Trigonometry Examples

Graph f(x)=3 natural log of x
f(x)=3ln(x)
Step 1
Find the asymptotes.
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Step 1.1
Set the argument of the logarithm equal to zero.
x3=0
Step 1.2
Solve for x.
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Step 1.2.1
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
x=30
Step 1.2.2
Simplify 30.
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Step 1.2.2.1
Rewrite 0 as 03.
x=303
Step 1.2.2.2
Pull terms out from under the radical, assuming real numbers.
x=0
x=0
x=0
Step 1.3
The vertical asymptote occurs at x=0.
Vertical Asymptote: x=0
Vertical Asymptote: x=0
Step 2
Find the point at x=1.
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Step 2.1
Replace the variable x with 1 in the expression.
f(1)=3ln(1)
Step 2.2
Simplify the result.
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Step 2.2.1
The natural logarithm of 1 is 0.
f(1)=30
Step 2.2.2
Multiply 3 by 0.
f(1)=0
Step 2.2.3
The final answer is 0.
0
0
Step 2.3
Convert 0 to decimal.
y=0
y=0
Step 3
Find the point at x=2.
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Step 3.1
Replace the variable x with 2 in the expression.
f(2)=3ln(2)
Step 3.2
Simplify the result.
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Step 3.2.1
Simplify 3ln(2) by moving 3 inside the logarithm.
f(2)=ln(23)
Step 3.2.2
Raise 2 to the power of 3.
f(2)=ln(8)
Step 3.2.3
The final answer is ln(8).
ln(8)
ln(8)
Step 3.3
Convert ln(8) to decimal.
y=2.07944154
y=2.07944154
Step 4
Find the point at x=3.
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Step 4.1
Replace the variable x with 3 in the expression.
f(3)=3ln(3)
Step 4.2
Simplify the result.
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Step 4.2.1
Simplify 3ln(3) by moving 3 inside the logarithm.
f(3)=ln(33)
Step 4.2.2
Raise 3 to the power of 3.
f(3)=ln(27)
Step 4.2.3
The final answer is ln(27).
ln(27)
ln(27)
Step 4.3
Convert ln(27) to decimal.
y=3.29583686
y=3.29583686
Step 5
The log function can be graphed using the vertical asymptote at x=0 and the points (1,0),(2,2.07944154),(3,3.29583686).
Vertical Asymptote: x=0
xy1022.07933.296
Step 6
image of graph
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