微积分学示例

$y = \frac{{(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3}}{{(e^{x} + 1)}^{7}}$

解题步骤 1

在等式两边同时取微分

$\frac{d}{d x} (y) = \frac{d}{d x} (\frac{{(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3}}{{(e^{x} + 1)}^{7}})$

解题步骤 2

$y$ 对 $x$ 的导数为 $y'$ 。

$y'$

解题步骤 3

对方程右边求微分。

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解题步骤 3.1

使用除法定则求微分，根据该法则， $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ 等于 $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ ，其中 $f (x) = {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3}$ 且 $g (x) = {(e^{x} + 1)}^{7}$ 。

$\frac{{(e^{x} + 1)}^{7} \frac{d}{d x} [{(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3}] - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{({(e^{x} + 1)}^{7})}^{2}}$

解题步骤 3.2

将 ${({(e^{x} + 1)}^{7})}^{2}$ 中的指数相乘。

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解题步骤 3.2.1

运用幂法则并将指数相乘， ${(a^{m})}^{n} = a^{m n}$ 。

$\frac{{(e^{x} + 1)}^{7} \frac{d}{d x} [{(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3}] - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{7 \cdot 2}}$

解题步骤 3.2.2

将 $7$ 乘以 $2$ 。

$\frac{{(e^{x} + 1)}^{7} \frac{d}{d x} [{(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3}] - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.3

使用乘积法则求微分，根据该法则， $\frac{d}{d x} [f (x) g (x)]$ 等于 $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ ，其中 $f (x) = {(x^{2} + 1)}^{10}$ 且 $g (x) = {(x^{2} + 2)}^{3}$ 。

$\frac{{(e^{x} + 1)}^{7} ({(x^{2} + 1)}^{10} \frac{d}{d x} [{(x^{2} + 2)}^{3}] + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.4

使用链式法则求微分，根据该法则， $\frac{d}{d x} [f (g (x))]$ 等于 $f' (g (x)) g' (x)$ ，其中 $f (x) = x^{3}$ 且 $g (x) = x^{2} + 2$ 。

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解题步骤 3.4.1

要使用链式法则，请将 $u_{1}$ 设为 $x^{2} + 2$ 。

$\frac{{(e^{x} + 1)}^{7} ({(x^{2} + 1)}^{10} (\frac{d}{d u_{1}} [{u_{1}}^{3}] \frac{d}{d x} [x^{2} + 2]) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.4.2

使用幂法则求微分，根据该法则， $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ 等于 $n {u_{1}}^{n - 1}$ ，其中 $n = 3$ 。

$\frac{{(e^{x} + 1)}^{7} ({(x^{2} + 1)}^{10} (3 {u_{1}}^{2} \frac{d}{d x} [x^{2} + 2]) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.4.3

使用 $x^{2} + 2$ 替换所有出现的 $u_{1}$ 。

$\frac{{(e^{x} + 1)}^{7} ({(x^{2} + 1)}^{10} (3 {(x^{2} + 2)}^{2} \frac{d}{d x} [x^{2} + 2]) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.5

求微分。

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解题步骤 3.5.1

将 $3$ 移到 ${(x^{2} + 1)}^{10}$ 的左侧。

$\frac{{(e^{x} + 1)}^{7} (3 \cdot {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} \frac{d}{d x} [x^{2} + 2] + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.5.2

根据加法法则， $x^{2} + 2$ 对 $x$ 的导数是 $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [2]$ 。

$\frac{{(e^{x} + 1)}^{7} (3 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [2]) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.5.3

使用幂法则求微分，根据该法则， $\frac{d}{d x} [x^{n}]$ 等于 $n x^{n - 1}$ ，其中 $n = 2$ 。

$\frac{{(e^{x} + 1)}^{7} (3 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} (2 x + \frac{d}{d x} [2]) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.5.4

因为 $2$ 对于 $x$ 是常数，所以 $2$ 对 $x$ 的导数为 $0$ 。

$\frac{{(e^{x} + 1)}^{7} (3 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} (2 x + 0) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.5.5

化简表达式。

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解题步骤 3.5.5.1

将 $2 x$ 和 $0$ 相加。

$\frac{{(e^{x} + 1)}^{7} (3 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} (2 x) + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.5.5.2

将 $2$ 乘以 $3$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + {(x^{2} + 2)}^{3} \frac{d}{d x} [{(x^{2} + 1)}^{10}]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.6

使用链式法则求微分，根据该法则， $\frac{d}{d x} [f (g (x))]$ 等于 $f' (g (x)) g' (x)$ ，其中 $f (x) = x^{10}$ 且 $g (x) = x^{2} + 1$ 。

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解题步骤 3.6.1

要使用链式法则，请将 $u_{2}$ 设为 $x^{2} + 1$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + {(x^{2} + 2)}^{3} (\frac{d}{d u_{2}} [{u_{2}}^{10}] \frac{d}{d x} [x^{2} + 1])) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.6.2

