Trigonometry Examples

$f (x) = 6 x^{2} - 7 x - 3$

Step 1

Find the properties of the given parabola.

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Step 1.1

Rewrite the equation in vertex form.

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Step 1.1.1

Complete the square for $6 x^{2} - 7 x - 3$ .

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Step 1.1.1.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 6$

$b = - 7$

$c = - 3$

Step 1.1.1.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 1.1.1.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 1.1.1.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 7}{2 \cdot 6}$

Step 1.1.1.3.2

Simplify the right side.

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Step 1.1.1.3.2.1

Multiply $2$ by $6$ .

$d = \frac{- 7}{12}$

Step 1.1.1.3.2.2

Move the negative in front of the fraction.

$d = - \frac{7}{12}$

Step 1.1.1.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 1.1.1.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 3 - \frac{{(- 7)}^{2}}{4 \cdot 6}$

Step 1.1.1.4.2

Simplify the right side.

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Step 1.1.1.4.2.1

Simplify each term.

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Step 1.1.1.4.2.1.1

Raise $- 7$ to the power of $2$ .

$e = - 3 - \frac{49}{4 \cdot 6}$

Step 1.1.1.4.2.1.2

Multiply $4$ by $6$ .

$e = - 3 - \frac{49}{24}$

Step 1.1.1.4.2.2

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{24}{24}$ .

$e = - 3 \cdot \frac{24}{24} - \frac{49}{24}$

Step 1.1.1.4.2.3

Combine $- 3$ and $\frac{24}{24}$ .

$e = \frac{- 3 \cdot 24}{24} - \frac{49}{24}$

Step 1.1.1.4.2.4

Combine the numerators over the common denominator.

$e = \frac{- 3 \cdot 24 - 49}{24}$

Step 1.1.1.4.2.5

Simplify the numerator.

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Step 1.1.1.4.2.5.1

Multiply $- 3$ by $24$ .

$e = \frac{- 72 - 49}{24}$

Step 1.1.1.4.2.5.2

Subtract $49$ from $- 72$ .

$e = \frac{- 121}{24}$

Step 1.1.1.4.2.6

Move the negative in front of the fraction.

$e = - \frac{121}{24}$

Step 1.1.1.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $6 {(x - \frac{7}{12})}^{2} - \frac{121}{24}$ .

$6 {(x - \frac{7}{12})}^{2} - \frac{121}{24}$

Step 1.1.2

Set $y$ equal to the new right side.

$y = 6 {(x - \frac{7}{12})}^{2} - \frac{121}{24}$

Step 1.2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 6$

$h = \frac{7}{12}$

$k = - \frac{121}{24}$

Step 1.3

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Step 1.4

Find the vertex $(h, k)$ .

$(\frac{7}{12}, - \frac{121}{24})$

Step 1.5

Find $p$ , the distance from the vertex to the focus.

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Step 1.5.1

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Step 1.5.2

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 6}$

Step 1.5.3

Multiply $4$ by $6$ .

$\frac{1}{24}$

Step 1.6

Find the focus.

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Step 1.6.1

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Step 1.6.2

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{7}{12}, - 5)$

Step 1.7

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = \frac{7}{12}$

Step 1.8

Find the directrix.

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Step 1.8.1

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Step 1.8.2

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{61}{12}$

Step 1.9

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(\frac{7}{12}, - \frac{121}{24})$

Focus: $(\frac{7}{12}, - 5)$

Axis of Symmetry: $x = \frac{7}{12}$

Directrix: $y = - \frac{61}{12}$

Direction: Opens Up

Vertex: $(\frac{7}{12}, - \frac{121}{24})$

Focus: $(\frac{7}{12}, - 5)$

Axis of Symmetry: $x = \frac{7}{12}$

Directrix: $y = - \frac{61}{12}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

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Step 2.1

Replace the variable $x$ with $0$ in the expression.

$f (0) = 6 {(0)}^{2} - 7 \cdot 0 - 3$

Step 2.2

Simplify the result.

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Step 2.2.1

Simplify each term.

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Step 2.2.1.1

Raising $0$ to any positive power yields $0$ .

$f (0) = 6 \cdot 0 - 7 \cdot 0 - 3$

Step 2.2.1.2

Multiply $6$ by $0$ .

$f (0) = 0 - 7 \cdot 0 - 3$

Step 2.2.1.3

Multiply $- 7$ by $0$ .

$f (0) = 0 + 0 - 3$

Step 2.2.2

Simplify by adding and subtracting.

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Step 2.2.2.1

Add $0$ and $0$ .

$f (0) = 0 - 3$

Step 2.2.2.2

Subtract $3$ from $0$ .

$f (0) = - 3$

Step 2.2.3

The final answer is $- 3$ .

$- 3$

Step 2.3

The $y$ value at $x = 0$ is $- 3$ .

$y = - 3$

Step 2.4

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = 6 {(- 1)}^{2} - 7 \cdot - 1 - 3$

Step 2.5

Simplify the result.

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Step 2.5.1

Simplify each term.

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Step 2.5.1.1

Raise $- 1$ to the power of $2$ .

$f (- 1) = 6 \cdot 1 - 7 \cdot - 1 - 3$

Step 2.5.1.2

Multiply $6$ by $1$ .

$f (- 1) = 6 - 7 \cdot - 1 - 3$

Step 2.5.1.3

Multiply $- 7$ by $- 1$ .

$f (- 1) = 6 + 7 - 3$

Step 2.5.2

Simplify by adding and subtracting.

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Step 2.5.2.1

Add $6$ and $7$ .

$f (- 1) = 13 - 3$

Step 2.5.2.2

Subtract $3$ from $13$ .

$f (- 1) = 10$

Step 2.5.3

The final answer is $10$ .

$10$

Step 2.6

The $y$ value at $x = - 1$ is $10$ .

$y = 10$

Step 2.7

Replace the variable $x$ with $2$ in the expression.

$f (2) = 6 {(2)}^{2} - 7 \cdot 2 - 3$

Step 2.8

Simplify the result.

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Step 2.8.1

Simplify each term.

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Step 2.8.1.1

Raise $2$ to the power of $2$ .

$f (2) = 6 \cdot 4 - 7 \cdot 2 - 3$

Step 2.8.1.2

Multiply $6$ by $4$ .

$f (2) = 24 - 7 \cdot 2 - 3$

Step 2.8.1.3

Multiply $- 7$ by $2$ .

$f (2) = 24 - 14 - 3$

Step 2.8.2

Simplify by subtracting numbers.

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Step 2.8.2.1

Subtract $14$ from $24$ .

$f (2) = 10 - 3$

Step 2.8.2.2

Subtract $3$ from $10$ .

$f (2) = 7$

Step 2.8.3

The final answer is $7$ .

$7$

Step 2.9

The $y$ value at $x = 2$ is $7$ .

$y = 7$

Step 2.10

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 1 & 10 \\ 0 & - 3 \\ \frac{7}{12} & - \frac{121}{24} \\ 2 & 7 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(\frac{7}{12}, - \frac{121}{24})$

Focus: $(\frac{7}{12}, - 5)$

Axis of Symmetry: $x = \frac{7}{12}$

Directrix: $y = - \frac{61}{12}$

$\begin{array}{c} x & y \\ - 1 & 10 \\ 0 & - 3 \\ \frac{7}{12} & - \frac{121}{24} \\ 2 & 7 \end{array}$

Step 4