线性代数示例

$[\begin{array}{c} \cos (b) & \frac{i}{g} \cdot \sin (b) \\ \sin (b) \cdot (i g) & \cos (b) \end{array}] \cdot [\begin{array}{c} \cos (a) & \frac{i}{d} \cdot \sin (a) \\ \sin (a) \cdot (i d) & \cos (a) \end{array}]$

解题步骤 1

组合 $\frac{i}{g}$ 和 $\sin (b)$ 。

$[\begin{array}{c} \cos (b) & \frac{i \sin (b)}{g} \\ \sin (b) \cdot (i g) & \cos (b) \end{array}] \cdot [\begin{array}{c} \cos (a) & \frac{i}{d} \cdot \sin (a) \\ \sin (a) \cdot (i d) & \cos (a) \end{array}]$

解题步骤 2

使用乘法的交换性质重写。

$[\begin{array}{c} \cos (b) & \frac{i \sin (b)}{g} \\ i \sin (b) g & \cos (b) \end{array}] \cdot [\begin{array}{c} \cos (a) & \frac{i}{d} \cdot \sin (a) \\ \sin (a) \cdot (i d) & \cos (a) \end{array}]$

解题步骤 3

组合 $\frac{i}{d}$ 和 $\sin (a)$ 。

$[\begin{array}{c} \cos (b) & \frac{i \sin (b)}{g} \\ i \sin (b) g & \cos (b) \end{array}] \cdot [\begin{array}{c} \cos (a) & \frac{i \sin (a)}{d} \\ \sin (a) \cdot (i d) & \cos (a) \end{array}]$

解题步骤 4

使用乘法的交换性质重写。

$[\begin{array}{c} \cos (b) & \frac{i \sin (b)}{g} \\ i \sin (b) g & \cos (b) \end{array}] \cdot [\begin{array}{c} \cos (a) & \frac{i \sin (a)}{d} \\ i \sin (a) d & \cos (a) \end{array}]$

解题步骤 5

乘以 $[\begin{array}{c} \cos (b) & \frac{i \sin (b)}{g} \\ i \sin (b) g & \cos (b) \end{array}] [\begin{array}{c} \cos (a) & \frac{i \sin (a)}{d} \\ i \sin (a) d & \cos (a) \end{array}]$ 。

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解题步骤 5.1

Two matrices can be multiplied if and only if the number of columns in the first matrix is equal to the number of rows in the second matrix. In this case, the first matrix is $2 \times 2$ and the second matrix is $2 \times 2$ .

解题步骤 5.2

将第一个矩阵中的每一行乘以第二个矩阵中的每一列。

$[\begin{array}{c} \cos (b) \cos (a) + \frac{i \sin (b)}{g} (i \sin (a) d) & \cos (b) \frac{i \sin (a)}{d} + \frac{i \sin (b)}{g} \cos (a) \\ i \sin (b) g \cos (a) + \cos (b) (i \sin (a) d) & i \sin (b) g \frac{i \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3

通过展开所有表达式化简矩阵的每一个元素。

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解题步骤 5.3.1

乘以 $i \sin (b) g \frac{i \sin (a)}{d}$ 。

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解题步骤 5.3.1.1

组合 $i$ 和 $\frac{i \sin (a)}{d}$ 。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \sin (b) g \frac{i (i \sin (a))}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.1.2

对 $i$ 进行 $1$ 次方运算。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \sin (b) g \frac{i^{1} i \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.1.3

对 $i$ 进行 $1$ 次方运算。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \sin (b) g \frac{i^{1} i^{1} \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.1.4

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \sin (b) g \frac{i^{1 + 1} \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.1.5

将 $1$ 和 $1$ 相加。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \sin (b) g \frac{i^{2} \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.1.6

组合 $\sin (b)$ 和 $\frac{i^{2} \sin (a)}{d}$ 。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & g \frac{\sin (b) (i^{2} \sin (a))}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.1.7

组合 $g$ 和 $\frac{\sin (b) (i^{2} \sin (a))}{d}$ 。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \frac{g (\sin (b) (i^{2} \sin (a)))}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.2

化简分子。

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解题步骤 5.3.2.1

将 $i^{2}$ 重写为 $- 1$ 。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \frac{g \sin (b) \cdot - 1 \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.2.2

提取负因数。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & \frac{- g \sin (b) \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

解题步骤 5.3.3

将负号移到分数的前面。

$[\begin{array}{c} \cos (b) \cos (a) - \frac{d \sin (a) \sin (b)}{g} & \frac{i \cos (b) \sin (a)}{d} + \frac{i \sin (b) \cos (a)}{g} \\ i g \sin (b) \cos (a) + i d \cos (b) \sin (a) & - \frac{g \sin (b) \sin (a)}{d} + \cos (b) \cos (a) \end{array}]$

线性代数 示例

线性代数示例