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Trigonometry Examples
A=15A=15 , a=4 , b=5
Step 1
The Law of Sines produces an ambiguous angle result. This means that there are 2 angles that will correctly solve the equation. For the first triangle, use the first possible angle value.
Solve for the first triangle.
Step 2
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 3
Substitute the known values into the law of sines to find B.
sin(B)5=sin(15)4
Step 4
Step 4.1
Multiply both sides of the equation by 5.
5sin(B)5=5sin(15)4
Step 4.2
Simplify both sides of the equation.
Step 4.2.1
Simplify the left side.
Step 4.2.1.1
Cancel the common factor of 5.
Step 4.2.1.1.1
Cancel the common factor.
5sin(B)5=5sin(15)4
Step 4.2.1.1.2
Rewrite the expression.
sin(B)=5sin(15)4
sin(B)=5sin(15)4
sin(B)=5sin(15)4
Step 4.2.2
Simplify the right side.
Step 4.2.2.1
Simplify 5sin(15)4.
Step 4.2.2.1.1
The exact value of sin(15) is √6-√24.
Step 4.2.2.1.1.1
Split 15 into two angles where the values of the six trigonometric functions are known.
sin(B)=5sin(45-30)4
Step 4.2.2.1.1.2
Separate negation.
sin(B)=5sin(45-(30))4
Step 4.2.2.1.1.3
Apply the difference of angles identity.
sin(B)=5sin(45)cos(30)-cos(45)sin(30)4
Step 4.2.2.1.1.4
The exact value of sin(45) is √22.
sin(B)=5√22cos(30)-cos(45)sin(30)4
Step 4.2.2.1.1.5
The exact value of cos(30) is √32.
sin(B)=5√22⋅√32-cos(45)sin(30)4
Step 4.2.2.1.1.6
The exact value of cos(45) is √22.
sin(B)=5√22⋅√32-√22sin(30)4
Step 4.2.2.1.1.7
The exact value of sin(30) is 12.
sin(B)=5√22⋅√32-√22⋅124
Step 4.2.2.1.1.8
Simplify √22⋅√32-√22⋅12.
Step 4.2.2.1.1.8.1
Simplify each term.
Step 4.2.2.1.1.8.1.1
Multiply √22⋅√32.
Step 4.2.2.1.1.8.1.1.1
Multiply √22 by √32.
sin(B)=5√2√32⋅2-√22⋅124
Step 4.2.2.1.1.8.1.1.2
Combine using the product rule for radicals.
sin(B)=5√2⋅32⋅2-√22⋅124
Step 4.2.2.1.1.8.1.1.3
Multiply 2 by 3.
sin(B)=5√62⋅2-√22⋅124
Step 4.2.2.1.1.8.1.1.4
Multiply 2 by 2.
sin(B)=5√64-√22⋅124
sin(B)=5√64-√22⋅124
Step 4.2.2.1.1.8.1.2
Multiply -√22⋅12.
Step 4.2.2.1.1.8.1.2.1
Multiply 12 by √22.
sin(B)=5√64-√22⋅24
Step 4.2.2.1.1.8.1.2.2
Multiply 2 by 2.
sin(B)=5√64-√244
sin(B)=5√64-√244
sin(B)=5√64-√244
Step 4.2.2.1.1.8.2
Combine the numerators over the common denominator.
sin(B)=5√6-√244
sin(B)=5√6-√244
sin(B)=5√6-√244
Step 4.2.2.1.2
Multiply the numerator by the reciprocal of the denominator.
sin(B)=5(√6-√24⋅14)
Step 4.2.2.1.3
Multiply √6-√24⋅14.
Step 4.2.2.1.3.1
Multiply √6-√24 by 14.
sin(B)=5√6-√24⋅4
Step 4.2.2.1.3.2
Multiply 4 by 4.
sin(B)=5√6-√216
sin(B)=5√6-√216
Step 4.2.2.1.4
Combine 5 and √6-√216.
sin(B)=5(√6-√2)16
sin(B)=5(√6-√2)16
sin(B)=5(√6-√2)16
sin(B)=5(√6-√2)16
Step 4.3
Take the inverse sine of both sides of the equation to extract B from inside the sine.
B=arcsin(5(√6-√2)16)
Step 4.4
Simplify the right side.
Step 4.4.1
Evaluate arcsin(5(√6-√2)16).
B=18.87616421
B=18.87616421
Step 4.5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from 180 to find the solution in the second quadrant.
