Enter a problem...
Trigonometry Examples
A=30° , a=13 , b=26
Step 1
The Law of Sines produces an ambiguous angle result. This means that there are 2 angles that will correctly solve the equation. For the first triangle, use the first possible angle value.
Solve for the first triangle.
Step 2
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 3
Substitute the known values into the law of sines to find B.
sin(B)26=sin(30°)13
Step 4
Step 4.1
Multiply both sides of the equation by 26.
26sin(B)26=26sin(30°)13
Step 4.2
Simplify both sides of the equation.
Step 4.2.1
Simplify the left side.
Step 4.2.1.1
Cancel the common factor of 26.
Step 4.2.1.1.1
Cancel the common factor.
26sin(B)26=26sin(30°)13
Step 4.2.1.1.2
Rewrite the expression.
sin(B)=26sin(30°)13
sin(B)=26sin(30°)13
sin(B)=26sin(30°)13
Step 4.2.2
Simplify the right side.
Step 4.2.2.1
Simplify 26sin(30°)13.
Step 4.2.2.1.1
Cancel the common factor of 13.
Step 4.2.2.1.1.1
Factor 13 out of 26.
sin(B)=13(2)sin(30°)13
Step 4.2.2.1.1.2
Cancel the common factor.
sin(B)=13⋅2sin(30°)13
Step 4.2.2.1.1.3
Rewrite the expression.
sin(B)=2sin(30°)
sin(B)=2sin(30°)
Step 4.2.2.1.2
The exact value of sin(30°) is 12.
sin(B)=2(12)
Step 4.2.2.1.3
Cancel the common factor of 2.
Step 4.2.2.1.3.1
Cancel the common factor.
sin(B)=2(12)
Step 4.2.2.1.3.2
Rewrite the expression.
sin(B)=1
sin(B)=1
sin(B)=1
sin(B)=1
sin(B)=1
Step 4.3
Take the inverse sine of both sides of the equation to extract B from inside the sine.
B=arcsin(1)
Step 4.4
Simplify the right side.
Step 4.4.1
The exact value of arcsin(1) is 90.
B=90
B=90
Step 4.5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from 180 to find the solution in the second quadrant.
B=180-90
Step 4.6
Subtract 90 from 180.
B=90
Step 4.7
The solution to the equation B=90.
B=90,90
B=90,90
Step 5
The sum of all the angles in a triangle is 180 degrees.
30°+C+90=180
Step 6
Step 6.1
Add 30° and 90.
C+120=180
Step 6.2
Move all terms not containing C to the right side of the equation.
Step 6.2.1
Subtract 120 from both sides of the equation.
C=180-120
Step 6.2.2
Subtract 120 from 180.
C=60
C=60
C=60
Step 7
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 8
Substitute the known values into the law of sines to find c.
sin(60)c=sin(30°)13
Step 9
Step 9.1
Factor each term.
Step 9.1.1
The exact value of sin(60) is √32.
√32c=sin(30°)13
Step 9.1.2
Multiply the numerator by the reciprocal of the denominator.
√32⋅1c=sin(30°)13
Step 9.1.3
Multiply √32 by 1c.
√32c=sin(30°)13
Step 9.1.4
The exact value of sin(30°) is 12.
√32c=1213
Step 9.1.5
Multiply the numerator by the reciprocal of the denominator.
√32c=12⋅113
Step 9.1.6
Multiply 12⋅113.
Step 9.1.6.1
Multiply 12 by 113.
√32c=12⋅13
Step 9.1.6.2
Multiply 2 by 13.
√32c=126
√32c=126
√32c=126
Step 9.2
Find the LCD of the terms in the equation.
Step 9.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
2c,26
Step 9.2.2
Since 2c,26 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 2,26 then find LCM for the variable part c1.
Step 9.2.3
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 9.2.4
Since 2 has no factors besides 1 and 2.
2 is a prime number
Step 9.2.5
26 has factors of 2 and 13.
2⋅13
Step 9.2.6
Multiply 2 by 13.