使用幂法则求微分，根据该法则， $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ 等于 $n {u_{2}}^{n - 1}$ ，其中 $n = 10$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + {(x^{2} + 2)}^{3} (10 {u_{2}}^{9} \frac{d}{d x} [x^{2} + 1])) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.6.3

使用 $x^{2} + 1$ 替换所有出现的 $u_{2}$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + {(x^{2} + 2)}^{3} (10 {(x^{2} + 1)}^{9} \frac{d}{d x} [x^{2} + 1])) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.7

求微分。

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解题步骤 3.7.1

将 $10$ 移到 ${(x^{2} + 2)}^{3}$ 的左侧。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 10 \cdot {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} \frac{d}{d x} [x^{2} + 1]) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.7.2

根据加法法则， $x^{2} + 1$ 对 $x$ 的导数是 $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1]$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 10 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1])) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.7.3

使用幂法则求微分，根据该法则， $\frac{d}{d x} [x^{n}]$ 等于 $n x^{n - 1}$ ，其中 $n = 2$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 10 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} (2 x + \frac{d}{d x} [1])) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.7.4

因为 $1$ 对于 $x$ 是常数，所以 $1$ 对 $x$ 的导数为 $0$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 10 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} (2 x + 0)) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.7.5

化简表达式。

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解题步骤 3.7.5.1

将 $2 x$ 和 $0$ 相加。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 10 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} (2 x)) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.7.5.2

将 $2$ 乘以 $10$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} \frac{d}{d x} [{(e^{x} + 1)}^{7}]}{{(e^{x} + 1)}^{14}}$

解题步骤 3.8

使用链式法则求微分，根据该法则， $\frac{d}{d x} [f (g (x))]$ 等于 $f' (g (x)) g' (x)$ ，其中 $f (x) = x^{7}$ 且 $g (x) = e^{x} + 1$ 。

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解题步骤 3.8.1

要使用链式法则，请将 $u_{3}$ 设为 $e^{x} + 1$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (\frac{d}{d u_{3}} [{u_{3}}^{7}] \frac{d}{d x} [e^{x} + 1])}{{(e^{x} + 1)}^{14}}$

解题步骤 3.8.2

使用幂法则求微分，根据该法则， $\frac{d}{d u_{3}} [{u_{3}}^{n}]$ 等于 $n {u_{3}}^{n - 1}$ ，其中 $n = 7$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (7 {u_{3}}^{6} \frac{d}{d x} [e^{x} + 1])}{{(e^{x} + 1)}^{14}}$

解题步骤 3.8.3

使用 $e^{x} + 1$ 替换所有出现的 $u_{3}$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (7 {(e^{x} + 1)}^{6} \frac{d}{d x} [e^{x} + 1])}{{(e^{x} + 1)}^{14}}$

解题步骤 3.9

通过提取公因式进行化简。

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解题步骤 3.9.1

将 $7$ 乘以 $- 1$ 。

$\frac{{(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} ({(e^{x} + 1)}^{6} \frac{d}{d x} [e^{x} + 1])}{{(e^{x} + 1)}^{14}}$

解题步骤 3.9.2

从 ${(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} ({(e^{x} + 1)}^{6} \frac{d}{d x} [e^{x} + 1])$ 中分解出因数 ${(e^{x} + 1)}^{6}$ 。

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解题步骤 3.9.2.1

从 ${(e^{x} + 1)}^{7} (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x)$ 中分解出因数 ${(e^{x} + 1)}^{6}$ 。

$\frac{{(e^{x} + 1)}^{6} ((e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x)) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} ({(e^{x} + 1)}^{6} \frac{d}{d x} [e^{x} + 1])}{{(e^{x} + 1)}^{14}}$

解题步骤 3.9.2.2

从 $- 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} ({(e^{x} + 1)}^{6} \frac{d}{d x} [e^{x} + 1])$ 中分解出因数 ${(e^{x} + 1)}^{6}$ 。

$\frac{{(e^{x} + 1)}^{6} ((e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x)) + {(e^{x} + 1)}^{6} (- 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (\frac{d}{d x} [e^{x} + 1]))}{{(e^{x} + 1)}^{14}}$

解题步骤 3.9.2.3

从 ${(e^{x} + 1)}^{6} ((e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x)) + {(e^{x} + 1)}^{6} (- 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (\frac{d}{d x} [e^{x} + 1]))$ 中分解出因数 ${(e^{x} + 1)}^{6}$ 。

$\frac{{(e^{x} + 1)}^{6} ((e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (\frac{d}{d x} [e^{x} + 1]))}{{(e^{x} + 1)}^{14}}$

解题步骤 3.10

约去公因数。

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解题步骤 3.10.1

从 ${(e^{x} + 1)}^{14}$ 中分解出因数 ${(e^{x} + 1)}^{6}$ 。

解题步骤 3.10.2

约去公因数。

解题步骤 3.10.3

重写表达式。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (\frac{d}{d x} [e^{x} + 1])}{{(e^{x} + 1)}^{8}}$

