Trigonometry Examples

$y = 4 \sin (π x + 2) - 5$

Step 1

Use the form $a \sin (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = 4$

$b = π$

$c = - 2$

$d = - 5$

Step 2

Find the amplitude $| a |$ .

Amplitude: $4$

Step 3

Find the period using the formula $\frac{2 π}{| b |}$ .

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Step 3.1

Find the period of $4 \sin (π x + 2)$ .

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Step 3.1.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 3.1.2

Replace $b$ with $π$ in the formula for period.

$\frac{2 π}{| π |}$

Step 3.1.3

$π$ is approximately $3.14159265$ which is positive so remove the absolute value

$\frac{2 π}{π}$

Step 3.1.4

Cancel the common factor of $π$ .

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Step 3.1.4.1

Cancel the common factor.

$\frac{2 π}{π}$

Step 3.1.4.2

Divide $2$ by $1$ .

$2$

Step 3.2

Find the period of $- 5$ .

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Step 3.2.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 3.2.2

Replace $b$ with $π$ in the formula for period.

$\frac{2 π}{| π |}$

Step 3.2.3

$π$ is approximately $3.14159265$ which is positive so remove the absolute value

$\frac{2 π}{π}$

Step 3.2.4

Cancel the common factor of $π$ .

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Step 3.2.4.1

Cancel the common factor.

$\frac{2 π}{π}$

Step 3.2.4.2

Divide $2$ by $1$ .

$2$

Step 3.3

The period of addition/subtraction of trig functions is the maximum of the individual periods.

$2$

Step 4

Find the phase shift using the formula $\frac{c}{b}$ .

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Step 4.1

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Step 4.2

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{- 2}{π}$

Step 4.3

Move the negative in front of the fraction.

Phase Shift: $- \frac{2}{π}$

Step 5

List the properties of the trigonometric function.

Amplitude: $4$

Period: $2$

Phase Shift: $- \frac{2}{π}$ ( $\frac{2}{π}$ to the left)

Vertical Shift: $- 5$

Step 6

Select a few points to graph.

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Step 6.1

Find the point at $x = - \frac{2}{π}$ .

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Step 6.1.1

Replace the variable $x$ with $- \frac{2}{π}$ in the expression.

$f (- \frac{2}{π}) = 4 \sin (π (- \frac{2}{π}) + 2) - 5$

Step 6.1.2

Simplify the result.

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Step 6.1.2.1

Simplify each term.

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Step 6.1.2.1.1

Cancel the common factor of $π$ .

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Step 6.1.2.1.1.1

Move the leading negative in $- \frac{2}{π}$ into the numerator.

$f (- \frac{2}{π}) = 4 \sin (π (\frac{- 2}{π}) + 2) - 5$

Step 6.1.2.1.1.2

Cancel the common factor.

$f (- \frac{2}{π}) = 4 \sin (π (\frac{- 2}{π}) + 2) - 5$

Step 6.1.2.1.1.3

Rewrite the expression.

$f (- \frac{2}{π}) = 4 \sin (- 2 + 2) - 5$

Step 6.1.2.1.2

Add $- 2$ and $2$ .

$f (- \frac{2}{π}) = 4 \sin (0) - 5$

Step 6.1.2.1.3

The exact value of $\sin (0)$ is $0$ .

$f (- \frac{2}{π}) = 4 \cdot 0 - 5$

Step 6.1.2.1.4

Multiply $4$ by $0$ .

$f (- \frac{2}{π}) = 0 - 5$

Step 6.1.2.2

Subtract $5$ from $0$ .

$f (- \frac{2}{π}) = - 5$

Step 6.1.2.3

The final answer is $- 5$ .

$- 5$

Step 6.2

Find the point at $x = \frac{1}{2} - \frac{2}{π}$ .

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Step 6.2.1

Replace the variable $x$ with $\frac{1}{2} - \frac{2}{π}$ in the expression.

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (π (\frac{1}{2} - \frac{2}{π}) + 2) - 5$

Step 6.2.2

Simplify the result.

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Step 6.2.2.1

Simplify each term.

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Step 6.2.2.1.1

Simplify each term.

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Step 6.2.2.1.1.1

Apply the distributive property.

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (π (\frac{1}{2}) + π (- \frac{2}{π}) + 2) - 5$

Step 6.2.2.1.1.2

Combine $π$ and $\frac{1}{2}$ .

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (\frac{π}{2} + π (- \frac{2}{π}) + 2) - 5$

Step 6.2.2.1.1.3

Cancel the common factor of $π$ .

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Step 6.2.2.1.1.3.1

Move the leading negative in $- \frac{2}{π}$ into the numerator.

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (\frac{π}{2} + π (\frac{- 2}{π}) + 2) - 5$

Step 6.2.2.1.1.3.2

Cancel the common factor.

