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Trigonometry Examples
SideAngleb=4c=a=3A=B=C=90°SideAngleb=4c=a=3A=B=C=90°
Step 1
Use the law of cosines to find the unknown side of the triangle, given the other two sides and the included angle.
c2=a2+b2-2abcos(C)c2=a2+b2−2abcos(C)
Step 2
Solve the equation.
c=√a2+b2-2abcos(C)c=√a2+b2−2abcos(C)
Step 3
Substitute the known values into the equation.
c=√(3)2+(4)2-2⋅3⋅4cos(90°)c=√(3)2+(4)2−2⋅3⋅4cos(90°)
Step 4
Step 4.1
Raise 33 to the power of 22.
c=√9+(4)2-2⋅3⋅(4cos(90°))c=√9+(4)2−2⋅3⋅(4cos(90°))
Step 4.2
Raise 44 to the power of 22.
c=√9+16-2⋅3⋅(4cos(90°))c=√9+16−2⋅3⋅(4cos(90°))
Step 4.3
Multiply -2⋅3⋅4−2⋅3⋅4.
Step 4.3.1
Multiply -2−2 by 33.
c=√9+16-6⋅(4cos(90°))c=√9+16−6⋅(4cos(90°))
Step 4.3.2
Multiply -6−6 by 44.
c=√9+16-24cos(90°)c=√9+16−24cos(90°)
c=√9+16-24cos(90°)c=√9+16−24cos(90°)
Step 4.4
The exact value of cos(90°)cos(90°) is 00.
c=√9+16-24⋅0c=√9+16−24⋅0
Step 4.5
Multiply -24−24 by 00.
c=√9+16+0c=√9+16+0
Step 4.6
Add 9+169+16 and 00.
c=√9+16c=√9+16
Step 4.7
Add 99 and 1616.
c=√25c=√25
Step 4.8
Rewrite 2525 as 5252.
c=√52c=√52
Step 4.9
Pull terms out from under the radical, assuming positive real numbers.
c=5c=5
c=5c=5
Step 5
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)csin(A)a=sin(B)b=sin(C)c
Step 6
Substitute the known values into the law of sines to find AA.
sin(A)3=sin(90°)5sin(A)3=sin(90°)5
Step 7
Step 7.1
Multiply both sides of the equation by 33.
3sin(A)3=3sin(90°)53sin(A)3=3sin(90°)5
Step 7.2
Simplify both sides of the equation.
Step 7.2.1
Simplify the left side.
Step 7.2.1.1
Cancel the common factor of 33.
Step 7.2.1.1.1
Cancel the common factor.
3sin(A)3=3sin(90°)5
Step 7.2.1.1.2
Rewrite the expression.
sin(A)=3sin(90°)5
sin(A)=3sin(90°)5
sin(A)=3sin(90°)5
Step 7.2.2
Simplify the right side.
Step 7.2.2.1
Simplify 3sin(90°)5.
Step 7.2.2.1.1
The exact value of sin(90°) is 1.
sin(A)=3(15)
Step 7.2.2.1.2
Combine 3 and 15.
sin(A)=35
sin(A)=35
sin(A)=35
sin(A)=35
Step 7.3
Take the inverse sine of both sides of the equation to extract A from inside the sine.
A=arcsin(35)
Step 7.4
Simplify the right side.
Step 7.4.1
Evaluate arcsin(35).
A=36.86989764
A=36.86989764
Step 7.5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from 180 to find the solution in the second quadrant.
A=180-36.86989764
Step 7.6
Subtract 36.86989764 from 180.
A=143.13010235
Step 7.7
The solution to the equation A=36.86989764.
A=36.86989764,143.13010235
Step 7.8
Exclude the invalid angle.
A=36.86989764
A=36.86989764
Step 8
The sum of all the angles in a triangle is 180 degrees.
36.86989764+90°+B=180
Step 9
Step 9.1
Add 36.86989764 and 90°.
126.86989764+B=180
Step 9.2
Move all terms not containing B to the right side of the equation.
Step 9.2.1
Subtract 126.86989764 from both sides of the equation.
B=180-126.86989764
Step 9.2.2
Subtract 126.86989764 from 180.
B=53.13010235
B=53.13010235
B=53.13010235
Step 10
These are the results for all angles and sides for the given triangle.
A=36.86989764
B=53.13010235
C=90°
a=3
b=4
c=5