Trigonometry Examples

$\frac{- 5 x + 10}{x - 4} > 0$

Step 1

Find all the values where the expression switches from negative to positive by setting each factor equal to $0$ and solving.

$- 5 x + 10 = 0$

$x - 4 = 0$

Step 2

Subtract $10$ from both sides of the equation.

$- 5 x = - 10$

Step 3

Divide each term in $- 5 x = - 10$ by $- 5$ and simplify.

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Step 3.1

Divide each term in $- 5 x = - 10$ by $- 5$ .

$\frac{- 5 x}{- 5} = \frac{- 10}{- 5}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $- 5$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{- 5 x}{- 5} = \frac{- 10}{- 5}$

Step 3.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 10}{- 5}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide $- 10$ by $- 5$ .

$x = 2$

Step 4

Add $4$ to both sides of the equation.

$x = 4$

Step 5

Solve for each factor to find the values where the absolute value expression goes from negative to positive.

$x = 2$

$x = 4$

Step 6

Consolidate the solutions.

$x = 2, 4$

Step 7

Find the domain of $\frac{- 5 x + 10}{x - 4}$ .

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Step 7.1

Set the denominator in $\frac{- 5 x + 10}{x - 4}$ equal to $0$ to find where the expression is undefined.

$x - 4 = 0$

Step 7.2

Add $4$ to both sides of the equation.

$x = 4$

Step 7.3

The domain is all values of $x$ that make the expression defined.

$(- \infty, 4) \cup (4, \infty)$

Step 8

Use each root to create test intervals.

$x < 2$

$2 < x < 4$

$x > 4$

Step 9

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

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Step 9.1

Test a value on the interval $x < 2$ to see if it makes the inequality true.

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Step 9.1.1

Choose a value on the interval $x < 2$ and see if this value makes the original inequality true.

$x = 0$

Step 9.1.2

Replace $x$ with $0$ in the original inequality.

$\frac{- 5 \cdot 0 + 10}{(0) - 4} > 0$

Step 9.1.3

The left side $- 2.5$ is not greater than the right side $0$ , which means that the given statement is false.

False

Step 9.2

Test a value on the interval $2 < x < 4$ to see if it makes the inequality true.

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Step 9.2.1

Choose a value on the interval $2 < x < 4$ and see if this value makes the original inequality true.

$x = 3$

Step 9.2.2

Replace $x$ with $3$ in the original inequality.

$\frac{- 5 \cdot 3 + 10}{(3) - 4} > 0$

Step 9.2.3

The left side $5$ is greater than the right side $0$ , which means that the given statement is always true.

True

Step 9.3

Test a value on the interval $x > 4$ to see if it makes the inequality true.

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Step 9.3.1

Choose a value on the interval $x > 4$ and see if this value makes the original inequality true.

$x = 6$

Step 9.3.2

Replace $x$ with $6$ in the original inequality.

$\frac{- 5 \cdot 6 + 10}{(6) - 4} > 0$

Step 9.3.3

The left side $- 10$ is not greater than the right side $0$ , which means that the given statement is false.

False

Step 9.4

Compare the intervals to determine which ones satisfy the original inequality.

$x < 2$ False

$2 < x < 4$ True

$x > 4$ False

$x < 2$ False

$2 < x < 4$ True

$x > 4$ False

Step 10

The solution consists of all of the true intervals.

$2 < x < 4$

Step 11

Convert the inequality to interval notation.

$(2, 4)$

Step 12