Trigonometry Examples

$\sin (π - t) = \sin (t)$

Step 1

Start on the left side.

$\sin (π - t)$

Step 2

Apply the difference of angles identity.

$\sin (π) \cos (t) - \cos (π) \sin (t)$

Step 3

Simplify the expression.

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Step 3.1

Simplify each term.

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Step 3.1.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$\sin (0) \cos (t) - \cos (π) \sin (t)$

Step 3.1.2

The exact value of $\sin (0)$ is $0$ .

$0 \cos (t) - \cos (π) \sin (t)$

Step 3.1.3

Multiply $0$ by $\cos (t)$ .

$0 - \cos (π) \sin (t)$

Step 3.1.4

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.

$0 - - \cos (0) \sin (t)$

Step 3.1.5

The exact value of $\cos (0)$ is $1$ .

$0 - (- 1 \cdot 1) \sin (t)$

Step 3.1.6

Multiply $- (- 1 \cdot 1)$ .

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Step 3.1.6.1

Multiply $- 1$ by $1$ .

$0 - - 1 \sin (t)$

Step 3.1.6.2

Multiply $- 1$ by $- 1$ .

$0 + 1 \sin (t)$

Step 3.1.7

Multiply $\sin (t)$ by $1$ .

$0 + \sin (t)$

Step 3.2

Add $0$ and $\sin (t)$ .

$\sin (t)$

Step 4

Because the two sides have been shown to be equivalent, the equation is an identity.

$\sin (π - t) = \sin (t)$ is an identity