解题步骤 3.11

根据加法法则， $e^{x} + 1$ 对 $x$ 的导数是 $\frac{d}{d x} [e^{x}] + \frac{d}{d x} [1]$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (\frac{d}{d x} [e^{x}] + \frac{d}{d x} [1])}{{(e^{x} + 1)}^{8}}$

解题步骤 3.12

使用指数法则求微分，根据该法则， $\frac{d}{d x} [a^{x}]$ 等于 $a^{x} \ln (a)$ ，其中 $a$ = $e$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (e^{x} + \frac{d}{d x} [1])}{{(e^{x} + 1)}^{8}}$

解题步骤 3.13

使用常数法则求导。

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解题步骤 3.13.1

因为 $1$ 对于 $x$ 是常数，所以 $1$ 对 $x$ 的导数为 $0$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} (e^{x} + 0)}{{(e^{x} + 1)}^{8}}$

解题步骤 3.13.2

将 $e^{x}$ 和 $0$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{2} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14

化简分子。

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解题步骤 3.14.1

化简每一项。

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解题步骤 3.14.1.1

将 ${(x^{2} + 2)}^{2}$ 重写为 $(x^{2} + 2) (x^{2} + 2)$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} ((x^{2} + 2) (x^{2} + 2)) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.2

使用 FOIL 方法展开 $(x^{2} + 2) (x^{2} + 2)$ 。

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解题步骤 3.14.1.2.1

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{2} (x^{2} + 2) + 2 (x^{2} + 2)) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.2.2

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{2} x^{2} + x^{2} \cdot 2 + 2 (x^{2} + 2)) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.2.3

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{2} x^{2} + x^{2} \cdot 2 + 2 x^{2} + 2 \cdot 2) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.3

化简并合并同类项。

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解题步骤 3.14.1.3.1

化简每一项。

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解题步骤 3.14.1.3.1.1

通过指数相加将 $x^{2}$ 乘以 $x^{2}$ 。

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解题步骤 3.14.1.3.1.1.1

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{2 + 2} + x^{2} \cdot 2 + 2 x^{2} + 2 \cdot 2) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.3.1.1.2

将 $2$ 和 $2$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{4} + x^{2} \cdot 2 + 2 x^{2} + 2 \cdot 2) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.3.1.2

将 $2$ 移到 $x^{2}$ 的左侧。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{4} + 2 \cdot x^{2} + 2 x^{2} + 2 \cdot 2) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.3.1.3

将 $2$ 乘以 $2$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{4} + 2 x^{2} + 2 x^{2} + 4) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.3.2

将 $2 x^{2}$ 和 $2 x^{2}$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{4} + 4 x^{2} + 4) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.4

运用分配律。

$\frac{(e^{x} + 1) ((6 {(x^{2} + 1)}^{10} x^{4} + 6 {(x^{2} + 1)}^{10} (4 x^{2}) + 6 {(x^{2} + 1)}^{10} \cdot 4) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.5

化简。

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解题步骤 3.14.1.5.1

使用乘法的交换性质重写。

$\frac{(e^{x} + 1) ((6 {(x^{2} + 1)}^{10} x^{4} + 6 \cdot 4 {(x^{2} + 1)}^{10} x^{2} + 6 {(x^{2} + 1)}^{10} \cdot 4) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.5.2

将 $4$ 乘以 $6$ 。

$\frac{(e^{x} + 1) ((6 {(x^{2} + 1)}^{10} x^{4} + 6 \cdot 4 {(x^{2} + 1)}^{10} x^{2} + 24 {(x^{2} + 1)}^{10}) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.6

将 $6$ 乘以 $4$ 。

$\frac{(e^{x} + 1) ((6 {(x^{2} + 1)}^{10} x^{4} + 24 {(x^{2} + 1)}^{10} x^{2} + 24 {(x^{2} + 1)}^{10}) x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.7

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{4} x + 24 {(x^{2} + 1)}^{10} x^{2} x + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8

化简。

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解题步骤 3.14.1.8.1

通过指数相加将 $x^{4}$ 乘以 $x$ 。

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解题步骤 3.14.1.8.1.1

移动 $x$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x \cdot x^{4}) + 24 {(x^{2} + 1)}^{10} x^{2} x + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.1.2

将 $x$ 乘以 $x^{4}$ 。

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解题步骤 3.14.1.8.1.2.1

对 $x$ 进行 $1$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} (x^{1} x^{4}) + 24 {(x^{2} + 1)}^{10} x^{2} x + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.1.2.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{1 + 4} + 24 {(x^{2} + 1)}^{10} x^{2} x + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.1.3

将 $1$ 和 $4$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{2} x + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.2

通过指数相加将 $x^{2}$ 乘以 $x$ 。

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解题步骤 3.14.1.8.2.1

移动 $x$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} (x \cdot x^{2}) + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.2.2

将 $x$ 乘以 $x^{2}$ 。

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解题步骤 3.14.1.8.2.2.1

对 $x$ 进行 $1$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} (x^{1} x^{2}) + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.2.2.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{1 + 2} + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.8.2.3

