Trigonometry Examples

$\cos (2 θ) = \frac{1}{2}$

Step 1

Take the inverse cosine of both sides of the equation to extract $θ$ from inside the cosine.

$2 θ = \arccos (\frac{1}{2})$

Step 2

Simplify the right side.

Tap for more steps...

Step 2.1

The exact value of $\arccos (\frac{1}{2})$ is $\frac{π}{3}$ .

$2 θ = \frac{π}{3}$

Step 3

Divide each term in $2 θ = \frac{π}{3}$ by $2$ and simplify.

Tap for more steps...

Step 3.1

Divide each term in $2 θ = \frac{π}{3}$ by $2$ .

$\frac{2 θ}{2} = \frac{\frac{π}{3}}{2}$

Step 3.2

Simplify the left side.

Tap for more steps...

Step 3.2.1

Cancel the common factor of $2$ .

Tap for more steps...

Step 3.2.1.1

Cancel the common factor.

$\frac{2 θ}{2} = \frac{\frac{π}{3}}{2}$

Step 3.2.1.2

Divide $θ$ by $1$ .

$θ = \frac{\frac{π}{3}}{2}$

Step 3.3

Simplify the right side.

Tap for more steps...

Step 3.3.1

Multiply the numerator by the reciprocal of the denominator.

$θ = \frac{π}{3} \cdot \frac{1}{2}$

Step 3.3.2

Multiply $\frac{π}{3} \cdot \frac{1}{2}$ .

Tap for more steps...

Step 3.3.2.1

Multiply $\frac{π}{3}$ by $\frac{1}{2}$ .

$θ = \frac{π}{3 \cdot 2}$

Step 3.3.2.2

Multiply $3$ by $2$ .

$θ = \frac{π}{6}$

Step 4

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$2 θ = 2 π - \frac{π}{3}$

Step 5

Solve for $θ$ .

Tap for more steps...

Step 5.1

Simplify.

Tap for more steps...

Step 5.1.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 θ = 2 π \cdot \frac{3}{3} - \frac{π}{3}$

Step 5.1.2

Combine $2 π$ and $\frac{3}{3}$ .

$2 θ = \frac{2 π \cdot 3}{3} - \frac{π}{3}$

Step 5.1.3

Combine the numerators over the common denominator.

$2 θ = \frac{2 π \cdot 3 - π}{3}$

Step 5.1.4

Multiply $3$ by $2$ .

$2 θ = \frac{6 π - π}{3}$

Step 5.1.5

Subtract $π$ from $6 π$ .

$2 θ = \frac{5 π}{3}$

Step 5.2

Divide each term in $2 θ = \frac{5 π}{3}$ by $2$ and simplify.

Tap for more steps...

Step 5.2.1

Divide each term in $2 θ = \frac{5 π}{3}$ by $2$ .

$\frac{2 θ}{2} = \frac{\frac{5 π}{3}}{2}$

Step 5.2.2

Simplify the left side.

Tap for more steps...

Step 5.2.2.1

Cancel the common factor of $2$ .

Tap for more steps...

Step 5.2.2.1.1

Cancel the common factor.

$\frac{2 θ}{2} = \frac{\frac{5 π}{3}}{2}$

Step 5.2.2.1.2

Divide $θ$ by $1$ .

$θ = \frac{\frac{5 π}{3}}{2}$

Step 5.2.3

Simplify the right side.

Tap for more steps...

Step 5.2.3.1

Multiply the numerator by the reciprocal of the denominator.

$θ = \frac{5 π}{3} \cdot \frac{1}{2}$

Step 5.2.3.2

Multiply $\frac{5 π}{3} \cdot \frac{1}{2}$ .

Tap for more steps...

Step 5.2.3.2.1

Multiply $\frac{5 π}{3}$ by $\frac{1}{2}$ .

$θ = \frac{5 π}{3 \cdot 2}$

Step 5.2.3.2.2

Multiply $3$ by $2$ .

$θ = \frac{5 π}{6}$

Step 6

Find the period of $\cos (2 θ)$ .

Tap for more steps...

Step 6.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 6.2

Replace $b$ with $2$ in the formula for period.

$\frac{2 π}{| 2 |}$

Step 6.3

The absolute value is the distance between a number and zero. The distance between $0$ and $2$ is $2$ .

$\frac{2 π}{2}$

Step 6.4

Cancel the common factor of $2$ .

Tap for more steps...

Step 6.4.1

Cancel the common factor.

$\frac{2 π}{2}$

Step 6.4.2

Divide $π$ by $1$ .

$π$

Step 7

The period of the $\cos (2 θ)$ function is $π$ so values will repeat every $π$ radians in both directions.

$θ = \frac{π}{6} + π n, \frac{5 π}{6} + π n$ , for any integer $n$