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热门问题
代数
求出最小公倍数(LCM) 16
16
16
解题步骤 1
最小公倍数是能被所有数整除的最小正数。
1. 列出每个数的质因数。
2. 将每个因数乘以它在任一数字中出现的最大次数。
解题步骤 2
16
16
的质因数是
2
⋅
2
⋅
2
⋅
2
2
⋅
2
⋅
2
⋅
2
。
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解题步骤 2.1
16
16
具有因式
2
2
和
8
8
。
2
⋅
8
2
⋅
8
解题步骤 2.2
8
8
具有因式
2
2
和
4
4
。
2
⋅
2
⋅
4
2
⋅
2
⋅
4
解题步骤 2.3
4
4
具有因式
2
2
和
2
2
。
2
⋅
2
⋅
2
⋅
2
2
⋅
2
⋅
2
⋅
2
2
⋅
2
⋅
2
⋅
2
2
⋅
2
⋅
2
⋅
2
解题步骤 3
乘以
2
⋅
2
⋅
2
⋅
2
2
⋅
2
⋅
2
⋅
2
。
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解题步骤 3.1
将
2
2
乘以
2
2
。
4
⋅
2
⋅
2
4
⋅
2
⋅
2
解题步骤 3.2
将
4
4
乘以
2
2
。
8
⋅
2
8
⋅
2
解题步骤 3.3
将
8
8
乘以
2
2
。
16
16
16
16
1
6
1
6
(
(
)
)
|
|
[
[
]
]
√
√
≥
≥
7
7
8
8
9
9
≤
≤
4
4
5
5
6
6
/
/
^
^
×
×
>
>
∩
∩
∪
∪
1
1
2
2
3
3
-
-
+
+
÷
÷
<
<
π
π
∞
∞
,
,
0
0
.
.
%
%
=
=
⎡
⎢
⎣
x
2
1
2
√
π
∫
x
d
x
⎤
⎥
⎦
[
x
2
1
2
π
∫
x
d
x
]
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