有限数学示例

$c = 15 x + 600$ , $r = 30 x$

解题步骤 1

Move variables to the left and constant terms to the right.

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解题步骤 1.1

从等式两边同时减去 $15 x$ 。

$c - 15 x = 600$

$r = 30 x$

解题步骤 1.2

从等式两边同时减去 $30 x$ 。

$c - 15 x = 600$

$r - 30 x = 0$

$c - 15 x = 600$

$r - 30 x = 0$

解题步骤 2

Write the system as a matrix.

$[\begin{array}{c} 1 & 0 & - 15 & 600 \\ 0 & 1 & - 30 & 0 \end{array}]$

解题步骤 3

Use the result matrix to declare the final solution to the system of equations.

$c - 15 x = 600$

$r - 30 x = 0$

解题步骤 4

The solution is the set of ordered pairs that make the system true.

$(600 + 15 x, 30 x, x)$

有限数学 示例