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$x + y = - 2$ , $x - y = 11$

Bước 1

Write the system as a matrix.

$[\begin{array}{c} 1 & 1 & - 2 \\ 1 & - 1 & 11 \end{array}]$

Bước 2

Tìm dạng ma trận hàng bậc thang rút gọn.

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Bước 2.1

Perform the row operation $R_{2} = R_{2} - R_{1}$ to make the entry at $2, 1$ a $0$ .

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Bước 2.1.1

Perform the row operation $R_{2} = R_{2} - R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 1 & - 2 \\ 1 - 1 & - 1 - 1 & 11 + 2 \end{array}]$

Bước 2.1.2

Rút gọn $R_{2}$ .

$[\begin{array}{c} 1 & 1 & - 2 \\ 0 & - 2 & 13 \end{array}]$

Bước 2.2

Multiply each element of $R_{2}$ by $- \frac{1}{2}$ to make the entry at $2, 2$ a $1$ .

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Bước 2.2.1

Multiply each element of $R_{2}$ by $- \frac{1}{2}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 1 & - 2 \\ - \frac{1}{2} \cdot 0 & - \frac{1}{2} \cdot - 2 & - \frac{1}{2} \cdot 13 \end{array}]$

Bước 2.2.2

Rút gọn $R_{2}$ .

$[\begin{array}{c} 1 & 1 & - 2 \\ 0 & 1 & - \frac{13}{2} \end{array}]$

Bước 2.3

Perform the row operation $R_{1} = R_{1} - R_{2}$ to make the entry at $1, 2$ a $0$ .

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Bước 2.3.1

Perform the row operation $R_{1} = R_{1} - R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 0 & 1 - 1 & - 2 + \frac{13}{2} \\ 0 & 1 & - \frac{13}{2} \end{array}]$

Bước 2.3.2

Rút gọn $R_{1}$ .

$[\begin{array}{c} 1 & 0 & \frac{9}{2} \\ 0 & 1 & - \frac{13}{2} \end{array}]$

Bước 3

Use the result matrix to declare the final solution to the system of equations.

$x = \frac{9}{2}$

$y = - \frac{13}{2}$

Bước 4

The solution is the set of ordered pairs that make the system true.

$(\frac{9}{2}, - \frac{13}{2})$