三角学 示例

化简 (cos(y)+1/y*sin(x)-1/y*sin(y))/(1/y*cos(x)+xcos(y)-x/y*sin(y))
cos(y)+1ysin(x)-1ysin(y)1ycos(x)+xcos(y)-xysin(y)cos(y)+1ysin(x)1ysin(y)1ycos(x)+xcos(y)xysin(y)
解题步骤 1
化简分子。
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解题步骤 1.1
组合 1y1ysin(x)sin(x)
cos(y)+sin(x)y-1ysin(y)1ycos(x)+xcos(y)-xysin(y)cos(y)+sin(x)y1ysin(y)1ycos(x)+xcos(y)xysin(y)
解题步骤 1.2
组合 sin(y)sin(y)1y1y
cos(y)+sin(x)y-sin(y)y1ycos(x)+xcos(y)-xysin(y)cos(y)+sin(x)ysin(y)y1ycos(x)+xcos(y)xysin(y)
cos(y)+sin(x)y-sin(y)y1ycos(x)+xcos(y)-xysin(y)cos(y)+sin(x)ysin(y)y1ycos(x)+xcos(y)xysin(y)
解题步骤 2
化简分母。
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解题步骤 2.1
组合 1y1ycos(x)cos(x)
cos(y)+sin(x)y-sin(y)ycos(x)y+xcos(y)-xysin(y)cos(y)+sin(x)ysin(y)ycos(x)y+xcos(y)xysin(y)
解题步骤 2.2
组合 sin(y)sin(y)xyxy
cos(y)+sin(x)y-sin(y)ycos(x)y+xcos(y)-sin(y)xycos(y)+sin(x)ysin(y)ycos(x)y+xcos(y)sin(y)xy
cos(y)+sin(x)y-sin(y)ycos(x)y+xcos(y)-sin(y)xycos(y)+sin(x)ysin(y)ycos(x)y+xcos(y)sin(y)xy
解题步骤 3
Multiply the numerator and denominator of the fraction by yy.
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解题步骤 3.1
cos(y)+sin(x)y-sin(y)ycos(x)y+xcos(y)-sin(y)xycos(y)+sin(x)ysin(y)ycos(x)y+xcos(y)sin(y)xy 乘以 yyyy
yycos(y)+sin(x)y-sin(y)ycos(x)y+xcos(y)-sin(y)xyyycos(y)+sin(x)ysin(y)ycos(x)y+xcos(y)sin(y)xy
解题步骤 3.2
合并。
y(cos(y)+sin(x)y-sin(y)y)y(cos(x)y+xcos(y)-sin(y)xy)y(cos(y)+sin(x)ysin(y)y)y(cos(x)y+xcos(y)sin(y)xy)
y(cos(y)+sin(x)y-sin(y)y)y(cos(x)y+xcos(y)-sin(y)xy)y(cos(y)+sin(x)ysin(y)y)y(cos(x)y+xcos(y)sin(y)xy)
解题步骤 4
运用分配律。
ycos(y)+ysin(x)y+y(-sin(y)y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)ycos(y)+ysin(x)y+y(sin(y)y)ycos(x)y+y(xcos(y))+y(sin(y)xy)
解题步骤 5
通过相约进行化简。
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解题步骤 5.1
约去 yy 的公因数。
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解题步骤 5.1.1
约去公因数。
ycos(y)+ysin(x)y+y(-sin(y)y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.1.2
重写表达式。
ycos(y)+sin(x)+y(-sin(y)y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)
ycos(y)+sin(x)+y(-sin(y)y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.2
约去 y 的公因数。
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解题步骤 5.2.1
-sin(y)y 中前置负号移到分子中。
ycos(y)+sin(x)+y-sin(y)yycos(x)y+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.2.2
约去公因数。
ycos(y)+sin(x)+y-sin(y)yycos(x)y+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.2.3
重写表达式。
ycos(y)+sin(x)-sin(y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)
ycos(y)+sin(x)-sin(y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.3
约去 y 的公因数。
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解题步骤 5.3.1
约去公因数。
ycos(y)+sin(x)-sin(y)ycos(x)y+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.3.2
重写表达式。
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))+y(-sin(y)xy)
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))+y(-sin(y)xy)
解题步骤 5.4
约去 y 的公因数。
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解题步骤 5.4.1
-sin(y)xy 中前置负号移到分子中。
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))+y-sin(y)xy
解题步骤 5.4.2
约去公因数。
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))+y-sin(y)xy
解题步骤 5.4.3
重写表达式。
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))-sin(y)x
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))-sin(y)x
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))-sin(y)x
解题步骤 6
ycos(y)+sin(x)-sin(y)cos(x)+y(xcos(y))-sin(y)x 中的因式重新排序。
ycos(y)+sin(x)-sin(y)cos(x)+yxcos(y)-xsin(y)
 [x2  12  π  xdx ]