将 $1$ 和 $2$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 {(x^{2} + 2)}^{3} {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.9

使用二项式定理。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 ({(x^{2})}^{3} + 3 {(x^{2})}^{2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10

化简每一项。

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解题步骤 3.14.1.10.1

将 ${(x^{2})}^{3}$ 中的指数相乘。

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解题步骤 3.14.1.10.1.1

运用幂法则并将指数相乘， ${(a^{m})}^{n} = a^{m n}$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{2 \cdot 3} + 3 {(x^{2})}^{2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.1.2

将 $2$ 乘以 $3$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 3 {(x^{2})}^{2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.2

将 ${(x^{2})}^{2}$ 中的指数相乘。

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解题步骤 3.14.1.10.2.1

运用幂法则并将指数相乘， ${(a^{m})}^{n} = a^{m n}$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 3 x^{2 \cdot 2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.2.2

将 $2$ 乘以 $2$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 3 x^{4} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.3

将 $2$ 乘以 $3$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 6 x^{4} + 3 x^{2} \cdot 2^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.4

对 $2$ 进行 $2$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 6 x^{4} + 3 x^{2} \cdot 4 + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.5

将 $4$ 乘以 $3$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 6 x^{4} + 12 x^{2} + 2^{3}) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.10.6

对 $2$ 进行 $3$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{6} + 6 x^{4} + 12 x^{2} + 8) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.11

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + (20 x^{6} + 20 (6 x^{4}) + 20 (12 x^{2}) + 20 \cdot 8) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.12

化简。

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解题步骤 3.14.1.12.1

将 $6$ 乘以 $20$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + (20 x^{6} + 120 x^{4} + 20 (12 x^{2}) + 20 \cdot 8) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.12.2

将 $12$ 乘以 $20$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + (20 x^{6} + 120 x^{4} + 240 x^{2} + 20 \cdot 8) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.12.3

将 $20$ 乘以 $8$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + (20 x^{6} + 120 x^{4} + 240 x^{2} + 160) {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.13

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + (20 x^{6} {(x^{2} + 1)}^{9} + 120 x^{4} {(x^{2} + 1)}^{9} + 240 x^{2} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9}) x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.14

运用分配律。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{6} {(x^{2} + 1)}^{9} x + 120 x^{4} {(x^{2} + 1)}^{9} x + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15

化简。

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解题步骤 3.14.1.15.1

通过指数相加将 $x^{6}$ 乘以 $x$ 。

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解题步骤 3.14.1.15.1.1

移动 $x$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x \cdot x^{6}) {(x^{2} + 1)}^{9} + 120 x^{4} {(x^{2} + 1)}^{9} x + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.1.2

将 $x$ 乘以 $x^{6}$ 。

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解题步骤 3.14.1.15.1.2.1

对 $x$ 进行 $1$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 (x^{1} x^{6}) {(x^{2} + 1)}^{9} + 120 x^{4} {(x^{2} + 1)}^{9} x + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.1.2.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{1 + 6} {(x^{2} + 1)}^{9} + 120 x^{4} {(x^{2} + 1)}^{9} x + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.1.3

将 $1$ 和 $6$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{4} {(x^{2} + 1)}^{9} x + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.2

通过指数相加将 $x^{4}$ 乘以 $x$ 。

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解题步骤 3.14.1.15.2.1

移动 $x$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 (x \cdot x^{4}) {(x^{2} + 1)}^{9} + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.2.2

将 $x$ 乘以 $x^{4}$ 。

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解题步骤 3.14.1.15.2.2.1

对 $x$ 进行 $1$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 (x^{1} x^{4}) {(x^{2} + 1)}^{9} + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.2.2.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{1 + 4} {(x^{2} + 1)}^{9} + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.2.3

将 $1$ 和 $4$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{2} {(x^{2} + 1)}^{9} x + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.3

通过指数相加将 $x^{2}$ 乘以 $x$ 。

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解题步骤 3.14.1.15.3.1

移动 $x$ 。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 (x \cdot x^{2}) {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.3.2

将 $x$ 乘以 $x^{2}$ 。

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解题步骤 3.14.1.15.3.2.1

对 $x$ 进行 $1$ 次方运算。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 (x^{1} x^{2}) {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.3.2.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{1 + 2} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.1.15.3.3

将 $1$ 和 $2$ 相加。

$\frac{(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.2

将第一个表达式中的每一项与第二个表达式中的每一项相乘来展开 $(e^{x} + 1) (6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x)$ 。

$\frac{e^{x} (6 {(x^{2} + 1)}^{10} x^{5}) + e^{x} (24 {(x^{2} + 1)}^{10} x^{3}) + e^{x} (24 {(x^{2} + 1)}^{10} x) + e^{x} (20 x^{7} {(x^{2} + 1)}^{9}) + e^{x} (120 x^{5} {(x^{2} + 1)}^{9}) + e^{x} (240 x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3