B=180-18.87616421
Step 4.6
Subtract 18.87616421 from 180.
B=161.12383578
Step 4.7
The solution to the equation B=18.87616421.
B=18.87616421,161.12383578
B=18.87616421,161.12383578
Step 5
The sum of all the angles in a triangle is 180 degrees.
15+C+18.87616421=180
Step 6
Step 6.1
Add 15 and 18.87616421.
C+33.87616421=180
Step 6.2
Move all terms not containing C to the right side of the equation.
Step 6.2.1
Subtract 33.87616421 from both sides of the equation.
C=180-33.87616421
Step 6.2.2
Subtract 33.87616421 from 180.
C=146.12383578
C=146.12383578
C=146.12383578
Step 7
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 8
Substitute the known values into the law of sines to find c.
sin(146.12383578)c=sin(15)4
Step 9
Step 9.1
Factor each term.
Step 9.1.1
Evaluate sin(146.12383578).
0.55739976c=sin(15)4
Step 9.1.2
The exact value of sin(15) is √6-√24.
Step 9.1.2.1
Split 15 into two angles where the values of the six trigonometric functions are known.
0.55739976c=sin(45-30)4
Step 9.1.2.2
Separate negation.
0.55739976c=sin(45-(30))4
Step 9.1.2.3
Apply the difference of angles identity.
0.55739976c=sin(45)cos(30)-cos(45)sin(30)4
Step 9.1.2.4
The exact value of sin(45) is √22.
0.55739976c=√22cos(30)-cos(45)sin(30)4
Step 9.1.2.5
The exact value of cos(30) is √32.
0.55739976c=√22⋅√32-cos(45)sin(30)4
Step 9.1.2.6
The exact value of cos(45) is √22.
0.55739976c=√22⋅√32-√22sin(30)4
Step 9.1.2.7
The exact value of sin(30) is 12.
0.55739976c=√22⋅√32-√22⋅124
Step 9.1.2.8
Simplify √22⋅√32-√22⋅12.
Step 9.1.2.8.1
Simplify each term.
Step 9.1.2.8.1.1
Multiply √22⋅√32.
Step 9.1.2.8.1.1.1
Multiply √22 by √32.
0.55739976c=√2√32⋅2-√22⋅124
Step 9.1.2.8.1.1.2
Combine using the product rule for radicals.
0.55739976c=√2⋅32⋅2-√22⋅124
Step 9.1.2.8.1.1.3
Multiply 2 by 3.
0.55739976c=√62⋅2-√22⋅124
Step 9.1.2.8.1.1.4
Multiply 2 by 2.
0.55739976c=√64-√22⋅124
0.55739976c=√64-√22⋅124
Step 9.1.2.8.1.2
Multiply -√22⋅12.
Step 9.1.2.8.1.2.1
Multiply 12 by √22.
0.55739976c=√64-√22⋅24
Step 9.1.2.8.1.2.2
Multiply 2 by 2.
0.55739976c=√64-√244
0.55739976c=√64-√244
0.55739976c=√64-√244
Step 9.1.2.8.2
Combine the numerators over the common denominator.
0.55739976c=√6-√244
0.55739976c=√6-√244
0.55739976c=√6-√244
Step 9.1.3
Multiply the numerator by the reciprocal of the denominator.
0.55739976c=√6-√24⋅14
Step 9.1.4
Multiply √6-√24⋅14.
Step 9.1.4.1
Multiply √6-√24 by 14.
0.55739976c=√6-√24⋅4
Step 9.1.4.2
Multiply 4 by 4.
0.55739976c=√6-√216
0.55739976c=√6-√216
0.55739976c=√6-√216
Step 9.2
Find the LCD of the terms in the equation.
Step 9.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
c,16
Step 9.2.2
Since c,16 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 1,16 then find LCM for the variable part c1.
Step 9.2.3
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 9.2.4
The number 1 is not a prime number because it only has one positive factor, which is itself.
Not prime
Step 9.2.5
The prime factors for 16 are 2⋅2⋅2⋅2.
Step 9.2.5.1
16 has factors of 2 and 8.
2⋅8
Step 9.2.5.2
8 has factors of 2 and 4.
2⋅2⋅4
Step 9.2.5.3
4 has factors of 2 and 2.
2⋅2⋅2⋅2
2⋅2⋅2⋅2
Step 9.2.6
Multiply 2⋅2⋅2⋅2.
Step 9.2.6.1
Multiply 2 by 2.
