线性代数示例

$[\begin{array}{c} 4 & 1 & - 3 \\ 3 & 2 & 5 \\ 0 & 1 & 6 \end{array}]$

解题步骤 1

求行简化阶梯形矩阵。

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解题步骤 1.1

Multiply each element of $R_{1}$ by $\frac{1}{4}$ to make the entry at $1, 1$ a $1$ .

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解题步骤 1.1.1

Multiply each element of $R_{1}$ by $\frac{1}{4}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} \frac{4}{4} & \frac{1}{4} & \frac{- 3}{4} \\ 3 & 2 & 5 \\ 0 & 1 & 6 \end{array}]$

解题步骤 1.1.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 3 & 2 & 5 \\ 0 & 1 & 6 \end{array}]$

解题步骤 1.2

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

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解题步骤 1.2.1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 3 - 3 \cdot 1 & 2 - 3 (\frac{1}{4}) & 5 - 3 (- \frac{3}{4}) \\ 0 & 1 & 6 \end{array}]$

解题步骤 1.2.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & \frac{5}{4} & \frac{29}{4} \\ 0 & 1 & 6 \end{array}]$

解题步骤 1.3

Multiply each element of $R_{2}$ by $\frac{4}{5}$ to make the entry at $2, 2$ a $1$ .

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解题步骤 1.3.1

Multiply each element of $R_{2}$ by $\frac{4}{5}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ \frac{4}{5} \cdot 0 & \frac{4}{5} \cdot \frac{5}{4} & \frac{4}{5} \cdot \frac{29}{4} \\ 0 & 1 & 6 \end{array}]$

解题步骤 1.3.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & 1 & \frac{29}{5} \\ 0 & 1 & 6 \end{array}]$

解题步骤 1.4

Perform the row operation $R_{3} = R_{3} - R_{2}$ to make the entry at $3, 2$ a $0$ .

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解题步骤 1.4.1

Perform the row operation $R_{3} = R_{3} - R_{2}$ to make the entry at $3, 2$ a $0$ .

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & 1 & \frac{29}{5} \\ 0 - 0 & 1 - 1 & 6 - \frac{29}{5} \end{array}]$

解题步骤 1.4.2

化简 $R_{3}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & 1 & \frac{29}{5} \\ 0 & 0 & \frac{1}{5} \end{array}]$

解题步骤 1.5

Multiply each element of $R_{3}$ by $5$ to make the entry at $3, 3$ a $1$ .

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解题步骤 1.5.1

Multiply each element of $R_{3}$ by $5$ to make the entry at $3, 3$ a $1$ .

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & 1 & \frac{29}{5} \\ 5 \cdot 0 & 5 \cdot 0 & 5 (\frac{1}{5}) \end{array}]$

解题步骤 1.5.2

化简 $R_{3}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & 1 & \frac{29}{5} \\ 0 & 0 & 1 \end{array}]$

解题步骤 1.6

Perform the row operation $R_{2} = R_{2} - \frac{29}{5} R_{3}$ to make the entry at $2, 3$ a $0$ .

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解题步骤 1.6.1

Perform the row operation $R_{2} = R_{2} - \frac{29}{5} R_{3}$ to make the entry at $2, 3$ a $0$ .

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 - \frac{29}{5} \cdot 0 & 1 - \frac{29}{5} \cdot 0 & \frac{29}{5} - \frac{29}{5} \cdot 1 \\ 0 & 0 & 1 \end{array}]$

解题步骤 1.6.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & - \frac{3}{4} \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}]$

解题步骤 1.7

Perform the row operation $R_{1} = R_{1} + \frac{3}{4} R_{3}$ to make the entry at $1, 3$ a $0$ .

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解题步骤 1.7.1

Perform the row operation $R_{1} = R_{1} + \frac{3}{4} R_{3}$ to make the entry at $1, 3$ a $0$ .

$[\begin{array}{c} 1 + \frac{3}{4} \cdot 0 & \frac{1}{4} + \frac{3}{4} \cdot 0 & - \frac{3}{4} + \frac{3}{4} \cdot 1 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}]$

解题步骤 1.7.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & \frac{1}{4} & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}]$

解题步骤 1.8

Perform the row operation $R_{1} = R_{1} - \frac{1}{4} R_{2}$ to make the entry at $1, 2$ a $0$ .

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解题步骤 1.8.1

Perform the row operation $R_{1} = R_{1} - \frac{1}{4} R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - \frac{1}{4} \cdot 0 & \frac{1}{4} - \frac{1}{4} \cdot 1 & 0 - \frac{1}{4} \cdot 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}]$

解题步骤 1.8.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}]$

解题步骤 2

The pivot positions are the locations with the leading $1$ in each row. The pivot columns are the columns that have a pivot position.

Pivot Positions: $a_{11}, a_{22},$ and $a_{33}$

Pivot Columns: $1, 2,$ and $3$

线性代数 示例

线性代数示例