Trigonometry Examples

$\sec (x) = \frac{5}{3}$

Step 1

Take the inverse secant of both sides of the equation to extract $x$ from inside the secant.

$x = arcsec (\frac{5}{3})$

Step 2

Simplify the right side.

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Step 2.1

Evaluate $arcsec (\frac{5}{3})$ .

$x = 0.92729521$

Step 3

The secant function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$x = 2 (3.14159265) - 0.92729521$

Step 4

Simplify $2 (3.14159265) - 0.92729521$ .

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Step 4.1

Multiply $2$ by $3.14159265$ .

$x = 6.2831853 - 0.92729521$

Step 4.2

Subtract $0.92729521$ from $6.2831853$ .

$x = 5.35589008$

Step 5

Find the period of $\sec (x)$ .

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Step 5.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 5.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 5.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 5.4

Divide $2 π$ by $1$ .

$2 π$

Step 6

The period of the $\sec (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = 0.92729521 + 2 π n, 5.35589008 + 2 π n$ , for any integer $n$