化简每一项。

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解题步骤 3.14.3.1

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + e^{x} (24 {(x^{2} + 1)}^{10} x^{3}) + e^{x} (24 {(x^{2} + 1)}^{10} x) + e^{x} (20 x^{7} {(x^{2} + 1)}^{9}) + e^{x} (120 x^{5} {(x^{2} + 1)}^{9}) + e^{x} (240 x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.2

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + e^{x} (24 {(x^{2} + 1)}^{10} x) + e^{x} (20 x^{7} {(x^{2} + 1)}^{9}) + e^{x} (120 x^{5} {(x^{2} + 1)}^{9}) + e^{x} (240 x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.3

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + e^{x} (20 x^{7} {(x^{2} + 1)}^{9}) + e^{x} (120 x^{5} {(x^{2} + 1)}^{9}) + e^{x} (240 x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.4

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + e^{x} (120 x^{5} {(x^{2} + 1)}^{9}) + e^{x} (240 x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.5

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + e^{x} (240 x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.6

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + e^{x} (160 {(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.7

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 1 (6 {(x^{2} + 1)}^{10} x^{5}) + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.8

将 $6 {(x^{2} + 1)}^{10} x^{5}$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 1 (24 {(x^{2} + 1)}^{10} x^{3}) + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.9

将 $24 {(x^{2} + 1)}^{10} x^{3}$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 1 (24 {(x^{2} + 1)}^{10} x) + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.10

将 $24 {(x^{2} + 1)}^{10} x$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 1 (20 x^{7} {(x^{2} + 1)}^{9}) + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.11

将 $20 x^{7} {(x^{2} + 1)}^{9}$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 1 (120 x^{5} {(x^{2} + 1)}^{9}) + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.12

将 $120 x^{5} {(x^{2} + 1)}^{9}$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 1 (240 x^{3} {(x^{2} + 1)}^{9}) + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.13

将 $240 x^{3} {(x^{2} + 1)}^{9}$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 1 (160 {(x^{2} + 1)}^{9} x) - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.3.14

将 $160 {(x^{2} + 1)}^{9} x$ 乘以 $1$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} {(x^{2} + 2)}^{3} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.4

使用二项式定理。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} ({(x^{2})}^{3} + 3 {(x^{2})}^{2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5

化简每一项。

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解题步骤 3.14.5.1

将 ${(x^{2})}^{3}$ 中的指数相乘。

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解题步骤 3.14.5.1.1

运用幂法则并将指数相乘， ${(a^{m})}^{n} = a^{m n}$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{2 \cdot 3} + 3 {(x^{2})}^{2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.1.2

将 $2$ 乘以 $3$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 3 {(x^{2})}^{2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.2

将 ${(x^{2})}^{2}$ 中的指数相乘。

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解题步骤 3.14.5.2.1

运用幂法则并将指数相乘， ${(a^{m})}^{n} = a^{m n}$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 3 x^{2 \cdot 2} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.2.2

将 $2$ 乘以 $2$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 3 x^{4} \cdot 2 + 3 x^{2} \cdot 2^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.3

将 $2$ 乘以 $3$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 6 x^{4} + 3 x^{2} \cdot 2^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.4

对 $2$ 进行 $2$ 次方运算。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 6 x^{4} + 3 x^{2} \cdot 4 + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.5

将 $4$ 乘以 $3$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 6 x^{4} + 12 x^{2} + 2^{3}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.5.6

对 $2$ 进行 $3$ 次方运算。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} (x^{6} + 6 x^{4} + 12 x^{2} + 8) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.6

运用分配律。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x + (- 7 {(x^{2} + 1)}^{10} x^{6} - 7 {(x^{2} + 1)}^{10} (6 x^{4}) - 7 {(x^{2} + 1)}^{10} (12 x^{2}) - 7 {(x^{2} + 1)}^{10} \cdot 8) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.7

化简。

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解题步骤 3.14.7.1

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x + (- 7 {(x^{2} + 1)}^{10} x^{6} - 7 \cdot 6 {(x^{2} + 1)}^{10} x^{4} - 7 {(x^{2} + 1)}^{10} (12 x^{2}) - 7 {(x^{2} + 1)}^{10} \cdot 8) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.7.2

使用乘法的交换性质重写。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x + (- 7 {(x^{2} + 1)}^{10} x^{6} - 7 \cdot 6 {(x^{2} + 1)}^{10} x^{4} - 7 \cdot 12 {(x^{2} + 1)}^{10} x^{2} - 7 {(x^{2} + 1)}^{10} \cdot 8) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.7.3

将 $8$ 乘以 $- 7$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x + (- 7 {(x^{2} + 1)}^{10} x^{6} - 7 \cdot 6 {(x^{2} + 1)}^{10} x^{4} - 7 \cdot 12 {(x^{2} + 1)}^{10} x^{2} - 56 {(x^{2} + 1)}^{10}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.8