26
Step 9.2.7
The factor for c1 is c itself.
c1=c
c occurs 1 time.
Step 9.2.8
The LCM of c1 is the result of multiplying all prime factors the greatest number of times they occur in either term.
c
Step 9.2.9
The LCM for 2c,26 is the numeric part 26 multiplied by the variable part.
26c
26c
Step 9.3
Multiply each term in √32c=126 by 26c to eliminate the fractions.
Step 9.3.1
Multiply each term in √32c=126 by 26c.
√32c(26c)=126(26c)
Step 9.3.2
Simplify the left side.
Step 9.3.2.1
Rewrite using the commutative property of multiplication.
26√32cc=126(26c)
Step 9.3.2.2
Cancel the common factor of 2.
Step 9.3.2.2.1
Factor 2 out of 26.
2(13)√32cc=126(26c)
Step 9.3.2.2.2
Factor 2 out of 2c.
2(13)√32(c)c=126(26c)
Step 9.3.2.2.3
Cancel the common factor.
2⋅13√32cc=126(26c)
Step 9.3.2.2.4
Rewrite the expression.
13√3cc=126(26c)
13√3cc=126(26c)
Step 9.3.2.3
Combine 13 and √3c.
13√3cc=126(26c)
Step 9.3.2.4
Cancel the common factor of c.
Step 9.3.2.4.1
Cancel the common factor.
13√3cc=126(26c)
Step 9.3.2.4.2
Rewrite the expression.
13√3=126(26c)
13√3=126(26c)
13√3=126(26c)
Step 9.3.3
Simplify the right side.
Step 9.3.3.1
Cancel the common factor of 26.
Step 9.3.3.1.1
Factor 26 out of 26c.
13√3=126(26(c))
Step 9.3.3.1.2
Cancel the common factor.
13√3=126(26c)
Step 9.3.3.1.3
Rewrite the expression.
13√3=c
13√3=c
13√3=c
13√3=c
Step 9.4
Rewrite the equation as c=13√3.
c=13√3
c=13√3
Step 10
For the second triangle, use the second possible angle value.
Solve for the second triangle.
Step 11
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 12
Substitute the known values into the law of sines to find B.
sin(B)26=sin(30°)13
Step 13
Step 13.1
Multiply both sides of the equation by 26.
26sin(B)26=26sin(30°)13
Step 13.2
Simplify both sides of the equation.
Step 13.2.1
Simplify the left side.
Step 13.2.1.1
Cancel the common factor of 26.
Step 13.2.1.1.1
Cancel the common factor.
26sin(B)26=26sin(30°)13
Step 13.2.1.1.2
Rewrite the expression.
sin(B)=26sin(30°)13
sin(B)=26sin(30°)13
sin(B)=26sin(30°)13
Step 13.2.2
Simplify the right side.
Step 13.2.2.1
Simplify 26sin(30°)13.
Step 13.2.2.1.1
Cancel the common factor of 13.
Step 13.2.2.1.1.1
Factor 13 out of 26.
sin(B)=13(2)sin(30°)13
Step 13.2.2.1.1.2
Cancel the common factor.
sin(B)=13⋅2sin(30°)13
Step 13.2.2.1.1.3
Rewrite the expression.
sin(B)=2sin(30°)
sin(B)=2sin(30°)
Step 13.2.2.1.2
The exact value of sin(30°) is 12.
sin(B)=2(12)
Step 13.2.2.1.3
Cancel the common factor of 2.
Step 13.2.2.1.3.1
Cancel the common factor.
sin(B)=2(12)
Step 13.2.2.1.3.2
Rewrite the expression.
sin(B)=1
sin(B)=1
sin(B)=1
sin(B)=1
sin(B)=1
Step 13.3
Take the inverse sine of both sides of the equation to extract B from inside the sine.
B=arcsin(1)
Step 13.4
Simplify the right side.
Step 13.4.1
The exact value of arcsin(1) is 90.
B=90
B=90
Step 13.5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from 180 to find the solution in the second quadrant.
B=180-90
Step 13.6
Subtract 90 from 180.
