Trigonometry Examples

$9 \cos (t) - \sqrt{3} = 7 \cos (t)$

Step 1

Move all terms containing $\cos (t)$ to the left side of the equation.

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Step 1.1

Subtract $7 \cos (t)$ from both sides of the equation.

$9 \cos (t) - \sqrt{3} - 7 \cos (t) = 0$

Step 1.2

Subtract $7 \cos (t)$ from $9 \cos (t)$ .

$2 \cos (t) - \sqrt{3} = 0$

Step 2

Add $\sqrt{3}$ to both sides of the equation.

$2 \cos (t) = \sqrt{3}$

Step 3

Divide each term in $2 \cos (t) = \sqrt{3}$ by $2$ and simplify.

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Step 3.1

Divide each term in $2 \cos (t) = \sqrt{3}$ by $2$ .

$\frac{2 \cos (t)}{2} = \frac{\sqrt{3}}{2}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $2$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{2 \cos (t)}{2} = \frac{\sqrt{3}}{2}$

Step 3.2.1.2

Divide $\cos (t)$ by $1$ .

$\cos (t) = \frac{\sqrt{3}}{2}$

Step 4

Take the inverse cosine of both sides of the equation to extract $t$ from inside the cosine.

$t = \arccos (\frac{\sqrt{3}}{2})$

Step 5

Simplify the right side.

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Step 5.1

The exact value of $\arccos (\frac{\sqrt{3}}{2})$ is $\frac{π}{6}$ .

$t = \frac{π}{6}$

Step 6

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$t = 2 π - \frac{π}{6}$

Step 7

Simplify $2 π - \frac{π}{6}$ .

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Step 7.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{6}{6}$ .

$t = 2 π \cdot \frac{6}{6} - \frac{π}{6}$

Step 7.2

Combine fractions.

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Step 7.2.1

Combine $2 π$ and $\frac{6}{6}$ .

$t = \frac{2 π \cdot 6}{6} - \frac{π}{6}$

Step 7.2.2

Combine the numerators over the common denominator.

$t = \frac{2 π \cdot 6 - π}{6}$

Step 7.3

Simplify the numerator.

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Step 7.3.1

Multiply $6$ by $2$ .

$t = \frac{12 π - π}{6}$

Step 7.3.2

Subtract $π$ from $12 π$ .

$t = \frac{11 π}{6}$

Step 8

Find the period of $\cos (t)$ .

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Step 8.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 8.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 8.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 8.4

Divide $2 π$ by $1$ .

$2 π$

Step 9

The period of the $\cos (t)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$t = \frac{π}{6} + 2 π n, \frac{11 π}{6} + 2 π n$ , for any integer $n$