Trigonometry Examples

$x^{2} - 4 x + 3 = 8$

Step 1

Subtract $8$ from both sides of the equation.

$x^{2} - 4 x + 3 - 8 = 0$

Step 2

Subtract $8$ from $3$ .

$x^{2} - 4 x - 5 = 0$

Step 3

Factor $x^{2} - 4 x - 5$ using the AC method.

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Step 3.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 5$ and whose sum is $- 4$ .

$- 5, 1$

Step 3.2

Write the factored form using these integers.

$(x - 5) (x + 1) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 5 = 0$

$x + 1 = 0$

Step 5

Set $x - 5$ equal to $0$ and solve for $x$ .

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Step 5.1

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Step 5.2

Add $5$ to both sides of the equation.

$x = 5$

Step 6

Set $x + 1$ equal to $0$ and solve for $x$ .

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Step 6.1

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Step 6.2

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 7

The final solution is all the values that make $(x - 5) (x + 1) = 0$ true.

$x = 5, - 1$