三角学示例

$\frac{1}{\sec (x + 1)} + \frac{1}{\sec (x - 1)} = 2 \cot (x) \csc (x)$

解题步骤 1

对方程两边进行作图。

$y = \frac{1}{\sec (x + 1)} + \frac{1}{\sec (x - 1)}$

$y = 2 \cot (x) \csc (x)$

解题步骤 2

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$