初级微积分示例

$[\begin{array}{c} - 1 & 2 & - 6 \end{array}] = [\begin{array}{c} - 6 & 5 & - 4 \end{array}] - X$

解题步骤 1

Move all terms not containing a variable to the right side.

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解题步骤 1.1

从等式两边同时减去 $[\begin{array}{c} - 1 & 2 & - 6 \end{array}]$ 。

$0 = [\begin{array}{c} - 6 & 5 & - 4 \end{array}] - X - [\begin{array}{c} - 1 & 2 & - 6 \end{array}]$

解题步骤 2

Move all terms containing a variable to the left side.

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解题步骤 2.1

在等式两边都加上 $X$ 。

$X = [\begin{array}{c} - 6 & 5 & - 4 \end{array}] - [\begin{array}{c} - 1 & 2 & - 6 \end{array}]$

初级微积分 示例