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (\frac{π}{2} + π (\frac{- 2}{π}) + 2) - 5$

Step 6.2.2.1.1.3.3

Rewrite the expression.

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (\frac{π}{2} - 2 + 2) - 5$

Step 6.2.2.1.2

Add $- 2$ and $2$ .

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (\frac{π}{2} + 0) - 5$

Step 6.2.2.1.3

Add $\frac{π}{2}$ and $0$ .

$f (\frac{1}{2} - \frac{2}{π}) = 4 \sin (\frac{π}{2}) - 5$

Step 6.2.2.1.4

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (\frac{1}{2} - \frac{2}{π}) = 4 \cdot 1 - 5$

Step 6.2.2.1.5

Multiply $4$ by $1$ .

$f (\frac{1}{2} - \frac{2}{π}) = 4 - 5$

Step 6.2.2.2

Subtract $5$ from $4$ .

$f (\frac{1}{2} - \frac{2}{π}) = - 1$

Step 6.2.2.3

The final answer is $- 1$ .

$- 1$

Step 6.3

Find the point at $x = 1 - \frac{2}{π}$ .

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Step 6.3.1

Replace the variable $x$ with $1 - \frac{2}{π}$ in the expression.

$f (1 - \frac{2}{π}) = 4 \sin (π (1 - \frac{2}{π}) + 2) - 5$

Step 6.3.2

Simplify the result.

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Step 6.3.2.1

Simplify each term.

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Step 6.3.2.1.1

Simplify each term.

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Step 6.3.2.1.1.1

Apply the distributive property.

$f (1 - \frac{2}{π}) = 4 \sin (π \cdot 1 + π (- \frac{2}{π}) + 2) - 5$

Step 6.3.2.1.1.2

Multiply $π$ by $1$ .

$f (1 - \frac{2}{π}) = 4 \sin (π + π (- \frac{2}{π}) + 2) - 5$

Step 6.3.2.1.1.3

Cancel the common factor of $π$ .

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Step 6.3.2.1.1.3.1

Move the leading negative in $- \frac{2}{π}$ into the numerator.

$f (1 - \frac{2}{π}) = 4 \sin (π + π (\frac{- 2}{π}) + 2) - 5$

Step 6.3.2.1.1.3.2

Cancel the common factor.

$f (1 - \frac{2}{π}) = 4 \sin (π + π (\frac{- 2}{π}) + 2) - 5$

Step 6.3.2.1.1.3.3

Rewrite the expression.

$f (1 - \frac{2}{π}) = 4 \sin (π - 2 + 2) - 5$

Step 6.3.2.1.2

Add $- 2$ and $2$ .

$f (1 - \frac{2}{π}) = 4 \sin (π + 0) - 5$

Step 6.3.2.1.3

Add $π$ and $0$ .

$f (1 - \frac{2}{π}) = 4 \sin (π) - 5$

Step 6.3.2.1.4

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$f (1 - \frac{2}{π}) = 4 \sin (0) - 5$

Step 6.3.2.1.5

The exact value of $\sin (0)$ is $0$ .

$f (1 - \frac{2}{π}) = 4 \cdot 0 - 5$

Step 6.3.2.1.6

Multiply $4$ by $0$ .

$f (1 - \frac{2}{π}) = 0 - 5$

Step 6.3.2.2

Subtract $5$ from $0$ .

$f (1 - \frac{2}{π}) = - 5$

Step 6.3.2.3

The final answer is $- 5$ .

$- 5$

Step 6.4

Find the point at $x = \frac{3}{2} - \frac{2}{π}$ .

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Step 6.4.1

Replace the variable $x$ with $\frac{3}{2} - \frac{2}{π}$ in the expression.

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (π (\frac{3}{2} - \frac{2}{π}) + 2) - 5$

Step 6.4.2

Simplify the result.

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Step 6.4.2.1

Simplify each term.

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Step 6.4.2.1.1

Simplify each term.

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Step 6.4.2.1.1.1

Apply the distributive property.

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (π (\frac{3}{2}) + π (- \frac{2}{π}) + 2) - 5$

Step 6.4.2.1.1.2

Combine $π$ and $\frac{3}{2}$ .

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{π \cdot 3}{2} + π (- \frac{2}{π}) + 2) - 5$

Step 6.4.2.1.1.3

Cancel the common factor of $π$ .

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Step 6.4.2.1.1.3.1

Move the leading negative in $- \frac{2}{π}$ into the numerator.

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{π \cdot 3}{2} + π (\frac{- 2}{π}) + 2) - 5$

Step 6.4.2.1.1.3.2

Cancel the common factor.

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{π \cdot 3}{2} + π (\frac{- 2}{π}) + 2) - 5$

Step 6.4.2.1.1.3.3

Rewrite the expression.

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{π \cdot 3}{2} - 2 + 2) - 5$

Step 6.4.2.1.1.4

Move $3$ to the left of $π$ .

