sin6(x))+(isin(x))7
解题步骤 4.1.22.3
-11 进行 22 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7cos7(x)+7cos6(x)isin(x)21cos5(x)sin2(x)35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(1i2sin6(x))+(isin(x))7
解题步骤 4.1.23
i2 乘以 1
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(i2sin6(x))+(isin(x))7
解题步骤 4.1.24
i2 重写为 -1
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(-1sin6(x))+(isin(x))7
解题步骤 4.1.25
-1sin6(x) 重写为 -sin6(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)+7cos(x)(-sin6(x))+(isin(x))7
解题步骤 4.1.26
-1 乘以 7
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+(isin(x))7
解题步骤 4.1.27
isin(x) 运用乘积法则。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i7sin7(x)
解题步骤 4.1.28
i7 重写为 i4(i2i)
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解题步骤 4.1.28.1
因式分解出 i4
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i4i3sin7(x)
解题步骤 4.1.28.2
因式分解出 i2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i4(i2i)sin7(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i4(i2i)sin7(x)
解题步骤 4.1.29
i4 重写为 1
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解题步骤 4.1.29.1
i4 重写为 (i2)2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+(i2)2(i2i)sin7(x)
解题步骤 4.1.29.2
i2 重写为 -1
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+(-1)2(i2i)sin7(x)
解题步骤 4.1.29.3
-1 进行 2 次方运算。
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+1(i2i)sin7(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+1(i2i)sin7(x)
解题步骤 4.1.30
i2i 乘以 1
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)+i2isin7(x)
解题步骤 4.1.31
i2 重写为 -1
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-1isin7(x)
解题步骤 4.1.32
-1i 重写为 -i
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
解题步骤 4.2
cos7(x)+7cos6(x)isin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x) 中的因式重新排序。
cos7(x)+7icos6(x)sin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
cos7(x)+7icos6(x)sin(x)-21cos5(x)sin2(x)-35icos4(x)sin3(x)+35cos3(x)sin4(x)+21icos2(x)sin5(x)-7cos(x)sin6(x)-isin7(x)
解题步骤 5
提取虚部等于 sin(7x) 的表达式。去掉虚数 i
sin(7x)=7cos6(x)sin(x)-35cos4(x)sin3(x)+21cos2(x)sin5(x)-sin7(x)
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