有限数学示例

$[\begin{array}{c} a + 6 & 5 z + 1 & 2 m \\ 2 k & 0 & 0 \end{array}] + [\begin{array}{c} 12 a & 8 x & 6 m \\ 2 k & 0 & 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 1

加上相应元素。

$[\begin{array}{c} a + 6 + 12 a & 5 z + 1 + 8 x & 2 m + 6 m \\ 2 k + 2 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 2

Simplify each element.

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解题步骤 2.1

将 $a$ 和 $12 a$ 相加。

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 2 m + 6 m \\ 2 k + 2 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 2.2

将 $2 m$ 和 $6 m$ 相加。

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 2 k + 2 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 2.3

将 $2 k$ 和 $2 k$ 相加。

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 4 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 2.4

将 $0$ 和 $0$ 相加。

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 4 k & 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 2.5

将 $0$ 和 $0$ 相加。

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 4 k & 0 & 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

解题步骤 3

Write as a linear system of equations.

$13 a + 6 = 58$

$5 z + 1 + 8 x = - 38$

$8 m = 24$

$4 k = 12$

$0 = 0$

解题步骤 4

Since $0 = 0$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.

有限数学 示例

有限数学示例