Trigonometry Examples

$y = \sin (x + 2 π)$

Step 1

Use the form $a \sin (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = 1$

$b = 1$

$c = - 2 π$

$d = 0$

Step 2

Find the amplitude $| a |$ .

Amplitude: $1$

Step 3

Find the period of $\sin (x + 2 π)$ .

Tap for more steps...

Step 3.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 3.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 3.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 3.4

Divide $2 π$ by $1$ .

$2 π$

Step 4

Find the phase shift using the formula $\frac{c}{b}$ .

Tap for more steps...

Step 4.1

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Step 4.2

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{- 2 π}{1}$

Step 4.3

Divide $- 2 π$ by $1$ .

Phase Shift: $- 2 π$

Step 5

List the properties of the trigonometric function.

Amplitude: $1$

Period: $2 π$

Phase Shift: $- 2 π$ ( $2 π$ to the left)

Vertical Shift: None

Step 6

Select a few points to graph.

Tap for more steps...

Step 6.1

Find the point at $x = - 2 π$ .

Tap for more steps...

Step 6.1.1

Replace the variable $x$ with $- 2 π$ in the expression.

$f (- 2 π) = \sin ((- 2 π) + 2 π)$

Step 6.1.2

Simplify the result.

Tap for more steps...

Step 6.1.2.1

Add $- 2 π$ and $2 π$ .

$f (- 2 π) = \sin (0)$

Step 6.1.2.2

The exact value of $\sin (0)$ is $0$ .

$f (- 2 π) = 0$

Step 6.1.2.3

The final answer is $0$ .

$0$

Step 6.2

Find the point at $x = - \frac{3 π}{2}$ .

Tap for more steps...

Step 6.2.1

Replace the variable $x$ with $- \frac{3 π}{2}$ in the expression.

$f (- \frac{3 π}{2}) = \sin ((- \frac{3 π}{2}) + 2 π)$

Step 6.2.2

Simplify the result.

Tap for more steps...

Step 6.2.2.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$f (- \frac{3 π}{2}) = \sin (- \frac{3 π}{2} + 2 π \cdot \frac{2}{2})$

Step 6.2.2.2

Combine fractions.

Tap for more steps...

Step 6.2.2.2.1

Combine $2 π$ and $\frac{2}{2}$ .

$f (- \frac{3 π}{2}) = \sin (- \frac{3 π}{2} + \frac{2 π \cdot 2}{2})$

Step 6.2.2.2.2

Combine the numerators over the common denominator.

$f (- \frac{3 π}{2}) = \sin (\frac{- 3 π + 2 π \cdot 2}{2})$

Step 6.2.2.3

Simplify the numerator.

Tap for more steps...

Step 6.2.2.3.1

Multiply $2$ by $2$ .

$f (- \frac{3 π}{2}) = \sin (\frac{- 3 π + 4 π}{2})$

Step 6.2.2.3.2

Add $- 3 π$ and $4 π$ .

$f (- \frac{3 π}{2}) = \sin (\frac{π}{2})$

Step 6.2.2.4

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (- \frac{3 π}{2}) = 1$

Step 6.2.2.5

The final answer is $1$ .

$1$

Step 6.3

Find the point at $x = - π$ .

Tap for more steps...

Step 6.3.1

Replace the variable $x$ with $- π$ in the expression.

$f (- π) = \sin ((- π) + 2 π)$

Step 6.3.2

Simplify the result.

Tap for more steps...

Step 6.3.2.1

Add $- π$ and $2 π$ .

$f (- π) = \sin (π)$

Step 6.3.2.2

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$f (- π) = \sin (0)$

Step 6.3.2.3

The exact value of $\sin (0)$ is $0$ .

$f (- π) = 0$

Step 6.3.2.4

The final answer is $0$ .

$0$

Step 6.4

Find the point at $x = - \frac{π}{2}$ .

Tap for more steps...

Step 6.4.1

Replace the variable $x$ with $- \frac{π}{2}$ in the expression.

$f (- \frac{π}{2}) = \sin ((- \frac{π}{2}) + 2 π)$

Step 6.4.2

Simplify the result.

Tap for more steps...

Step 6.4.2.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$f (- \frac{π}{2}) = \sin (- \frac{π}{2} + 2 π \cdot \frac{2}{2})$

Step 6.4.2.2

Combine fractions.

Tap for more steps...

Step 6.4.2.2.1

Combine $2 π$ and $\frac{2}{2}$ .

$f (- \frac{π}{2}) = \sin (- \frac{π}{2} + \frac{2 π \cdot 2}{2})$

Step 6.4.2.2.2

Combine the numerators over the common denominator.

$f (- \frac{π}{2}) = \sin (\frac{- π + 2 π \cdot 2}{2})$

Step 6.4.2.3

Simplify the numerator.

Tap for more steps...

Step 6.4.2.3.1

Multiply $2$ by $2$ .

$f (- \frac{π}{2}) = \sin (\frac{- π + 4 π}{2})$

Step 6.4.2.3.2

Add $- π$ and $4 π$ .

$f (- \frac{π}{2}) = \sin (\frac{3 π}{2})$

Step 6.4.2.4

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the fourth quadrant.

$f (- \frac{π}{2}) = - \sin (\frac{π}{2})$

Step 6.4.2.5

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (- \frac{π}{2}) = - 1 \cdot 1$

Step 6.4.2.6

Multiply $- 1$ by $1$ .

$f (- \frac{π}{2}) = - 1$

Step 6.4.2.7

The final answer is $- 1$ .

$- 1$

Step 6.5

Find the point at $x = 0$ .

Tap for more steps...

Step 6.5.1

Replace the variable $x$ with $0$ in the expression.

$f (0) = \sin ((0) + 2 π)$

Step 6.5.2

Simplify the result.

Tap for more steps...

Step 6.5.2.1

Add $0$ and $2 π$ .

$f (0) = \sin (2 π)$

Step 6.5.2.2

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$f (0) = \sin (0)$

Step 6.5.2.3

The exact value of $\sin (0)$ is $0$ .

$f (0) = 0$

Step 6.5.2.4

The final answer is $0$ .

$0$

Step 6.6

List the points in a table.

$\begin{array}{c} x & f (x) \\ - 2 π & 0 \\ - \frac{3 π}{2} & 1 \\ - π & 0 \\ - \frac{π}{2} & - 1 \\ 0 & 0 \end{array}$

Step 7

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude: $1$

Period: $2 π$

Phase Shift: $- 2 π$ ( $2 π$ to the left)

Vertical Shift: None

$\begin{array}{c} x & f (x) \\ - 2 π & 0 \\ - \frac{3 π}{2} & 1 \\ - π & 0 \\ - \frac{π}{2} & - 1 \\ 0 & 0 \end{array}$

Step 8