Trigonometry Examples

$g (x) = \ln (x - 1)$

Step 1

Find the asymptotes.

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Step 1.1

Set the argument of the logarithm equal to zero.

$x - 1 = 0$

Step 1.2

Add $1$ to both sides of the equation.

$x = 1$

Step 1.3

The vertical asymptote occurs at $x = 1$ .

Vertical Asymptote: $x = 1$

Step 2

Find the point at $x = 2$ .

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Step 2.1

Replace the variable $x$ with $2$ in the expression.

$f (2) = \ln ((2) - 1)$

Step 2.2

Simplify the result.

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Step 2.2.1

Subtract $1$ from $2$ .

$f (2) = \ln (1)$

Step 2.2.2

The natural logarithm of $1$ is $0$ .

$f (2) = 0$

Step 2.2.3

The final answer is $0$ .

$0$

Step 2.3

Convert $0$ to decimal.

$y = 0$

Step 3

Find the point at $x = 3$ .

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Step 3.1

Replace the variable $x$ with $3$ in the expression.

$f (3) = \ln ((3) - 1)$

Step 3.2

Simplify the result.

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Step 3.2.1

Subtract $1$ from $3$ .

$f (3) = \ln (2)$

Step 3.2.2

The final answer is $\ln (2)$ .

$\ln (2)$

Step 3.3

Convert $\ln (2)$ to decimal.

$y = 0.69314718$

Step 4

Find the point at $x = 4$ .

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Step 4.1

Replace the variable $x$ with $4$ in the expression.

$f (4) = \ln ((4) - 1)$

Step 4.2

Simplify the result.

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Step 4.2.1

Subtract $1$ from $4$ .

$f (4) = \ln (3)$

Step 4.2.2

The final answer is $\ln (3)$ .

$\ln (3)$

Step 4.3

Convert $\ln (3)$ to decimal.

$y = 1.09861228$

Step 5

The log function can be graphed using the vertical asymptote at $x = 1$ and the points $(2, 0), (3, 0.69314718), (4, 1.09861228)$ .

Vertical Asymptote: $x = 1$

$\begin{array}{c} x & y \\ 2 & 0 \\ 3 & 0.693 \\ 4 & 1.099 \end{array}$

Step 6