有限数学示例

$[\begin{array}{c} 2 & 4 \\ - 6 & - 4 \\ x & 4 \end{array}] + [\begin{array}{c} 4 & 10 \\ - 4 & - 2 \\ - 5 & y \end{array}] = [\begin{array}{c} 6 & 6 \\ - 10 & - 6 \\ - 4 & 2 \end{array}]$

解题步骤 1

加上相应元素。

$[\begin{array}{c} 2 + 4 & 4 + 10 \\ - 6 - 4 & - 4 - 2 \\ x - 5 & 4 + y \end{array}] = [\begin{array}{c} 6 & 6 \\ - 10 & - 6 \\ - 4 & 2 \end{array}]$

解题步骤 2

Simplify each element.

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解题步骤 2.1

将 $2$ 和 $4$ 相加。

$[\begin{array}{c} 6 & 4 + 10 \\ - 6 - 4 & - 4 - 2 \\ x - 5 & 4 + y \end{array}] = [\begin{array}{c} 6 & 6 \\ - 10 & - 6 \\ - 4 & 2 \end{array}]$

解题步骤 2.2

将 $4$ 和 $10$ 相加。

$[\begin{array}{c} 6 & 14 \\ - 6 - 4 & - 4 - 2 \\ x - 5 & 4 + y \end{array}] = [\begin{array}{c} 6 & 6 \\ - 10 & - 6 \\ - 4 & 2 \end{array}]$

解题步骤 2.3

从 $- 6$ 中减去 $4$ 。

$[\begin{array}{c} 6 & 14 \\ - 10 & - 4 - 2 \\ x - 5 & 4 + y \end{array}] = [\begin{array}{c} 6 & 6 \\ - 10 & - 6 \\ - 4 & 2 \end{array}]$

解题步骤 2.4

从 $- 4$ 中减去 $2$ 。

$[\begin{array}{c} 6 & 14 \\ - 10 & - 6 \\ x - 5 & 4 + y \end{array}] = [\begin{array}{c} 6 & 6 \\ - 10 & - 6 \\ - 4 & 2 \end{array}]$

解题步骤 3

Write as a linear system of equations.

$6 = 6$

$14 = 6$

$- 10 = - 10$

$- 6 = - 6$

$x - 5 = - 4$

$4 + y = 2$

解题步骤 4

Since $14 \neq 6$ , the matrix equation has no solution.

无解

有限数学 示例

有限数学示例