B=90
Step 13.7
The solution to the equation B=90.
B=90,90
B=90,90
Step 14
The sum of all the angles in a triangle is 180 degrees.
30°+C+90=180
Step 15
Step 15.1
Add 30° and 90.
C+120=180
Step 15.2
Move all terms not containing C to the right side of the equation.
Step 15.2.1
Subtract 120 from both sides of the equation.
C=180-120
Step 15.2.2
Subtract 120 from 180.
C=60
C=60
C=60
Step 16
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 17
Substitute the known values into the law of sines to find c.
sin(60)c=sin(30°)13
Step 18
Step 18.1
Factor each term.
Step 18.1.1
The exact value of sin(60) is √32.
√32c=sin(30°)13
Step 18.1.2
Multiply the numerator by the reciprocal of the denominator.
√32⋅1c=sin(30°)13
Step 18.1.3
Multiply √32 by 1c.
√32c=sin(30°)13
Step 18.1.4
The exact value of sin(30°) is 12.
√32c=1213
Step 18.1.5
Multiply the numerator by the reciprocal of the denominator.
√32c=12⋅113
Step 18.1.6
Multiply 12⋅113.
Step 18.1.6.1
Multiply 12 by 113.
√32c=12⋅13
Step 18.1.6.2
Multiply 2 by 13.
√32c=126
√32c=126
√32c=126
Step 18.2
Find the LCD of the terms in the equation.
Step 18.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
2c,26
Step 18.2.2
Since 2c,26 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 2,26 then find LCM for the variable part c1.
Step 18.2.3
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 18.2.4
Since 2 has no factors besides 1 and 2.
2 is a prime number
Step 18.2.5
26 has factors of 2 and 13.
2⋅13
Step 18.2.6
Multiply 2 by 13.
26
Step 18.2.7
The factor for c1 is c itself.
c1=c
c occurs 1 time.
Step 18.2.8
The LCM of c1 is the result of multiplying all prime factors the greatest number of times they occur in either term.
c
Step 18.2.9
The LCM for 2c,26 is the numeric part 26 multiplied by the variable part.
26c
26c
Step 18.3
Multiply each term in √32c=126 by 26c to eliminate the fractions.
Step 18.3.1
Multiply each term in √32c=126 by 26c.
√32c(26c)=126(26c)
Step 18.3.2
Simplify the left side.
Step 18.3.2.1
Rewrite using the commutative property of multiplication.
26√32cc=126(26c)
Step 18.3.2.2
Cancel the common factor of 2.
Step 18.3.2.2.1
Factor 2 out of 26.
2(13)√32cc=126(26c)
Step 18.3.2.2.2
Factor 2 out of 2c.
2(13)√32(c)c=126(26c)
Step 18.3.2.2.3
Cancel the common factor.
2⋅13√32cc=126(26c)
Step 18.3.2.2.4
Rewrite the expression.
13√3cc=126(26c)
13√3cc=126(26c)
Step 18.3.2.3
Combine 13 and √3c.
13√3cc=126(26c)
Step 18.3.2.4
Cancel the common factor of c.
Step 18.3.2.4.1
Cancel the common factor.
13√3cc=126(26c)
Step 18.3.2.4.2
Rewrite the expression.
13√3=126(26c)
13√3=126(26c)
13√3=126(26c)
Step 18.3.3
Simplify the right side.
Step 18.3.3.1
Cancel the common factor of 26.
Step 18.3.3.1.1
Factor 26 out of 26c.
13√3=126(26(c))
Step 18.3.3.1.2
Cancel the common factor.
13√3=126(26c)
Step 18.3.3.1.3
Rewrite the expression.
13√3=c
13√3=c
13√3=c
13√3=c
Step 18.4
Rewrite the equation as c=13√3.
c=13√3
c=13√3
Step 19
These are the results for all angles and sides for the given triangle.
First Triangle Combination:
A=30°
B=90
C=60
a=13
b=26
c=13√3
Second Triangle Combination:
A=30°
B=90
C=60
a=13
b=26
c=13√3