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{3 π}{2} - 2 + 2) - 5$

Step 6.4.2.1.2

Add $- 2$ and $2$ .

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{3 π}{2} + 0) - 5$

Step 6.4.2.1.3

Add $\frac{3 π}{2}$ and $0$ .

$f (\frac{3}{2} - \frac{2}{π}) = 4 \sin (\frac{3 π}{2}) - 5$

Step 6.4.2.1.4

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the fourth quadrant.

$f (\frac{3}{2} - \frac{2}{π}) = 4 (- \sin (\frac{π}{2})) - 5$

Step 6.4.2.1.5

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (\frac{3}{2} - \frac{2}{π}) = 4 (- 1 \cdot 1) - 5$

Step 6.4.2.1.6

Multiply $4 (- 1 \cdot 1)$ .

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Step 6.4.2.1.6.1

Multiply $- 1$ by $1$ .

$f (\frac{3}{2} - \frac{2}{π}) = 4 \cdot - 1 - 5$

Step 6.4.2.1.6.2

Multiply $4$ by $- 1$ .

$f (\frac{3}{2} - \frac{2}{π}) = - 4 - 5$

Step 6.4.2.2

Subtract $5$ from $- 4$ .

$f (\frac{3}{2} - \frac{2}{π}) = - 9$

Step 6.4.2.3

The final answer is $- 9$ .

$- 9$

Step 6.5

Find the point at $x = 2 - \frac{2}{π}$ .

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Step 6.5.1

Replace the variable $x$ with $2 - \frac{2}{π}$ in the expression.

$f (2 - \frac{2}{π}) = 4 \sin (π (2 - \frac{2}{π}) + 2) - 5$

Step 6.5.2

Simplify the result.

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Step 6.5.2.1

Simplify each term.

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Step 6.5.2.1.1

Simplify each term.

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Step 6.5.2.1.1.1

Apply the distributive property.

$f (2 - \frac{2}{π}) = 4 \sin (π \cdot 2 + π (- \frac{2}{π}) + 2) - 5$

Step 6.5.2.1.1.2

Move $2$ to the left of $π$ .

$f (2 - \frac{2}{π}) = 4 \sin (2 \cdot π + π (- \frac{2}{π}) + 2) - 5$

Step 6.5.2.1.1.3

Cancel the common factor of $π$ .

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Step 6.5.2.1.1.3.1

Move the leading negative in $- \frac{2}{π}$ into the numerator.

$f (2 - \frac{2}{π}) = 4 \sin (2 \cdot π + π (\frac{- 2}{π}) + 2) - 5$

Step 6.5.2.1.1.3.2

Cancel the common factor.

$f (2 - \frac{2}{π}) = 4 \sin (2 \cdot π + π (\frac{- 2}{π}) + 2) - 5$

Step 6.5.2.1.1.3.3

Rewrite the expression.

$f (2 - \frac{2}{π}) = 4 \sin (2 \cdot π - 2 + 2) - 5$

$f (2 - \frac{2}{π}) = 4 \sin (2 π - 2 + 2) - 5$

Step 6.5.2.1.2

Add $- 2$ and $2$ .

$f (2 - \frac{2}{π}) = 4 \sin (2 π + 0) - 5$

Step 6.5.2.1.3

Add $2 π$ and $0$ .

$f (2 - \frac{2}{π}) = 4 \sin (2 π) - 5$

Step 6.5.2.1.4

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$f (2 - \frac{2}{π}) = 4 \sin (0) - 5$

Step 6.5.2.1.5

The exact value of $\sin (0)$ is $0$ .

$f (2 - \frac{2}{π}) = 4 \cdot 0 - 5$

Step 6.5.2.1.6

Multiply $4$ by $0$ .

$f (2 - \frac{2}{π}) = 0 - 5$

Step 6.5.2.2

Subtract $5$ from $0$ .

$f (2 - \frac{2}{π}) = - 5$

Step 6.5.2.3

The final answer is $- 5$ .

$- 5$

Step 6.6

List the points in a table.

$\begin{array}{c} x & f (x) \\ - \frac{2}{π} & - 5 \\ \frac{1}{2} - \frac{2}{π} & - 1 \\ 1 - \frac{2}{π} & - 5 \\ \frac{3}{2} - \frac{2}{π} & - 9 \\ 2 - \frac{2}{π} & - 5 \end{array}$

Step 7

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude: $4$

Period: $2$

Phase Shift: $- \frac{2}{π}$ ( $\frac{2}{π}$ to the left)

Vertical Shift: $- 5$

$\begin{array}{c} x & f (x) \\ - \frac{2}{π} & - 5 \\ \frac{1}{2} - \frac{2}{π} & - 1 \\ 1 - \frac{2}{π} & - 5 \\ \frac{3}{2} - \frac{2}{π} & - 9 \\ 2 - \frac{2}{π} & - 5 \end{array}$

Step 8