Trigonometry Examples

$\sin (\frac{π}{12}) \cos (\frac{π}{12})$

Step 1

The exact value of $\sin (\frac{π}{12})$ is $\frac{\sqrt{6} - \sqrt{2}}{4}$ .

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Step 1.1

Split $\frac{π}{12}$ into two angles where the values of the six trigonometric functions are known.

$\sin (\frac{π}{4} - \frac{π}{6}) \cos (\frac{π}{12})$

Step 1.2

Apply the difference of angles identity.

$(\sin (\frac{π}{4}) \cos (\frac{π}{6}) - \cos (\frac{π}{4}) \sin (\frac{π}{6})) \cos (\frac{π}{12})$

Step 1.3

The exact value of $\sin (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$(\frac{\sqrt{2}}{2} \cos (\frac{π}{6}) - \cos (\frac{π}{4}) \sin (\frac{π}{6})) \cos (\frac{π}{12})$

Step 1.4

The exact value of $\cos (\frac{π}{6})$ is $\frac{\sqrt{3}}{2}$ .

$(\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \cos (\frac{π}{4}) \sin (\frac{π}{6})) \cos (\frac{π}{12})$

Step 1.5

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$(\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \sin (\frac{π}{6})) \cos (\frac{π}{12})$

Step 1.6

The exact value of $\sin (\frac{π}{6})$ is $\frac{1}{2}$ .

$(\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}) \cos (\frac{π}{12})$

Step 1.7

Simplify $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Step 1.7.1

Simplify each term.

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Step 1.7.1.1

Multiply $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}$ .

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Step 1.7.1.1.1

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{\sqrt{3}}{2}$ .

$(\frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}) \cos (\frac{π}{12})$

Step 1.7.1.1.2

Combine using the product rule for radicals.

$(\frac{\sqrt{2 \cdot 3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}) \cos (\frac{π}{12})$

Step 1.7.1.1.3

Multiply $2$ by $3$ .

$(\frac{\sqrt{6}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}) \cos (\frac{π}{12})$

Step 1.7.1.1.4

Multiply $2$ by $2$ .

$(\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}) \cos (\frac{π}{12})$

Step 1.7.1.2

Multiply $- \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Step 1.7.1.2.1

Multiply $\frac{1}{2}$ by $\frac{\sqrt{2}}{2}$ .

$(\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2 \cdot 2}) \cos (\frac{π}{12})$

Step 1.7.1.2.2

Multiply $2$ by $2$ .

$(\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4}) \cos (\frac{π}{12})$

Step 1.7.2

Combine the numerators over the common denominator.

$\frac{\sqrt{6} - \sqrt{2}}{4} \cos (\frac{π}{12})$

Step 2

The exact value of $\cos (\frac{π}{12})$ is $\frac{\sqrt{6} + \sqrt{2}}{4}$ .

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Step 2.1

Split $\frac{π}{12}$ into two angles where the values of the six trigonometric functions are known.

$\frac{\sqrt{6} - \sqrt{2}}{4} \cos (\frac{π}{4} - \frac{π}{6})$

Step 2.2

Apply the difference of angles identity $\cos (x - y) = \cos (x) \cos (y) + \sin (x) \sin (y)$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\cos (\frac{π}{4}) \cos (\frac{π}{6}) + \sin (\frac{π}{4}) \sin (\frac{π}{6}))$

Step 2.3

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{2}}{2} \cos (\frac{π}{6}) + \sin (\frac{π}{4}) \sin (\frac{π}{6}))$

Step 2.4

The exact value of $\cos (\frac{π}{6})$ is $\frac{\sqrt{3}}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \sin (\frac{π}{4}) \sin (\frac{π}{6}))$

Step 2.5

The exact value of $\sin (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \sin (\frac{π}{6}))$

Step 2.6

The exact value of $\sin (\frac{π}{6})$ is $\frac{1}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2})$

Step 2.7

Simplify $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Step 2.7.1

Simplify each term.

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Step 2.7.1.1

Multiply $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}$ .

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Step 2.7.1.1.1

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{\sqrt{3}}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2})$

Step 2.7.1.1.2

Combine using the product rule for radicals.

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{2 \cdot 3}}{2 \cdot 2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2})$

Step 2.7.1.1.3

Multiply $2$ by $3$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{6}}{2 \cdot 2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2})$

Step 2.7.1.1.4

Multiply $2$ by $2$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2})$

Step 2.7.1.2

Multiply $\frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Step 2.7.1.2.1

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{1}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2 \cdot 2})$

Step 2.7.1.2.2

Multiply $2$ by $2$ .

$\frac{\sqrt{6} - \sqrt{2}}{4} (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4})$

Step 2.7.2

Combine the numerators over the common denominator.

$\frac{\sqrt{6} - \sqrt{2}}{4} \cdot \frac{\sqrt{6} + \sqrt{2}}{4}$

Step 3

Multiply $\frac{\sqrt{6} - \sqrt{2}}{4} \cdot \frac{\sqrt{6} + \sqrt{2}}{4}$ .

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Step 3.1

Multiply $\frac{\sqrt{6} - \sqrt{2}}{4}$ by $\frac{\sqrt{6} + \sqrt{2}}{4}$ .

$\frac{(\sqrt{6} - \sqrt{2}) (\sqrt{6} + \sqrt{2})}{4 \cdot 4}$

Step 3.2

Multiply $4$ by $4$ .

$\frac{(\sqrt{6} - \sqrt{2}) (\sqrt{6} + \sqrt{2})}{16}$

Step 4

Simplify the numerator.