4⋅2⋅2
Step 9.2.6.2
Multiply 4 by 2.
8⋅2
Step 9.2.6.3
Multiply 8 by 2.
16
16
Step 9.2.7
The factor for c1 is c itself.
c1=c
c occurs 1 time.
Step 9.2.8
The LCM of c1 is the result of multiplying all prime factors the greatest number of times they occur in either term.
c
Step 9.2.9
The LCM for c,16 is the numeric part 16 multiplied by the variable part.
16c
16c
Step 9.3
Multiply each term in 0.55739976c=√6-√216 by 16c to eliminate the fractions.
Step 9.3.1
Multiply each term in 0.55739976c=√6-√216 by 16c.
0.55739976c(16c)=√6-√216(16c)
Step 9.3.2
Simplify the left side.
Step 9.3.2.1
Rewrite using the commutative property of multiplication.
160.55739976cc=√6-√216(16c)
Step 9.3.2.2
Multiply 160.55739976c.
Step 9.3.2.2.1
Combine 16 and 0.55739976c.
16⋅0.55739976cc=√6-√216(16c)
Step 9.3.2.2.2
Multiply 16 by 0.55739976.
8.91839623cc=√6-√216(16c)
8.91839623cc=√6-√216(16c)
Step 9.3.2.3
Cancel the common factor of c.
Step 9.3.2.3.1
Cancel the common factor.
8.91839623cc=√6-√216(16c)
Step 9.3.2.3.2
Rewrite the expression.
8.91839623=√6-√216(16c)
8.91839623=√6-√216(16c)
8.91839623=√6-√216(16c)
Step 9.3.3
Simplify the right side.
Step 9.3.3.1
Cancel the common factor of 16.
Step 9.3.3.1.1
Factor 16 out of 16c.
8.91839623=√6-√216(16(c))
Step 9.3.3.1.2
Cancel the common factor.
8.91839623=√6-√216(16c)
Step 9.3.3.1.3
Rewrite the expression.
8.91839623=(√6-√2)c
8.91839623=(√6-√2)c
Step 9.3.3.2
Apply the distributive property.
8.91839623=√6c-√2c
8.91839623=√6c-√2c
8.91839623=√6c-√2c
Step 9.4
Solve the equation.
Step 9.4.1
Rewrite the equation as √6c-√2c=8.91839623.
√6c-√2c=8.91839623
Step 9.4.2
Factor c out of √6c-√2c.
Step 9.4.2.1
Factor c out of √6c.
c√6-√2c=8.91839623
Step 9.4.2.2
Factor c out of -√2c.
c√6+c(-√2)=8.91839623
Step 9.4.2.3
Factor c out of c√6+c(-√2).
c(√6-√2)=8.91839623
c(√6-√2)=8.91839623
Step 9.4.3
Divide each term in c(√6-√2)=8.91839623 by √6-√2 and simplify.
Step 9.4.3.1
Divide each term in c(√6-√2)=8.91839623 by √6-√2.
c(√6-√2)√6-√2=8.91839623√6-√2
Step 9.4.3.2
Simplify the left side.
Step 9.4.3.2.1
Cancel the common factor of √6-√2.
Step 9.4.3.2.1.1
Cancel the common factor.
c(√6-√2)√6-√2=8.91839623√6-√2
Step 9.4.3.2.1.2
Divide c by 1.
c=8.91839623√6-√2
c=8.91839623√6-√2
c=8.91839623√6-√2
Step 9.4.3.3
Simplify the right side.
Step 9.4.3.3.1
Multiply 8.91839623√6-√2 by √6+√2√6+√2.
c=8.91839623√6-√2⋅√6+√2√6+√2
Step 9.4.3.3.2
Multiply 8.91839623√6-√2 by √6+√2√6+√2.
c=8.91839623(√6+√2)(√6-√2)(√6+√2)
Step 9.4.3.3.3
Expand the denominator using the FOIL method.
c=8.91839623(√6+√2)√62+√12-√12-√22
Step 9.4.3.3.4
Simplify.
c=8.91839623(√6+√2)4
Step 9.4.3.3.5
Multiply 8.91839623 by √6+√2.
c=34.458037014
Step 9.4.3.3.6
Divide 34.45803701 by 4.
c=8.61450925
c=8.61450925
c=8.61450925
c=8.61450925
c=8.61450925
Step 10
For the second triangle, use the second possible angle value.
Solve for the second triangle.
