Trigonometry Examples

$\frac{\sin^{2} (x) + 2 \cos (x) - 1}{\sin^{2} (x) + 3 \cos (x) - 3} = \frac{1}{1 - \sec (x)}$

Step 1

The provided equation is an identity.

$\frac{\sin^{2} (x) + 2 \cos (x) - 1}{\sin^{2} (x) + 3 \cos (x) - 3} = \frac{1}{1 - \sec (x)}$ is an identity