Matemática discreta Exemplos

$[\begin{array}{c} a + 6 & 5 z + 1 & 2 m \\ 2 k & 0 & 0 \end{array}] + [\begin{array}{c} 12 a & 8 x & 6 m \\ 2 k & 0 & 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 1

Adicione os elementos correspondentes.

$[\begin{array}{c} a + 6 + 12 a & 5 z + 1 + 8 x & 2 m + 6 m \\ 2 k + 2 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 2

Simplify each element.

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Etapa 2.1

Some $a$ e $12 a$ .

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 2 m + 6 m \\ 2 k + 2 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 2.2

Some $2 m$ e $6 m$ .

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 2 k + 2 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 2.3

Some $2 k$ e $2 k$ .

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 4 k & 0 + 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 2.4

Some $0$ e $0$ .

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 4 k & 0 & 0 + 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 2.5

Some $0$ e $0$ .

$[\begin{array}{c} 13 a + 6 & 5 z + 1 + 8 x & 8 m \\ 4 k & 0 & 0 \end{array}] = [\begin{array}{c} 58 & - 38 & 24 \\ 12 & 0 & 0 \end{array}]$

Etapa 3

Write as a linear system of equations.

$13 a + 6 = 58$

$5 z + 1 + 8 x = - 38$

$8 m = 24$

$4 k = 12$

$0 = 0$

Etapa 4

Since $0 = 0$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.