Trigonometry Examples

$f (x) = 8 \cos^{2} (x) - 6$

Step 1

Set $8 \cos^{2} (x) - 6$ equal to $0$ .

$8 \cos^{2} (x) - 6 = 0$

Step 2

Solve for $x$ .

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Step 2.1

Add $6$ to both sides of the equation.

$8 \cos^{2} (x) = 6$

Step 2.2

Divide each term in $8 \cos^{2} (x) = 6$ by $8$ and simplify.

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Step 2.2.1

Divide each term in $8 \cos^{2} (x) = 6$ by $8$ .

$\frac{8 \cos^{2} (x)}{8} = \frac{6}{8}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of $8$ .

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Step 2.2.2.1.1

Cancel the common factor.

$\frac{8 \cos^{2} (x)}{8} = \frac{6}{8}$

Step 2.2.2.1.2

Divide $\cos^{2} (x)$ by $1$ .

$\cos^{2} (x) = \frac{6}{8}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Cancel the common factor of $6$ and $8$ .

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Step 2.2.3.1.1

Factor $2$ out of $6$ .

$\cos^{2} (x) = \frac{2 (3)}{8}$

Step 2.2.3.1.2

Cancel the common factors.

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Step 2.2.3.1.2.1

Factor $2$ out of $8$ .

$\cos^{2} (x) = \frac{2 \cdot 3}{2 \cdot 4}$

Step 2.2.3.1.2.2

Cancel the common factor.

$\cos^{2} (x) = \frac{2 \cdot 3}{2 \cdot 4}$

Step 2.2.3.1.2.3

Rewrite the expression.

$\cos^{2} (x) = \frac{3}{4}$

Step 2.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$\cos (x) = \pm \sqrt{\frac{3}{4}}$

Step 2.4

Simplify $\pm \sqrt{\frac{3}{4}}$ .

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Step 2.4.1

Rewrite $\sqrt{\frac{3}{4}}$ as $\frac{\sqrt{3}}{\sqrt{4}}$ .

$\cos (x) = \pm \frac{\sqrt{3}}{\sqrt{4}}$

Step 2.4.2

Simplify the denominator.

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Step 2.4.2.1

Rewrite $4$ as $2^{2}$ .

$\cos (x) = \pm \frac{\sqrt{3}}{\sqrt{2^{2}}}$

Step 2.4.2.2

Pull terms out from under the radical, assuming positive real numbers.

$\cos (x) = \pm \frac{\sqrt{3}}{2}$

Step 2.5

The complete solution is the result of both the positive and negative portions of the solution.

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Step 2.5.1

First, use the positive value of the $\pm$ to find the first solution.

$\cos (x) = \frac{\sqrt{3}}{2}$

Step 2.5.2

Next, use the negative value of the $\pm$ to find the second solution.

$\cos (x) = - \frac{\sqrt{3}}{2}$

Step 2.5.3

The complete solution is the result of both the positive and negative portions of the solution.

$\cos (x) = \frac{\sqrt{3}}{2}, - \frac{\sqrt{3}}{2}$

Step 2.6

Set up each of the solutions to solve for $x$ .

$\cos (x) = \frac{\sqrt{3}}{2}$

$\cos (x) = - \frac{\sqrt{3}}{2}$

Step 2.7

Solve for $x$ in $\cos (x) = \frac{\sqrt{3}}{2}$ .

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Step 2.7.1

Take the inverse cosine of both sides of the equation to extract $x$ from inside the cosine.

$x = \arccos (\frac{\sqrt{3}}{2})$

Step 2.7.2

Simplify the right side.

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Step 2.7.2.1

The exact value of $\arccos (\frac{\sqrt{3}}{2})$ is $\frac{π}{6}$ .

$x = \frac{π}{6}$

Step 2.7.3

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$x = 2 π - \frac{π}{6}$

Step 2.7.4

Simplify $2 π - \frac{π}{6}$ .

