Trigonometry Examples

$y = - 2 - \cot (x)$

Step 1

Find the asymptotes.

Tap for more steps...

Step 1.1

For any $y = \cot (x)$ , vertical asymptotes occur at $x = n π$ , where $n$ is an integer. Use the basic period for $y = \cot (x)$ , $(0, π)$ , to find the vertical asymptotes for $y = - 2 - \cot (x)$ . Set the inside of the cotangent function, $b x + c$ , for $y = a \cot (b x + c) + d$ equal to $0$ to find where the vertical asymptote occurs for $y = - 2 - \cot (x)$ .

$x = 0$

Step 1.2

Set the inside of the cotangent function $x$ equal to $π$ .

$x = π$

Step 1.3

The basic period for $y = - 2 - \cot (x)$ will occur at $(0, π)$ , where $0$ and $π$ are vertical asymptotes.

$(0, π)$

Step 1.4

Find the period $\frac{π}{| b |}$ to find where the vertical asymptotes exist.

Tap for more steps...

Step 1.4.1

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Step 1.4.2

Divide $π$ by $1$ .

$π$

Step 1.5

The vertical asymptotes for $y = - 2 - \cot (x)$ occur at $0$ , $π$ , and every $π n$ , where $n$ is an integer.

$π n$

Step 1.6

There are only vertical asymptotes for tangent and cotangent functions.

Vertical Asymptotes: $x = π n$ for any integer $n$

No Horizontal Asymptotes

No Oblique Asymptotes

Vertical Asymptotes: $x = π n$ for any integer $n$

No Horizontal Asymptotes

No Oblique Asymptotes

Step 2

Rewrite the expression as $- \cot (x) - 2$ .

$- \cot (x) - 2$

Step 3

Use the form $a \cot (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = - 1$

$b = 1$

$c = 0$

$d = - 2$

Step 4

Since the graph of the function $c o t$ does not have a maximum or minimum value, there can be no value for the amplitude.

Amplitude: None

Step 5

Find the period using the formula $\frac{π}{| b |}$ .

Tap for more steps...

Step 5.1

Find the period of $- \cot (x)$ .

Tap for more steps...

Step 5.1.1

The period of the function can be calculated using $\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Step 5.1.2

Replace $b$ with $1$ in the formula for period.

$\frac{π}{| 1 |}$

Step 5.1.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Step 5.1.4

Divide $π$ by $1$ .

$π$

Step 5.2

Find the period of $- 2$ .

Tap for more steps...

Step 5.2.1

The period of the function can be calculated using $\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Step 5.2.2

Replace $b$ with $1$ in the formula for period.

$\frac{π}{| 1 |}$

Step 5.2.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Step 5.2.4

Divide $π$ by $1$ .

$π$

Step 5.3

The period of addition/subtraction of trig functions is the maximum of the individual periods.

$π$

Step 6

Find the phase shift using the formula $\frac{c}{b}$ .

Tap for more steps...

Step 6.1

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Step 6.2

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{1}$

Step 6.3

Divide $0$ by $1$ .

Phase Shift: $0$

Step 7

List the properties of the trigonometric function.

Amplitude: None

Period: $π$

Phase Shift: None

Vertical Shift: $- 2$

Step 8

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Vertical Asymptotes: $x = π n$ for any integer $n$

Amplitude: None

Period: $π$

Phase Shift: None

Vertical Shift: $- 2$

Step 9