化简每一项。

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解题步骤 3.14.8.1

将 $- 7$ 乘以 $6$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x + (- 7 {(x^{2} + 1)}^{10} x^{6} - 42 {(x^{2} + 1)}^{10} x^{4} - 7 \cdot 12 {(x^{2} + 1)}^{10} x^{2} - 56 {(x^{2} + 1)}^{10}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.8.2

将 $- 7$ 乘以 $12$ 。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x + (- 7 {(x^{2} + 1)}^{10} x^{6} - 42 {(x^{2} + 1)}^{10} x^{4} - 84 {(x^{2} + 1)}^{10} x^{2} - 56 {(x^{2} + 1)}^{10}) e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.9

运用分配律。

$\frac{6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10

以因式分解的形式重写 $6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}$ 。

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解题步骤 3.14.10.1

从 $6 e^{x} ({(x^{2} + 1)}^{10} x^{5}) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

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解题步骤 3.14.10.1.1

从 $6 e^{x} ({(x^{2} + 1)}^{10} x^{5})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + 24 e^{x} ({(x^{2} + 1)}^{10} x^{3}) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.2

从 $24 e^{x} ({(x^{2} + 1)}^{10} x^{3})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + 24 e^{x} ({(x^{2} + 1)}^{10} x) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.3

从 $24 e^{x} ({(x^{2} + 1)}^{10} x)$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + 20 e^{x} (x^{7} {(x^{2} + 1)}^{9}) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.4

从 $20 e^{x} (x^{7} {(x^{2} + 1)}^{9})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + 120 e^{x} (x^{5} {(x^{2} + 1)}^{9}) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.5

从 $120 e^{x} (x^{5} {(x^{2} + 1)}^{9})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + 240 e^{x} (x^{3} {(x^{2} + 1)}^{9}) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.6

从 $240 e^{x} (x^{3} {(x^{2} + 1)}^{9})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + 160 e^{x} ({(x^{2} + 1)}^{9} x) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.7

从 $160 e^{x} ({(x^{2} + 1)}^{9} x)$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + 6 {(x^{2} + 1)}^{10} x^{5} + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.8

从 $6 {(x^{2} + 1)}^{10} x^{5}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + 24 {(x^{2} + 1)}^{10} x^{3} + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.9

从 $24 {(x^{2} + 1)}^{10} x^{3}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + 24 {(x^{2} + 1)}^{10} x + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.10

从 $24 {(x^{2} + 1)}^{10} x$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + 20 x^{7} {(x^{2} + 1)}^{9} + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.11

从 $20 x^{7} {(x^{2} + 1)}^{9}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + 120 x^{5} {(x^{2} + 1)}^{9} + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.12

从 $120 x^{5} {(x^{2} + 1)}^{9}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + 240 x^{3} {(x^{2} + 1)}^{9} + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.13

从 $240 x^{3} {(x^{2} + 1)}^{9}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + 160 {(x^{2} + 1)}^{9} x - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.14

从 $160 {(x^{2} + 1)}^{9} x$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) - 7 {(x^{2} + 1)}^{10} x^{6} e^{x} - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.15

从 $- 7 {(x^{2} + 1)}^{10} x^{6} e^{x}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) - 42 {(x^{2} + 1)}^{10} x^{4} e^{x} - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.16

从 $- 42 {(x^{2} + 1)}^{10} x^{4} e^{x}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) - 84 {(x^{2} + 1)}^{10} x^{2} e^{x} - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.17

从 $- 84 {(x^{2} + 1)}^{10} x^{2} e^{x}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) - 56 {(x^{2} + 1)}^{10} e^{x}}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.18

从 $- 56 {(x^{2} + 1)}^{10} e^{x}$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.19

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x^{3}))$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.20

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3})) + {(x^{2} + 1)}^{9} (24 e^{x} ((x^{2} + 1) x))$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.21

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x)) + {(x^{2} + 1)}^{9} (20 e^{x} (x^{7}))$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.22

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7})) + {(x^{2} + 1)}^{9} (120 e^{x} (x^{5}))$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.23

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5})) + {(x^{2} + 1)}^{9} (240 e^{x} (x^{3}))$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.24

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3})) + {(x^{2} + 1)}^{9} (160 e^{x} (x))$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.25

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x)) + {(x^{2} + 1)}^{9} (6 (x^{2} + 1) x^{5})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.26

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3}) + {(x^{2} + 1)}^{9} (24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.27

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x) + {(x^{2} + 1)}^{9} (20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.28

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.29

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7}) + {(x^{2} + 1)}^{9} (120 x^{5})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.30

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5}) + {(x^{2} + 1)}^{9} (240 x^{3})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3}) + {(x^{2} + 1)}^{9} (160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.31

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3}) + {(x^{2} + 1)}^{9} (160 x)$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.32

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x) + {(x^{2} + 1)}^{9} (- 7 (x^{2} + 1) x^{6} e^{x})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.33

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x}) + {(x^{2} + 1)}^{9} (- 42 (x^{2} + 1) x^{4} e^{x})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.34

