三角学示例

$\frac{\cot (A) \csc (A)}{\sec (A)} = \frac{\cot^{2} (A) + 1}{\tan^{2} (A) + 1}$

解题步骤 1

对方程两边进行作图。

$y = \frac{\cot (A) \csc (A)}{\sec (A)}$

$y = \frac{\cot^{2} (A) + 1}{\tan^{2} (A) + 1}$

解题步骤 2

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$