Trigonometry Examples

$\frac{9}{(\sqrt[3]{4}) + 7}$

Step 1

Multiply $\frac{9}{\sqrt[3]{4} + 7}$ by $\frac{{\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2}}{{\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2}}$ .

$\frac{9}{\sqrt[3]{4} + 7} \cdot \frac{{\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2}}{{\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2}}$

Step 2

Combine fractions.

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Step 2.1

Multiply $\frac{9}{\sqrt[3]{4} + 7}$ by $\frac{{\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2}}{{\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2}}$ .

$\frac{9 ({\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2})}{(\sqrt[3]{4} + 7) ({\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2})}$

Step 2.2

Expand the denominator using the FOIL method.

$\frac{9 ({\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2})}{{\sqrt[3]{4}}^{3} - 7 {\sqrt[3]{4}}^{2} + \sqrt[3]{4} \cdot 7^{2} + 7 {\sqrt[3]{4}}^{2} - 49 \sqrt[3]{4} + 7^{3}}$

Step 2.3

Simplify.

$\frac{9 ({\sqrt[3]{4}}^{2} - \sqrt[3]{4} \cdot 7 + 7^{2})}{347}$

Step 3

Simplify the numerator.

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Step 3.1

Rewrite ${\sqrt[3]{4}}^{2}$ as $\sqrt[3]{4^{2}}$ .

$\frac{9 (\sqrt[3]{4^{2}} - \sqrt[3]{4} \cdot 7 + 7^{2})}{347}$

Step 3.2

Raise $4$ to the power of $2$ .

$\frac{9 (\sqrt[3]{16} - \sqrt[3]{4} \cdot 7 + 7^{2})}{347}$

Step 3.3

Rewrite $16$ as $2^{3} \cdot 2$ .

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Step 3.3.1

Factor $8$ out of $16$ .

$\frac{9 (\sqrt[3]{8 (2)} - \sqrt[3]{4} \cdot 7 + 7^{2})}{347}$

Step 3.3.2

Rewrite $8$ as $2^{3}$ .

$\frac{9 (\sqrt[3]{2^{3} \cdot 2} - \sqrt[3]{4} \cdot 7 + 7^{2})}{347}$

Step 3.4

Pull terms out from under the radical.

$\frac{9 (2 \sqrt[3]{2} - \sqrt[3]{4} \cdot 7 + 7^{2})}{347}$

Step 3.5

Multiply $7$ by $- 1$ .

$\frac{9 (2 \sqrt[3]{2} - 7 \sqrt[3]{4} + 7^{2})}{347}$

Step 3.6

Raise $7$ to the power of $2$ .

$\frac{9 (2 \sqrt[3]{2} - 7 \sqrt[3]{4} + 49)}{347}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$\frac{9 (2 \sqrt[3]{2} - 7 \sqrt[3]{4} + 49)}{347}$

Decimal Form:

$1.04804701 \dots$