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Trigonometry Examples
24(1-arccos(tan(0)tan(21.3))π)24(1−arccos(tan(0)tan(21.3))π)
Step 1
Step 1.1
Simplify the numerator.
Step 1.1.1
The exact value of tan(0)tan(0) is 00.
24(1-arccos(0tan(21.3))π)24(1−arccos(0tan(21.3))π)
Step 1.1.2
Multiply 00 by tan(21.3)tan(21.3).
24(1-arccos(0)π)24(1−arccos(0)π)
Step 1.1.3
The exact value of arccos(0)arccos(0) is π2π2.
24(1-π2π)24(1−π2π)
24(1-π2π)24(1−π2π)
Step 1.2
Multiply the numerator by the reciprocal of the denominator.
24(1-(π2⋅1π))24(1−(π2⋅1π))
Step 1.3
Cancel the common factor of ππ.
Step 1.3.1
Cancel the common factor.
24(1-(π2⋅1π))
Step 1.3.2
Rewrite the expression.
24(1-12)
24(1-12)
24(1-12)
Step 2
Step 2.1
Write 1 as a fraction with a common denominator.
24(22-12)
Step 2.2
Simplify the expression.
Step 2.2.1
Combine the numerators over the common denominator.
242-12
Step 2.2.2
Subtract 1 from 2.
24(12)
24(12)
Step 2.3
Cancel the common factor of 2.
Step 2.3.1
Factor 2 out of 24.
2(12)12
Step 2.3.2
Cancel the common factor.
2⋅1212
Step 2.3.3
Rewrite the expression.
12
12
12