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x}) + {(x^{2} + 1)}^{9} (- 84 (x^{2} + 1) x^{2} e^{x})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.1.35

从 ${(x^{2} + 1)}^{9} (6 e^{x} ((x^{2} + 1) x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x}) + {(x^{2} + 1)}^{9} (- 56 (x^{2} + 1) e^{x})$ 中分解出因数 ${(x^{2} + 1)}^{9}$ 。

解题步骤 3.14.10.2

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} (x^{2} x^{5} + 1 x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.3

通过指数相加将 $x^{2}$ 乘以 $x^{5}$ 。

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解题步骤 3.14.10.3.1

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} (x^{2 + 5} + 1 x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.3.2

将 $2$ 和 $5$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} (x^{7} + 1 x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.4

将 $x^{5}$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} (x^{7} + x^{5}) + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.5

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} ((x^{2} + 1) x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.6

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} (x^{2} x^{3} + 1 x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.7

通过指数相加将 $x^{2}$ 乘以 $x^{3}$ 。

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解题步骤 3.14.10.7.1

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} (x^{2 + 3} + 1 x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.7.2

将 $2$ 和 $3$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} (x^{5} + 1 x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.8

将 $x^{3}$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} (x^{5} + x^{3}) + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.9

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} ((x^{2} + 1) x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.10

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} (x^{2} x + 1 x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.11

通过指数相加将 $x^{2}$ 乘以 $x$ 。

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解题步骤 3.14.10.11.1

将 $x^{2}$ 乘以 $x$ 。

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解题步骤 3.14.10.11.1.1

对 $x$ 进行 $1$ 次方运算。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} (x^{2} x^{1} + 1 x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.11.1.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} (x^{2 + 1} + 1 x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.11.2

将 $2$ 和 $1$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} (x^{3} + 1 x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.12

将 $x$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} (x^{3} + x) + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.13

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{2} + 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.14

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + (6 x^{2} + 6 \cdot 1) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.15

将 $6$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + (6 x^{2} + 6) x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.16

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{2} x^{5} + 6 x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.17

通过指数相加将 $x^{2}$ 乘以 $x^{5}$ 。

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解题步骤 3.14.10.17.1

移动 $x^{5}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 (x^{5} x^{2}) + 6 x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.17.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{5 + 2} + 6 x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.17.3

将 $5$ 和 $2$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 (x^{2} + 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.18

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + (24 x^{2} + 24 \cdot 1) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.19

将 $24$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + (24 x^{2} + 24) x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.20

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{2} x^{3} + 24 x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.21

通过指数相加将 $x^{2}$ 乘以 $x^{3}$ 。

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解题步骤 3.14.10.21.1

移动 $x^{3}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 (x^{3} x^{2}) + 24 x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.21.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{3 + 2} + 24 x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.21.3

将 $3$ 和 $2$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 (x^{2} + 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.22

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + (24 x^{2} + 24 \cdot 1) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.23

将 $24$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + (24 x^{2} + 24) x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.24

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{2} x + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.25

通过指数相加将 $x^{2}$ 乘以 $x$ 。

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解题步骤 3.14.10.25.1

移动 $x$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 (x \cdot x^{2}) + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.25.2

将 $x$ 乘以 $x^{2}$ 。

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解题步骤 3.14.10.25.2.1

对 $x$ 进行 $1$ 次方运算。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 (x^{1} x^{2}) + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.25.2.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{1 + 2} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.25.3

将 $1$ 和 $2$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 (x^{2} + 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.26

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x + (- 7 x^{2} - 7 \cdot 1) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.27

将 $- 7$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x + (- 7 x^{2} - 7) x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.28

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x + (- 7 x^{2} x^{6} - 7 x^{6}) e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.29

通过指数相加将 $x^{2}$ 乘以 $x^{6}$ 。

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解题步骤 3.14.10.29.1

移动 $x^{6}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x + (- 7 (x^{6} x^{2}) - 7 x^{6}) e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.29.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x + (- 7 x^{6 + 2} - 7 x^{6}) e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.29.3

将 $6$ 和 $2$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x + (- 7 x^{8} - 7 x^{6}) e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.30

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 (x^{2} + 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.31

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} + (- 42 x^{2} - 42 \cdot 1) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.32

将 $- 42$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} + (- 42 x^{2} - 42) x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.33

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} + (- 42 x^{2} x^{4} - 42 x^{4}) e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.34

通过指数相加将 $x^{2}$ 乘以 $x^{4}$ 。

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解题步骤 3.14.10.34.1

移动 $x^{4}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} + (- 42 (x^{4} x^{2}) - 42 x^{4}) e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.34.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} + (- 42 x^{4 + 2} - 42 x^{4}) e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.34.3

将 $4$ 和 $2$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} + (- 42 x^{6} - 42 x^{4}) e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.35

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 (x^{2} + 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.36

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} + (- 84 x^{2} - 84 \cdot 1) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.37

