Trigonometry Examples

$\sin (x) + \cos (x) \cdot \cot (x) = \csc (x)$

Step 1

Start on the left side.

$\sin (x) + \cos (x) \cdot \cot (x)$

Step 2

Simplify each term.

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Step 2.1

Rewrite $\cot (x)$ in terms of sines and cosines.

$\sin (x) + \frac{\cos (x) \cos (x)}{\sin (x)}$

Step 2.2

Multiply $\cos (x) \frac{\cos (x)}{\sin (x)}$ .

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Step 2.2.1

Raise $\cos (x)$ to the power of $1$ .

$\sin (x) + \frac{\cos^{1} (x) \cos (x)}{\sin (x)}$

Step 2.2.2

Raise $\cos (x)$ to the power of $1$ .

$\sin (x) + \frac{\cos^{1} (x) \cos^{1} (x)}{\sin (x)}$

Step 2.2.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sin (x) + \frac{{\cos (x)}^{1 + 1}}{\sin (x)}$

Step 2.2.4

Add $1$ and $1$ .

$\sin (x) + \frac{\cos^{2} (x)}{\sin (x)}$

Step 3

Apply Pythagorean identity in reverse.

$\sin (x) + \frac{1 - \sin^{2} (x)}{\sin (x)}$

Step 4

Simplify.

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Step 4.1

Simplify the numerator.

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Step 4.1.1

Rewrite $1$ as $1^{2}$ .

$\sin (x) + \frac{1^{2} - {\sin (x)}^{2}}{\sin (x)}$

Step 4.1.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = \sin (x)$ .

$\sin (x) + \frac{(1 + \sin (x)) (1 - \sin (x))}{\sin (x)}$

Step 4.2

To write $\sin (x)$ as a fraction with a common denominator, multiply by $\frac{\sin (x)}{\sin (x)}$ .

$\frac{\sin (x) \sin (x)}{\sin (x)} + \frac{(1 + \sin (x)) (1 - \sin (x))}{\sin (x)}$

Step 4.3

Combine the numerators over the common denominator.

$\frac{\sin (x) \sin (x) + (1 + \sin (x)) (1 - \sin (x))}{\sin (x)}$

Step 4.4

Simplify the numerator.

$\frac{1}{\sin (x)}$

Step 5

Rewrite $\frac{1}{\sin (x)}$ as $\csc (x)$ .

$\csc (x)$

Step 6

Because the two sides have been shown to be equivalent, the equation is an identity.

$\sin (x) + \cos (x) \cdot \cot (x) = \csc (x)$ is an identity