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Step 4.1

Expand $(\sqrt{6} - \sqrt{2}) (\sqrt{6} + \sqrt{2})$ using the FOIL Method.

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Step 4.1.1

Apply the distributive property.

$\frac{\sqrt{6} (\sqrt{6} + \sqrt{2}) - \sqrt{2} (\sqrt{6} + \sqrt{2})}{16}$

Step 4.1.2

Apply the distributive property.

$\frac{\sqrt{6} \sqrt{6} + \sqrt{6} \sqrt{2} - \sqrt{2} (\sqrt{6} + \sqrt{2})}{16}$

Step 4.1.3

Apply the distributive property.

$\frac{\sqrt{6} \sqrt{6} + \sqrt{6} \sqrt{2} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2

Simplify and combine like terms.

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Step 4.2.1

Simplify each term.

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Step 4.2.1.1

Combine using the product rule for radicals.

$\frac{\sqrt{6 \cdot 6} + \sqrt{6} \sqrt{2} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.2

Multiply $6$ by $6$ .

$\frac{\sqrt{36} + \sqrt{6} \sqrt{2} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.3

Rewrite $36$ as $6^{2}$ .

$\frac{\sqrt{6^{2}} + \sqrt{6} \sqrt{2} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.4

Pull terms out from under the radical, assuming positive real numbers.

$\frac{6 + \sqrt{6} \sqrt{2} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.5

Combine using the product rule for radicals.

$\frac{6 + \sqrt{6 \cdot 2} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.6

Multiply $6$ by $2$ .

$\frac{6 + \sqrt{12} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.7

Rewrite $12$ as $2^{2} \cdot 3$ .

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Step 4.2.1.7.1

Factor $4$ out of $12$ .

$\frac{6 + \sqrt{4 (3)} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.7.2

Rewrite $4$ as $2^{2}$ .

$\frac{6 + \sqrt{2^{2} \cdot 3} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.8

Pull terms out from under the radical.

$\frac{6 + 2 \sqrt{3} - \sqrt{2} \sqrt{6} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.9

Multiply $- \sqrt{2} \sqrt{6}$ .

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Step 4.2.1.9.1

Combine using the product rule for radicals.

$\frac{6 + 2 \sqrt{3} - \sqrt{6 \cdot 2} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.9.2

Multiply $6$ by $2$ .

$\frac{6 + 2 \sqrt{3} - \sqrt{12} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.10

Rewrite $12$ as $2^{2} \cdot 3$ .

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Step 4.2.1.10.1

Factor $4$ out of $12$ .

$\frac{6 + 2 \sqrt{3} - \sqrt{4 (3)} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.10.2

Rewrite $4$ as $2^{2}$ .

$\frac{6 + 2 \sqrt{3} - \sqrt{2^{2} \cdot 3} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.11

Pull terms out from under the radical.

$\frac{6 + 2 \sqrt{3} - (2 \sqrt{3}) - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.12

Multiply $2$ by $- 1$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - \sqrt{2} \sqrt{2}}{16}$

Step 4.2.1.13

Multiply $- \sqrt{2} \sqrt{2}$ .

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Step 4.2.1.13.1

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - ({\sqrt{2}}^{1} \sqrt{2})}{16}$

Step 4.2.1.13.2

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - ({\sqrt{2}}^{1} {\sqrt{2}}^{1})}{16}$

Step 4.2.1.13.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - {\sqrt{2}}^{1 + 1}}{16}$

Step 4.2.1.13.4

Add $1$ and $1$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - {\sqrt{2}}^{2}}{16}$

Step 4.2.1.14

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

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Step 4.2.1.14.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - {(2^{\frac{1}{2}})}^{2}}{16}$

Step 4.2.1.14.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - 2^{\frac{1}{2} \cdot 2}}{16}$

Step 4.2.1.14.3

Combine $\frac{1}{2}$ and $2$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - 2^{\frac{2}{2}}}{16}$

Step 4.2.1.14.4

Cancel the common factor of $2$ .

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Step 4.2.1.14.4.1

Cancel the common factor.

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - 2^{\frac{2}{2}}}{16}$

Step 4.2.1.14.4.2

Rewrite the expression.

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - 2^{1}}{16}$

Step 4.2.1.14.5

Evaluate the exponent.

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - 1 \cdot 2}{16}$

Step 4.2.1.15

Multiply $- 1$ by $2$ .

$\frac{6 + 2 \sqrt{3} - 2 \sqrt{3} - 2}{16}$

Step 4.2.2

Subtract $2$ from $6$ .

$\frac{4 + 2 \sqrt{3} - 2 \sqrt{3}}{16}$

Step 4.2.3

Subtract $2 \sqrt{3}$ from $2 \sqrt{3}$ .

$\frac{4 + 0}{16}$

Step 4.2.4

Add $4$ and $0$ .

$\frac{4}{16}$

Step 5

Cancel the common factor of $4$ and $16$ .

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Step 5.1

Factor $4$ out of $4$ .

$\frac{4 (1)}{16}$

Step 5.2

Cancel the common factors.

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Step 5.2.1

Factor $4$ out of $16$ .

$\frac{4 \cdot 1}{4 \cdot 4}$

Step 5.2.2

Cancel the common factor.

$\frac{4 \cdot 1}{4 \cdot 4}$

Step 5.2.3

Rewrite the expression.

$\frac{1}{4}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{4}$

Decimal Form:

$0.25$