将 $- 84$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} + (- 84 x^{2} - 84) x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.38

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} + (- 84 x^{2} x^{2} - 84 x^{2}) e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.39

通过指数相加将 $x^{2}$ 乘以 $x^{2}$ 。

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解题步骤 3.14.10.39.1

移动 $x^{2}$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} + (- 84 (x^{2} x^{2}) - 84 x^{2}) e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.39.2

使用幂法则 $a^{m} a^{n} = a^{m + n}$ 合并指数。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} + (- 84 x^{2 + 2} - 84 x^{2}) e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.39.3

将 $2$ 和 $2$ 相加。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} + (- 84 x^{4} - 84 x^{2}) e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.40

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 (x^{2} + 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.41

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} + (- 56 x^{2} - 56 \cdot 1) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.42

将 $- 56$ 乘以 $1$ 。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} + (- 56 x^{2} - 56) e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.43

运用分配律。

$\frac{{(x^{2} + 1)}^{9} (6 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 20 e^{x} (x^{7}) + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.44

将 $6 e^{x} x^{7}$ 和 $20 e^{x} (x^{7})$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 6 e^{x} x^{5} + 24 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.45

将 $6 e^{x} x^{5}$ 和 $24 e^{x} x^{5}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 30 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 120 e^{x} (x^{5}) + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.46

将 $30 e^{x} x^{5}$ 和 $120 e^{x} (x^{5})$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 24 e^{x} x^{3} + 24 e^{x} x^{3} + 24 e^{x} x + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.47

将 $24 e^{x} x^{3}$ 和 $24 e^{x} x^{3}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 48 e^{x} x^{3} + 24 e^{x} x + 240 e^{x} (x^{3}) + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.48

将 $48 e^{x} x^{3}$ 和 $240 e^{x} (x^{3})$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 24 e^{x} x + 160 e^{x} (x) + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.49

将 $24 e^{x} x$ 和 $160 e^{x} (x)$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 6 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 20 x^{7} + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.50

将 $6 x^{7}$ 和 $20 x^{7}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 6 x^{5} + 24 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.51

将 $6 x^{5}$ 和 $24 x^{5}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 30 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 120 x^{5} + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.52

将 $30 x^{5}$ 和 $120 x^{5}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 24 x^{3} + 24 x^{3} + 24 x + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.53

将 $24 x^{3}$ 和 $24 x^{3}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 48 x^{3} + 24 x + 240 x^{3} + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.54

将 $48 x^{3}$ 和 $240 x^{3}$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 288 x^{3} + 24 x + 160 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.55

将 $24 x$ 和 $160 x$ 相加。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 288 x^{3} + 184 x - 7 x^{8} e^{x} - 7 x^{6} e^{x} - 42 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.56

从 $- 7 x^{6} e^{x}$ 中减去 $42 x^{6} e^{x}$ 。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 288 x^{3} + 184 x - 7 x^{8} e^{x} - 49 x^{6} e^{x} - 42 x^{4} e^{x} - 84 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.57

从 $- 42 x^{4} e^{x}$ 中减去 $84 x^{4} e^{x}$ 。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 288 x^{3} + 184 x - 7 x^{8} e^{x} - 49 x^{6} e^{x} - 126 x^{4} e^{x} - 84 x^{2} e^{x} - 56 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.58

从 $- 84 x^{2} e^{x}$ 中减去 $56 x^{2} e^{x}$ 。

$\frac{{(x^{2} + 1)}^{9} (26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x + 26 x^{7} + 150 x^{5} + 288 x^{3} + 184 x - 7 x^{8} e^{x} - 49 x^{6} e^{x} - 126 x^{4} e^{x} - 140 x^{2} e^{x} - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 3.14.10.59

重新排序项。

$\frac{{(x^{2} + 1)}^{9} (26 x^{7} + 150 x^{5} + 288 x^{3} + 26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x - 7 e^{x} x^{8} - 49 e^{x} x^{6} - 126 e^{x} x^{4} - 140 e^{x} x^{2} + 184 x - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 4

通过设置方程左边等于右边来进行方程变形。

$y' = \frac{{(x^{2} + 1)}^{9} (26 x^{7} + 150 x^{5} + 288 x^{3} + 26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x - 7 e^{x} x^{8} - 49 e^{x} x^{6} - 126 e^{x} x^{4} - 140 e^{x} x^{2} + 184 x - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

解题步骤 5

使用 $\frac{d y}{d x}$ 替换 $y'$ 。

$\frac{d y}{d x} = \frac{{(x^{2} + 1)}^{9} (26 x^{7} + 150 x^{5} + 288 x^{3} + 26 e^{x} x^{7} + 150 e^{x} x^{5} + 288 e^{x} x^{3} + 184 e^{x} x - 7 e^{x} x^{8} - 49 e^{x} x^{6} - 126 e^{x} x^{4} - 140 e^{x} x^{2} + 184 x - 56 e^{x})}{{(e^{x} + 1)}^{8}}$

微积分学 示例

微积分学示例