Step 11
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 12
Substitute the known values into the law of sines to find B.
sin(B)5=sin(15)4
Step 13
Step 13.1
Multiply both sides of the equation by 5.
5sin(B)5=5sin(15)4
Step 13.2
Simplify both sides of the equation.
Step 13.2.1
Simplify the left side.
Step 13.2.1.1
Cancel the common factor of 5.
Step 13.2.1.1.1
Cancel the common factor.
5sin(B)5=5sin(15)4
Step 13.2.1.1.2
Rewrite the expression.
sin(B)=5sin(15)4
sin(B)=5sin(15)4
sin(B)=5sin(15)4
Step 13.2.2
Simplify the right side.
Step 13.2.2.1
Simplify 5sin(15)4.
Step 13.2.2.1.1
The exact value of sin(15) is √6-√24.
Step 13.2.2.1.1.1
Split 15 into two angles where the values of the six trigonometric functions are known.
sin(B)=5sin(45-30)4
Step 13.2.2.1.1.2
Separate negation.
sin(B)=5sin(45-(30))4
Step 13.2.2.1.1.3
Apply the difference of angles identity.
sin(B)=5sin(45)cos(30)-cos(45)sin(30)4
Step 13.2.2.1.1.4
The exact value of sin(45) is √22.
sin(B)=5√22cos(30)-cos(45)sin(30)4
Step 13.2.2.1.1.5
The exact value of cos(30) is √32.
sin(B)=5√22⋅√32-cos(45)sin(30)4
Step 13.2.2.1.1.6
The exact value of cos(45) is √22.
sin(B)=5√22⋅√32-√22sin(30)4
Step 13.2.2.1.1.7
The exact value of sin(30) is 12.
sin(B)=5√22⋅√32-√22⋅124
Step 13.2.2.1.1.8
Simplify √22⋅√32-√22⋅12.
Step 13.2.2.1.1.8.1
Simplify each term.
Step 13.2.2.1.1.8.1.1
Multiply √22⋅√32.
Step 13.2.2.1.1.8.1.1.1
Multiply √22 by √32.
sin(B)=5√2√32⋅2-√22⋅124
Step 13.2.2.1.1.8.1.1.2
Combine using the product rule for radicals.
sin(B)=5√2⋅32⋅2-√22⋅124
Step 13.2.2.1.1.8.1.1.3
Multiply 2 by 3.
sin(B)=5√62⋅2-√22⋅124
Step 13.2.2.1.1.8.1.1.4
Multiply 2 by 2.
sin(B)=5√64-√22⋅124
sin(B)=5√64-√22⋅124
Step 13.2.2.1.1.8.1.2
Multiply -√22⋅12.
Step 13.2.2.1.1.8.1.2.1
Multiply 12 by √22.
sin(B)=5√64-√22⋅24
Step 13.2.2.1.1.8.1.2.2
Multiply 2 by 2.
sin(B)=5√64-√244
sin(B)=5√64-√244
sin(B)=5√64-√244
Step 13.2.2.1.1.8.2
Combine the numerators over the common denominator.
sin(B)=5√6-√244
sin(B)=5√6-√244
sin(B)=5√6-√244
Step 13.2.2.1.2
Multiply the numerator by the reciprocal of the denominator.
sin(B)=5(√6-√24⋅14)
Step 13.2.2.1.3
Multiply √6-√24⋅14.
Step 13.2.2.1.3.1
Multiply √6-√24 by 14.
sin(B)=5√6-√24⋅4
Step 13.2.2.1.3.2
Multiply 4 by 4.
sin(B)=5√6-√216
sin(B)=5√6-√216
Step 13.2.2.1.4
Combine 5 and √6-√216.
sin(B)=5(√6-√2)16
sin(B)=5(√6-√2)16
sin(B)=5(√6-√2)16
sin(B)=5(√6-√2)16
Step 13.3
Take the inverse sine of both sides of the equation to extract B from inside the sine.
B=arcsin(5(√6-√2)16)
Step 13.4
Simplify the right side.
Step 13.4.1
Evaluate arcsin(5(√6-√2)16).
B=18.87616421
B=18.87616421
Step 13.5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from 180 to find the solution in the second quadrant.
B=180-18.87616421
Step 13.6
Subtract 18.87616421 from 180.
B=161.12383578
Step 13.7
The solution to the equation B=18.87616421.
B=18.87616421,161.12383578
B=18.87616421,161.12383578
Step 14
The sum of all the angles in a triangle is 180 degrees.
