初等代数 示例

Since ${\displaystyle 25x^2,25y}$ contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part ${\displaystyle 25,25}$ then find LCM for the variable part ${\displaystyle x^2,y^1}$.

最小公倍数是能被所有数整除的最小正数。

${\displaystyle 25}$ 具有因式 ${\displaystyle 5}$ 和 ${\displaystyle 5}$。

将 ${\displaystyle 5}$ 乘以 ${\displaystyle 5}$。

${\displaystyle x^2}$ 的因数为 ${\displaystyle x\cdot x}$，即 ${\displaystyle x}$ 连续相乘 ${\displaystyle 2}$ 次。

${\displaystyle y^1}$ 的因式是 ${\displaystyle y}$ 本身。

${\displaystyle x^2,y^1}$ 的最小公倍数为在任一数中出现次数最多的所有质因数的乘积。

将 ${\displaystyle x}$ 乘以 ${\displaystyle x}$。