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Step 2.7.4.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{6}{6}$ .

$x = 2 π \cdot \frac{6}{6} - \frac{π}{6}$

Step 2.7.4.2

Combine fractions.

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Step 2.7.4.2.1

Combine $2 π$ and $\frac{6}{6}$ .

$x = \frac{2 π \cdot 6}{6} - \frac{π}{6}$

Step 2.7.4.2.2

Combine the numerators over the common denominator.

$x = \frac{2 π \cdot 6 - π}{6}$

Step 2.7.4.3

Simplify the numerator.

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Step 2.7.4.3.1

Multiply $6$ by $2$ .

$x = \frac{12 π - π}{6}$

Step 2.7.4.3.2

Subtract $π$ from $12 π$ .

$x = \frac{11 π}{6}$

Step 2.7.5

Find the period of $\cos (x)$ .

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Step 2.7.5.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 2.7.5.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 2.7.5.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 2.7.5.4

Divide $2 π$ by $1$ .

$2 π$

Step 2.7.6

The period of the $\cos (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{π}{6} + 2 π n, \frac{11 π}{6} + 2 π n$ , for any integer $n$

Step 2.8

Solve for $x$ in $\cos (x) = - \frac{\sqrt{3}}{2}$ .

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Step 2.8.1

Take the inverse cosine of both sides of the equation to extract $x$ from inside the cosine.

$x = \arccos (- \frac{\sqrt{3}}{2})$

Step 2.8.2

Simplify the right side.

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Step 2.8.2.1

The exact value of $\arccos (- \frac{\sqrt{3}}{2})$ is $\frac{5 π}{6}$ .

$x = \frac{5 π}{6}$

Step 2.8.3

The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the third quadrant.

$x = 2 π - \frac{5 π}{6}$

Step 2.8.4

Simplify $2 π - \frac{5 π}{6}$ .

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Step 2.8.4.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{6}{6}$ .

$x = 2 π \cdot \frac{6}{6} - \frac{5 π}{6}$

Step 2.8.4.2

Combine fractions.

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Step 2.8.4.2.1

Combine $2 π$ and $\frac{6}{6}$ .

$x = \frac{2 π \cdot 6}{6} - \frac{5 π}{6}$

Step 2.8.4.2.2

Combine the numerators over the common denominator.

$x = \frac{2 π \cdot 6 - 5 π}{6}$

Step 2.8.4.3

Simplify the numerator.

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Step 2.8.4.3.1

Multiply $6$ by $2$ .

$x = \frac{12 π - 5 π}{6}$

Step 2.8.4.3.2

Subtract $5 π$ from $12 π$ .

$x = \frac{7 π}{6}$

Step 2.8.5

Find the period of $\cos (x)$ .

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Step 2.8.5.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 2.8.5.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 2.8.5.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 2.8.5.4

Divide $2 π$ by $1$ .

$2 π$

Step 2.8.6

The period of the $\cos (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{5 π}{6} + 2 π n, \frac{7 π}{6} + 2 π n$ , for any integer $n$

Step 2.9

List all of the solutions.

$x = \frac{π}{6} + 2 π n, \frac{11 π}{6} + 2 π n, \frac{5 π}{6} + 2 π n, \frac{7 π}{6} + 2 π n$ , for any integer $n$

Step 2.10

Consolidate the solutions.

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Step 2.10.1

Consolidate $\frac{π}{6} + 2 π n$ and $\frac{7 π}{6} + 2 π n$ to $\frac{π}{6} + π n$ .

$x = \frac{π}{6} + π n, \frac{11 π}{6} + 2 π n, \frac{5 π}{6} + 2 π n$ , for any integer $n$

Step 2.10.2

Consolidate $\frac{11 π}{6} + 2 π n$ and $\frac{5 π}{6} + 2 π n$ to $\frac{5 π}{6} + π n$ .

$x = \frac{π}{6} + π n, \frac{5 π}{6} + π n$ , for any integer $n$

Step 3