15+C+161.12383578=180
Step 15
Step 15.1
Add 15 and 161.12383578.
C+176.12383578=180
Step 15.2
Move all terms not containing C to the right side of the equation.
Step 15.2.1
Subtract 176.12383578 from both sides of the equation.
C=180-176.12383578
Step 15.2.2
Subtract 176.12383578 from 180.
C=3.87616421
C=3.87616421
C=3.87616421
Step 16
The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.
sin(A)a=sin(B)b=sin(C)c
Step 17
Substitute the known values into the law of sines to find c.
sin(3.87616421)c=sin(15)4
Step 18
Step 18.1
Factor each term.
Step 18.1.1
Evaluate sin(3.87616421).
0.06760023c=sin(15)4
Step 18.1.2
The exact value of sin(15) is √6-√24.
Step 18.1.2.1
Split 15 into two angles where the values of the six trigonometric functions are known.
0.06760023c=sin(45-30)4
Step 18.1.2.2
Separate negation.
0.06760023c=sin(45-(30))4
Step 18.1.2.3
Apply the difference of angles identity.
0.06760023c=sin(45)cos(30)-cos(45)sin(30)4
Step 18.1.2.4
The exact value of sin(45) is √22.
0.06760023c=√22cos(30)-cos(45)sin(30)4
Step 18.1.2.5
The exact value of cos(30) is √32.
0.06760023c=√22⋅√32-cos(45)sin(30)4
Step 18.1.2.6
The exact value of cos(45) is √22.
0.06760023c=√22⋅√32-√22sin(30)4
Step 18.1.2.7
The exact value of sin(30) is 12.
0.06760023c=√22⋅√32-√22⋅124
Step 18.1.2.8
Simplify √22⋅√32-√22⋅12.
Step 18.1.2.8.1
Simplify each term.
Step 18.1.2.8.1.1
Multiply √22⋅√32.
Step 18.1.2.8.1.1.1
Multiply √22 by √32.
0.06760023c=√2√32⋅2-√22⋅124
Step 18.1.2.8.1.1.2
Combine using the product rule for radicals.
0.06760023c=√2⋅32⋅2-√22⋅124
Step 18.1.2.8.1.1.3
Multiply 2 by 3.
0.06760023c=√62⋅2-√22⋅124
Step 18.1.2.8.1.1.4
Multiply 2 by 2.
0.06760023c=√64-√22⋅124
0.06760023c=√64-√22⋅124
Step 18.1.2.8.1.2
Multiply -√22⋅12.
Step 18.1.2.8.1.2.1
Multiply 12 by √22.
0.06760023c=√64-√22⋅24
Step 18.1.2.8.1.2.2
Multiply 2 by 2.
0.06760023c=√64-√244
0.06760023c=√64-√244
0.06760023c=√64-√244
Step 18.1.2.8.2
Combine the numerators over the common denominator.
0.06760023c=√6-√244
0.06760023c=√6-√244
0.06760023c=√6-√244
Step 18.1.3
Multiply the numerator by the reciprocal of the denominator.
0.06760023c=√6-√24⋅14
Step 18.1.4
Multiply √6-√24⋅14.
Step 18.1.4.1
Multiply √6-√24 by 14.
0.06760023c=√6-√24⋅4
Step 18.1.4.2
Multiply 4 by 4.
0.06760023c=√6-√216
0.06760023c=√6-√216
0.06760023c=√6-√216
Step 18.2
Find the LCD of the terms in the equation.
Step 18.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
c,16
Step 18.2.2
Since c,16 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 1,16 then find LCM for the variable part c1.
Step 18.2.3
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 18.2.4
The number 1 is not a prime number because it only has one positive factor, which is itself.
Not prime
Step 18.2.5
The prime factors for 16 are 2⋅2⋅2⋅2.
Step 18.2.5.1
16 has factors of 2 and 8.
2⋅8
Step 18.2.5.2
8 has factors of 2 and 4.
2⋅2⋅4
Step 18.2.5.3
4 has factors of 2 and 2.
2⋅2⋅2⋅2
2⋅2⋅2⋅2
Step 18.2.6
Multiply 2⋅2⋅2⋅2.
Step 18.2.6.1
Multiply 2 by 2.
4⋅2⋅2
Step 18.2.6.2
Multiply 4 by 2.
8⋅2
Step 18.2.6.3
Multiply 8 by 2.
