Trigonometry Examples

Solve for b pi/2=(2pi)/b
π2=2πbπ2=2πb
Step 1
Rewrite the equation as 2πb=π22πb=π2.
2πb=π22πb=π2
Step 2
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
2π2=bπ2π2=bπ
Step 3
Solve the equation for bb.
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Step 3.1
Rewrite the equation as bπ=2π2bπ=2π2.
bπ=2π2bπ=2π2
Step 3.2
Multiply 22 by 22.
bπ=4πbπ=4π
Step 3.3
Divide each term in bπ=4πbπ=4π by ππ and simplify.
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Step 3.3.1
Divide each term in bπ=4πbπ=4π by ππ.
bππ=4ππbππ=4ππ
Step 3.3.2
Simplify the left side.
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Step 3.3.2.1
Cancel the common factor of ππ.
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Step 3.3.2.1.1
Cancel the common factor.
bππ=4ππ
Step 3.3.2.1.2
Divide b by 1.
b=4ππ
b=4ππ
b=4ππ
Step 3.3.3
Simplify the right side.
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Step 3.3.3.1
Cancel the common factor of π.
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Step 3.3.3.1.1
Cancel the common factor.
b=4ππ
Step 3.3.3.1.2
Divide 4 by 1.
b=4
b=4
b=4
b=4
b=4
Enter a problem...
 [x2  12  π  xdx ]