16
16
Step 18.2.7
The factor for c1 is c itself.
c1=c
c occurs 1 time.
Step 18.2.8
The LCM of c1 is the result of multiplying all prime factors the greatest number of times they occur in either term.
c
Step 18.2.9
The LCM for c,16 is the numeric part 16 multiplied by the variable part.
16c
16c
Step 18.3
Multiply each term in 0.06760023c=√6-√216 by 16c to eliminate the fractions.
Step 18.3.1
Multiply each term in 0.06760023c=√6-√216 by 16c.
0.06760023c(16c)=√6-√216(16c)
Step 18.3.2
Simplify the left side.
Step 18.3.2.1
Rewrite using the commutative property of multiplication.
160.06760023cc=√6-√216(16c)
Step 18.3.2.2
Multiply 160.06760023c.
Step 18.3.2.2.1
Combine 16 and 0.06760023c.
16⋅0.06760023cc=√6-√216(16c)
Step 18.3.2.2.2
Multiply 16 by 0.06760023.
1.08160376cc=√6-√216(16c)
1.08160376cc=√6-√216(16c)
Step 18.3.2.3
Cancel the common factor of c.
Step 18.3.2.3.1
Cancel the common factor.
1.08160376cc=√6-√216(16c)
Step 18.3.2.3.2
Rewrite the expression.
1.08160376=√6-√216(16c)
1.08160376=√6-√216(16c)
1.08160376=√6-√216(16c)
Step 18.3.3
Simplify the right side.
Step 18.3.3.1
Cancel the common factor of 16.
Step 18.3.3.1.1
Factor 16 out of 16c.
1.08160376=√6-√216(16(c))
Step 18.3.3.1.2
Cancel the common factor.
1.08160376=√6-√216(16c)
Step 18.3.3.1.3
Rewrite the expression.
1.08160376=(√6-√2)c
1.08160376=(√6-√2)c
Step 18.3.3.2
Apply the distributive property.
1.08160376=√6c-√2c
1.08160376=√6c-√2c
1.08160376=√6c-√2c
Step 18.4
Solve the equation.
Step 18.4.1
Rewrite the equation as √6c-√2c=1.08160376.
√6c-√2c=1.08160376
Step 18.4.2
Factor c out of √6c-√2c.
Step 18.4.2.1
Factor c out of √6c.
c√6-√2c=1.08160376
Step 18.4.2.2
Factor c out of -√2c.
c√6+c(-√2)=1.08160376
Step 18.4.2.3
Factor c out of c√6+c(-√2).
c(√6-√2)=1.08160376
c(√6-√2)=1.08160376
Step 18.4.3
Divide each term in c(√6-√2)=1.08160376 by √6-√2 and simplify.
Step 18.4.3.1
Divide each term in c(√6-√2)=1.08160376 by √6-√2.
c(√6-√2)√6-√2=1.08160376√6-√2
Step 18.4.3.2
Simplify the left side.
Step 18.4.3.2.1
Cancel the common factor of √6-√2.
Step 18.4.3.2.1.1
Cancel the common factor.
c(√6-√2)√6-√2=1.08160376√6-√2
Step 18.4.3.2.1.2
Divide c by 1.
c=1.08160376√6-√2
c=1.08160376√6-√2
c=1.08160376√6-√2
Step 18.4.3.3
Simplify the right side.
Step 18.4.3.3.1
Multiply 1.08160376√6-√2 by √6+√2√6+√2.
c=1.08160376√6-√2⋅√6+√2√6+√2
Step 18.4.3.3.2
Multiply 1.08160376√6-√2 by √6+√2√6+√2.
c=1.08160376(√6+√2)(√6-√2)(√6+√2)
Step 18.4.3.3.3
Expand the denominator using the FOIL method.
c=1.08160376(√6+√2)√62+√12-√12-√22
Step 18.4.3.3.4
Simplify.
c=1.08160376(√6+√2)4
Step 18.4.3.3.5
Multiply 1.08160376 by √6+√2.
c=4.178996034
Step 18.4.3.3.6
Divide 4.17899603 by 4.
c=1.044749
c=1.044749
c=1.044749
c=1.044749
c=1.044749
Step 19
These are the results for all angles and sides for the given triangle.
First Triangle Combination:
A=15
B=18.87616421
C=146.12383578
a=4
b=5
c=8.61450925
Second Triangle Combination:
A=15
B=161.12383578
C=3.87616421
a=4
b=5
c=1.044749